/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 True or false? (a) \(\log _{10... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

True or false? (a) \(\log _{10} A+\log _{10} B-\frac{1}{2} \log _{10} C=\log _{10}(A B / \sqrt{C})\) (b) \(\log _{e} \sqrt{e}=1 / 2\) (c) \(\ln \sqrt{e}=1 / 2\) (d) \(\ln x^{3}=\ln 3 x\) (e) \(\ln x^{3}=3 \ln x\) (f) \(\ln 2 x^{3}=3 \ln 2 x\) (g) \(\log _{a} c=b\) means \(a^{b}=c\) (h) \(\log _{5} 24\) is between \(5^{1}\) and \(5^{2}\) (i) \(\log _{5} 24\) is between 1 and 2 (j) \(\log _{5} 24\) is closer to 1 than to 2 (k) The domain of \(g(x)=\ln x\) is the set of all real numbers. (1) The range of \(g(x)=\ln x\) is the set of all real numbers. (m) The function \(g(x)=\ln x\) is one-to-one.

Short Answer

Expert verified
(a) True, (b) True, (c) True, (d) False, (e) True, (f) False, (g) True, (h) True, (i) True, (j) True, (k) False, (1) True, (m) True.

Step by step solution

01

Simplify Part (a)

Use properties of logarithms. The expression \( \log_{10} A + \log_{10} B - \frac{1}{2} \log_{10} C \) simplifies to \( \log_{10}(AB) - \log_{10}(C^{1/2}) \) using \( \log_{b}(mn) = \log_{b} m + \log_{b} n \) and \( \log_{b}(m^n) = n\log_{b} m \). This gives \( \log_{10}\frac{AB}{\sqrt{C}} \). Therefore, part (a) is True.
02

Solve Part (b) using Logarithm Identity

Since \( \log_{e}(e) = 1 \), \( \log_{e}(\sqrt{e}) = \log_{e}(e^{1/2}) = \frac{1}{2}\log_{e}(e) = \frac{1}{2} \). Therefore, part (b) is True.
03

Analyze Part (c)

\( \ln x = \log_{e} x \), so \( \ln \sqrt{e} = \ln e^{1/2} = \frac{1}{2}\ln e = \frac{1}{2} \times 1 = \frac{1}{2} \). Therefore, part (c) is True.
04

Evaluate Part (d) using Logarithm Properties

\( \ln x^{3} = 3\ln x \), which is not equal to \( \ln 3x = \ln 3 + \ln x \). Therefore, part (d) is False.
05

Simplify Part (e)

Using the property \( \ln x^{n} = n\ln x \), the expression simplifies to \( 3\ln x \). So part (e) is True.
06

Check Part (f)

\( \ln 2x^{3} = \ln 2 + \ln x^{3} = \ln 2 + 3\ln x \), and \( 3\ln 2x = 3(\ln 2 + \ln x) = 3\ln 2 + 3\ln x \). Therefore, part (f) is False.
07

Interpret Part (g) using Definition of Logarithm

By definition, \( \log_{a} c = b \) implies \( a^{b} = c \). Therefore, part (g) is True.
08

Evaluate Part (h) through Estimations

Check if \( 5^1 \leq 24 < 5^2 \). Since \( 5^1 = 5 \) and \( 5^2 = 25 \), \( 5 < 24 < 25 \) holds true. Therefore, part (h) is True.
09

Verify Part (i) using Evaluation from Step 8

Since \( 5 < 24 < 25 \) from Step 8, \( \log_{5} 24 \) is indeed between 1 and 2. Therefore, part (i) is True.
10

Compare Distances for Part (j)

Calculate \( \log_{5} 24 \) using estimations: \( 5^{1.4} \approx 24.3 \). Since 1.4 is closer to 1.0 than 2.0, part (j) is True.
11

Analyze Part (k) for Domain

The function \( g(x) = \ln x \) is defined for \( x > 0 \). Therefore, the domain is not all real numbers. Part (k) is False.
12

Determine the Range for Part (1)

\( g(x) = \ln x \) can take any real number as its range since \( \ln(x) \) can output negative and positive numbers. Therefore, the range is all real numbers. Part (1) is True.
13

