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Solve each equation and solve for \(x\) in terms of the other letters. $$\beta=10 \log _{10}\left(x / x_{0}\right)$$

Short Answer

Expert verified
\( x = x_0 \cdot 10^{\frac{\beta}{10}} \)

Step by step solution

01

Isolate the logarithmic expression

Starting with the equation \( \beta = 10 \log_{10}\left(\frac{x}{x_0}\right) \), divide both sides by 10 to isolate the logarithm: \( \frac{\beta}{10} = \log_{10}\left(\frac{x}{x_0}\right) \).
02

Eliminate the logarithm using exponentiation

To solve for \(x\), eliminate the logarithm by taking the base 10 raise of both sides: \( 10^{\frac{\beta}{10}} = \left(\frac{x}{x_0}\right) \).
03

Solve for x

Multiply both sides of the equation by \( x_0 \) to isolate \( x \): \( x = x_0 \cdot 10^{\frac{\beta}{10}} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Functions
Exponential functions are mathematical expressions where variables appear as an exponent. These functions are of the form \( y = a^x \), where \(a\) is a constant known as the base and \(x\) is the exponent. They are crucial in many scientific fields because they can model growth and decay processes effectively, such as population growth or radioactive decay.
Understanding how to manipulate exponential expressions is essential in solving equations involving them. When dealing with a function like \( 10^{\frac{\beta}{10}} \), the number 10 is the base, and \( \frac{\beta}{10} \) is the exponent.
Exponential functions have unique properties such as rapid growth, meaning small changes in the exponent can lead to large changes in the function value. Because of these properties, they are frequently used to convert logarithmic equations, turning a problem of finding exponents into a problem of handling powers. This makes them incredibly useful in fields like finance, biology, and physics.
Isolation of Variables
Isolation of variables is a key technique in algebra that simplifies the process of solving equations. The core idea is to manipulate the equation to express one variable in terms of others, making it easier to find its value. This often involves using inverse operations to eliminate operations attached to the variable.
For example, take the equation \( \beta = 10 \log_{10}\left(\frac{x}{x_0}\right) \). Our first step is to isolate the logarithmic expression by dividing both sides by 10, resulting in \( \frac{\beta}{10} = \log_{10}\left(\frac{x}{x_0}\right) \).
Through isolation, we can see clearer pathways to solutions, like transforming a complex expression into a more manageable form. This technique is not just limited to logarithmic equations but is widely applicable across various mathematical situations, making it a vital tool in problem-solving.
Logarithmic Properties
Logarithmic properties are rules that apply to logarithms, making it easier to work with them. Logarithms are the inverse operation of exponentiation and follow unique rules, such as the product, quotient, and power rules.
  • The **product rule** states that \( \log_b(MN) = \log_b(M) + \log_b(N) \).
  • The **quotient rule** is \( \log_b\left(\frac{M}{N}\right) = \log_b(M) - \log_b(N) \).
  • The **power rule** asserts \( \log_b(M^p) = p \cdot \log_b(M) \).
In our equation \( \beta = 10 \log_{10}\left(\frac{x}{x_0}\right) \), we use the process of eliminating the logarithm through exponentiation. By raising 10 to the power of both sides, we transform the equation into \( 10^{\frac{\beta}{10}} = \left(\frac{x}{x_0}\right) \), effectively removing the log function.
Understanding these properties enables students to simplify and solve equations that contain logarithms confidently. It lays a foundation for advanced manipulations and applications in calculus and other higher-level math topics.

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Most popular questions from this chapter

Exercises \(55-60\) introduce a model for population growth that takes into account limitations on food and the environment. This is the logistic growth model, named and studied by the nineteenth century Belgian mathematician and sociologist Pierre Verhulst. (The word "logistic" has Latin and Greek origins meaning "calculation" and "skilled in calculation," respectively. However, that is not why Verhulst named the curve as he did. See Exercise 56 for more about this.) In the logistic model that we "I study, the initial population growth resembles exponential growth. But then, at some point owing perhaps to food or space limitations, the growth slows down and eventually levels off, and the population approaches an equilibrium level. The basic equation that we'll use for logis- tic growth is where \(\mathcal{N}\) is the population at time \(t, P\) is the equilibrium population (or the upper limit for population), and a and b are positive constants. $$\mathcal{N}=\frac{P}{1+a e^{-b t}}$$ (Continuation of Exercise 55 ) The author's ideas for this exercise are based on Professor Bonnie Shulman's article "Math-Alive! Using Original Sources to Teach Mathematics in Social Context," Primus, vol. VIII (March \(1998)\) (a) The function \(\mathcal{N}\) in Exercise 55 expresses population as a function of time. But as pointed out by Professor Shulman, in Verhulst's original work it was the other way around; he expressed time as a function of population. In terms of our notation, we would say that he was studying the function \(\mathcal{N}^{-1}\). Given \(\mathcal{N}(t)=4 /\left(1+8 e^{-t}\right)\) find \(\mathcal{N}^{-1}(t)\) (b) Use a graphing utility to draw the graphs of \(\mathcal{N}, \mathcal{N}^{-1}\), and the line \(y=x\) in the viewing rectangle [-3,8,2] by \([-3,8,2] .\) Use true portions. (Why?) (c) In the viewing rectangle [0,5,1] by \([-3,2,1],\) draw the graphs of \(y=\mathcal{N}^{-1}(t)\) and \(y=\ln t .\) Note that the two graphs have the same general shape and characteristics. In other words, Verhulst's logistic function (our \(\mathcal{N}^{-1}\) ) appears log-like, or logistique, as Verhulst actually named it in French. (For details, both historical and mathematical, see the paper by Professor Shulman cited above.)

Solve the inequalities. Where appropriate, give an exact answer as well as a decimal approximation. $$4\left(10-e^{x}\right) \leq-3$$

Solve for \(x\) (assuming that \(a>b>0\) ): $$\begin{aligned} \left(a^{4}-2 a^{2} b^{2}+b^{4}\right)^{x-1}=(a-b)^{2 x}(a+b)^{-2} & \\ \text {Answer:} & x=\frac{\ln (a-b)}{\ln (a+b)} \end{aligned}$$

In 2000 the Philippines and Germany had similar size populations, but very different growth rates. The population of the Philippines was 80.3 million, with a relative growth rate of \(2.0 \%\) /year. The population of Germany was 82.1 million, with a relative "growth" rate of \(-0.1 \% /\) year. Using exponential models, make a projection for the population of Germany in the year when the Philippine population has doubled.

The half-life of strontium- 90 is 28 years. How much of a \(10-\mathrm{g}\) sample will remain after (a) 1 year? (b) 10 years?

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