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Answer True or False. You do not need a calculator for these exercises. Rather, use the fact that e is approximately 2.7 $$e^{0}=1$$

Short Answer

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True

Step by step solution

01

Understanding the Exponential Function

The exponential function is a mathematical function denoted as \( e^{x} \), where \( e \) is the base of the natural logarithm, approximately 2.7, and \( x \) is the exponent. A key property of exponential functions is that any non-zero number raised to the power of 0 is always 1.
02

Applying the Property

Using the property of exponents, any number, including \( e \), raised to the power of 0 will result in 1. Therefore, \( e^{0} = 1 \).
03

Conclusion

Based on the property of exponents that any number raised to the power of 0 equals 1, we determine that the statement \( e^{0} = 1 \) is True.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Properties of Exponents
When dealing with exponential functions, it's crucial to understand the properties of exponents. Exponents are mathematical expressions that represent repeated multiplication. For example, \( e^2 \) means \( e \times e \). One of the vital rules in the properties of exponents is that any non-zero number raised to the power of zero equals one, or mathematically, \( a^0 = 1 \). This property is especially useful when simplifying expressions and solving equations. It applies universally to all non-zero numbers, including irrational numbers like \( e \), which is the base of natural logarithms. By understanding this property, you can easily evaluate expressions such as \( e^0 \) without needing a calculator.These properties simplify exponential expressions, allowing us to handle complex equations efficiently and streamline mathematical problem-solving.
Natural Logarithm
The natural logarithm is an essential concept in mathematics, denoted as \( \ln(x) \). This type of logarithm uses the number \( e \), approximately 2.7, as its base. Understanding the natural logarithm helps decipher functions involving exponential growth or decay. The natural logarithm has several convenient attributes:
  • It is the inverse of the exponential function \( e^x \).
  • This means that if \( y = e^x \), then \( \ln(y) = x \).
  • It provides a simplified way to solve equations involving \( e \).
As a result, recognizing the relationship between \( e \) and \( \ln \) enables you to manipulate and solve logarithmic and exponential equations with ease. This is particularly effective in calculus and higher-level mathematics.
Mathematical Functions
Mathematical functions are expressions or rules that relate inputs to outputs. They are fundamental in nearly all areas of mathematics. A function takes an input, performs certain operations on this input, and transforms it into an output. Common types include linear, quadratic, and exponential functions like the one we examined with \( e^x \).Exponential functions, in particular, have the form \( f(x) = a \cdot e^{bx} \), where:
  • \( a \) is a constant and adjusts the function's overall growth.
  • \( b \) influences the rate of growth or decay.
These functions model many real-world processes such as population growth, radioactive decay, and continuously compounded interest. Understanding them helps in representing and predicting behavior in various scientific, financial, and engineering contexts.

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Most popular questions from this chapter

Solve each equation and solve for \(x\) in terms of the other letters. $$3 \ln x=\alpha+3 \ln \beta$$

A function \(f\) with domain \((1, \infty)\) is defined by the equation \(f(x)=\log _{x} 2\) (a) Find a value for \(x\) such that \(f(x)=2\) (b) Is the number that you found in part (a) a fixed point of the function \(f ?\)

Solve the inequalities. Where appropriate, give an exact answer as well as a decimal approximation. $$e^{x^{2}-4 x} \geq e^{5}$$

Exercises \(55-60\) introduce a model for population growth that takes into account limitations on food and the environment. This is the logistic growth model, named and studied by the nineteenth century Belgian mathematician and sociologist Pierre Verhulst. (The word "logistic" has Latin and Greek origins meaning "calculation" and "skilled in calculation," respectively. However, that is not why Verhulst named the curve as he did. See Exercise 56 for more about this.) In the logistic model that we "I study, the initial population growth resembles exponential growth. But then, at some point owing perhaps to food or space limitations, the growth slows down and eventually levels off, and the population approaches an equilibrium level. The basic equation that we'll use for logis- tic growth is where \(\mathcal{N}\) is the population at time \(t, P\) is the equilibrium population (or the upper limit for population), and a and b are positive constants. $$\mathcal{N}=\frac{P}{1+a e^{-b t}}$$ (Continuation of Exercise 55 ) The author's ideas for this exercise are based on Professor Bonnie Shulman's article "Math-Alive! Using Original Sources to Teach Mathematics in Social Context," Primus, vol. VIII (March \(1998)\) (a) The function \(\mathcal{N}\) in Exercise 55 expresses population as a function of time. But as pointed out by Professor Shulman, in Verhulst's original work it was the other way around; he expressed time as a function of population. In terms of our notation, we would say that he was studying the function \(\mathcal{N}^{-1}\). Given \(\mathcal{N}(t)=4 /\left(1+8 e^{-t}\right)\) find \(\mathcal{N}^{-1}(t)\) (b) Use a graphing utility to draw the graphs of \(\mathcal{N}, \mathcal{N}^{-1}\), and the line \(y=x\) in the viewing rectangle [-3,8,2] by \([-3,8,2] .\) Use true portions. (Why?) (c) In the viewing rectangle [0,5,1] by \([-3,2,1],\) draw the graphs of \(y=\mathcal{N}^{-1}(t)\) and \(y=\ln t .\) Note that the two graphs have the same general shape and characteristics. In other words, Verhulst's logistic function (our \(\mathcal{N}^{-1}\) ) appears log-like, or logistique, as Verhulst actually named it in French. (For details, both historical and mathematical, see the paper by Professor Shulman cited above.)

Solve each equation. $$x^{1+\log _{x} 16}=4 x^{2}$$

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