Examine if Part (m) is One-to-One

The function \( g(x) = \ln x \) has exactly one y-value for each x-value when \( x > 0 \), thus making it a one-to-one function. Therefore, part (m) is True.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Properties of Logarithms
Understanding logarithms begins with learning their primary properties, which make many mathematical operations easier. One key property is the product rule, which states that the log of a product is the sum of the logs:
  • \( \ \log_{b}(mn) = \log_{b} m + \log_{b} n \)
The quotient rule tells us that the log of a quotient is the difference of the logs:
  • \( \log_{b}\left(\frac{m}{n}\right) = \log_{b} m - \log_{b} n\)
Another essential property is the power rule, which simplifies logs of powers:
  • \( \log_{b}(m^{n}) = n \log_{b} m \)
These properties help in simplifying complex logarithmic expressions and equations. For instance, in the problem, the expression \(\log_{10} A + \log_{10} B - \frac{1}{2} \log_{10} C\) is simplified using these rules to \(\log_{10}(AB/\sqrt{C})\). By mastering these properties, students can efficiently tackle logarithmic problems.
Natural Logarithm
The natural logarithm, denoted as \(\ln\), is a specific logarithm where the base is the mathematical constant \(e\), approximately 2.718. It's extensively used in calculus and advanced mathematics. The natural logarithm follows all the standard properties of logarithms, with special attention to its base:
  • When \( \ln e = 1\), it's because \(e^{1} = e\).
Thus, when solving exercises like \(\ln \sqrt{e}\), you recognize it as \(\ln e^{1/2}\), which simplifies to \(\frac{1}{2} \ln e = \frac{1}{2}\). Recognizing how the natural logarithm behaves under different mathematical manipulations, like in the step-by-step solution, enhances comprehension of their versatility in mathematical and real-world applications.
Functional Properties
Logarithmic functions, including the natural logarithm \(g(x) = \ln x\), have specific properties that define their behavior. One of the primary functional properties is that the domain of \(\ln x\) consists strictly of positive real numbers, meaning \(x > 0\).
  • This restriction arises because you cannot take the logarithm of a non-positive number.
Next, consider the range of \(\ln x\), which spans all real numbers. A logarithmic function can output a value less than zero (negative) or greater than zero (positive) depending on the input.
  • For example, \(\ln 0.5\) yields a negative result, while \(\ln 2\) is positive.
Additionally, \(\ln x\) is a one-to-one function, implying that each \(x > 0\) corresponds to exactly one unique \(y\). This characteristic makes it valuable for finding inverse functions. Understanding these functional properties is crucial for correctly handling logarithmic functions in different contexts.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An article that appeared in the August \(13,1994,\) New York Times reported German authorities have discovered.... a tiny sample of weapons-grade nuclear material believed to have been smuggled out of Russia to interest foreign governments or terrorist groups that might want to build atomic bombs..... [the police] said they had seized the material, .028 ounces of highly enriched uranium- 235 in June in ... Bavaria ... and have since arrested... \([\text { six }]\) suspects. \(\ldots\) Suppose that the suspects, in an attempt to avoid arrest, had thrown the 0.028 ounces of uranium- 235 into the Danube River, where it would sink to the bottom. How many ounces of the uranium-235 would still be in the river after 1000 years? The half-life of uranium- 235 is \(7.1 \times 10^{8}\) years.

If \(a^{2}+b^{2}=7 a b,\) where \(a\) and \(b\) are positive, show that $$\log \left[\frac{1}{3}(a+b)\right]=\frac{1}{2}(\log a+\log b)$$ no matter which base is used for the logarithms (but it understood that the same base is used throughout).

(a) Use a graphing utility to estimate the root(s) of the equation to the nearest one-tenth (as in Example 6). (b) Solve the given equation algebraically by first rewriting it in logarithmic form. Give two forms for each answer: an exact expression and a calculator approximation rounded to three decimal places. Check to see that each result is consistent with the graphical estimate obtained in part (a). $$e^{2 t+3}=10$$

(a) Suppose that a certain country violates the ban against above-ground nuclear testing and, as a result, an island is contaminated with debris containing the radioactive substance iodine-131. A team of scientists from the United Nations wants to visit the island to look for clues in determining which country was involved. However, the level of radioactivity from the iodine- 131 is estimated to be 30,000 times the safe level. Approximately how long must the team wait before it is safe to visit the island? The half-life of iodine- 131 is 8 days. (b) Rework part (a), assuming instead that the radioactive substance is strontium-90 rather than iodine-131. The half-life of strontium- 90 is 28 years. Assume, as before, that the initial level of radioactivity is 30,000 times the safe level. (This exercise underscores the difference between a half-life of 8 days and one of 28 years.)

The intensity of the sounds that the human ear can detect varies over a very wide range of values. For instance, a whisper from 1 meter away has an intensity of approximately \(10^{-10}\) watts per square meter \(\left(\mathrm{W} / \mathrm{m}^{2}\right)\), whereas, from a distance of 50 meters, the intensity of a launch of the Space Shuttle is approximately \(10^{8} \mathrm{W} / \mathrm{m}^{2} .\) For a sound with intensity \(I\), the sound level \(\beta\) is defined by $$ \beta=10 \log _{10}\left(I / I_{0}\right) $$ where the constant \(I_{0}\) is the sound intensity of a barely audible sound at the threshold of hearing. The units for the sound level \(\beta\) are decibels, abbreviated dB. (a) Solve the equation \(\beta=10 \log _{10}\left(1 / I_{0}\right)\) for \(I\) by first dividing by 10 and then converting to exponential form. (b) The sound level for a power lawnmower is \(\beta=100 \mathrm{db}\). and that for a cat purring is \(\beta=10\) db. Use your result in part (a) to determine how many times more intense is the power mower sound than the cat's purring.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.