/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 Decide which of the following pr... [FREE SOLUTION] | 91Ó°ÊÓ

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Decide which of the following properties apply to each function. (More than one property may apply to a function.)A. The function is increasing for \(-\infty

Short Answer

Expert verified
The correct properties are A, D, E, G, and H.

Step by step solution

01

Identify the Function Type

The function given is \(y = \ln x\). This is a logarithmic function.
02

Determine the Domain

The natural logarithmic function \(y = \ln x\) is defined for \(x > 0\). Therefore, the domain of this function is \((0, \infty)\).
03

Determine the Range

The range of \(y = \ln x\) is all real numbers, or \((-fty, fty)\). This is because as \(x\) approaches infinity, \(y\) also approaches infinity, and as \(x\) approaches 0 from the right, \(y\) approaches negative infinity.
04

Analyze Increasing or Decreasing Behavior

The derivative of \(y = \ln x\) is \(\frac{d}{dx}(\ln x) = \frac{1}{x}\), which is positive for \(x > 0\). Hence, the function is increasing for its entire domain \((0, \infty)\).
05

Check for Turning Points

A turning point occurs where the derivative equals zero. Since \(\frac{1}{x} > 0\) for all \(x > 0\), there are no points where the derivative equals zero, indicating no turning points for \(y = \ln x\).
06

Confirm If One-to-One

A function is one-to-one if it is strictly increasing or decreasing. Since \(y = \ln x\) is increasing for \(x > 0\), it is one-to-one.
07

Check for Asymptotes

There is a vertical asymptote at \(x = 0\) because as \(x\) approaches 0 from the right, \(y = \ln x\) approaches \(-\infty\).
08

Determine If Polynomial

The function \(y = \ln x\) is not a polynomial function since it involves a logarithm rather than powers of \(x\).
09

Conclusion

The properties that apply to \(y = \ln x\) are as follows: it is increasing for \(-\infty<x<\infty\) (within its domain, actually this is \((0, \infty)\)), one-to-one, has a vertical asymptote, has a range of \((-fty, fty)\), and is not a polynomial. The domain of the function is \((0, \infty)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Domain
The domain of a function refers to all the possible input values (usually represented by the variable \(x\)) for which the function is defined. For a logarithmic function like \(y = \ln x\), the domain is only positive real numbers. This is because you cannot take the logarithm of zero or a negative number in real number mathematics. Therefore, the domain of \(\ln x\) is \((0, \infty)\). So if you're asked about the domain, just remember: only values greater than zero are suitable for \(x\) in \(\ln x\).
Understanding the domain is crucial because it tells you the range of the \(x\)-values you can plug into a function without running into any undefined scenarios. So whenever you're working with logarithmic functions, keep an eye on the domain restrictions!
Function Range
The range of a function is the set of all possible output values (usually represented by the variable \(y\)). For the natural logarithm function \(y = \ln x\), the range is all real numbers, or \((-\infty, \infty)\). This means that when you input valid \(x\)-values into the function, you can get any real number as an output.
This wide range happens because as \(x\) approaches zero from the right, \(y\) becomes very large and negative, and as \(x\) increases towards infinity, \(y\) becomes very large and positive. So, whatever number or goal you're aiming to reach with \(y\), you can get there using some \(x\) in the domain of the function!
Increasing Functions
An increasing function means that as \(x\) gets larger, \(y\) also gets larger. Specifically, for \(y = \ln x\), this behavior is present throughout its entire domain \((0, \infty)\). This is confirmed by exploring its derivative: the derivative \(\frac{d}{dx}(\ln x) = \frac{1}{x}\) is positive for all \(x > 0\).
In plain terms, for every step to the right on the \(x\)-axis, the function's output or value of \(y\) steps up. This characteristic makes the logarithmic function smooth and ever-increasing, without taking any dips or turns, as long as \(x\) is within its domain of positive numbers.
One-to-One Functions
A function is considered "one-to-one" if it doesn't assign the same \(y\)-value to more than one \(x\)-value. This means each input directly maps to a unique output, and vice versa.
For \(y = \ln x\), the function is one-to-one because it is continuously increasing and never repeats a \(y\)-value. This property is key in many mathematical applications because it implies that the function has an inverse function, meaning it can be "reversed" to find the original \(x\) when given a \(y\).
To sum up, the natural logarithmic function \(\ln x\) perfectly exemplifies a one-to-one function. The key takeaway here is that no two different \(x\)-values yield the same \(y\)-value, ensuring a direct correlation between input and output.
Vertical Asymptotes
Vertical asymptotes occur in a graph when the function approaches a specific \(x\)-value but never actually reaches it. For \(y = \ln x\), there's a vertical asymptote at \(x = 0\). This happens because as \(x\) approaches zero from the right-hand side, the value of \(y\) drops towards negative infinity.
It's important to remember that the function doesn't touch or cross this vertical line at \(x = 0\), making it a boundary. Asymptotes are crucial because they indicate where a function behaves differently or becomes undefined. They vividly illustrate the behavior of \(y = \ln x\) as it gets extremely negative near \(x = 0\). These insights help us understand and predict how the function behaves near its boundary limits.

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Most popular questions from this chapter

Radiocarbon Dating: Because rubidium-87 decays so slowly, the technique of rubidium-strontium dating is generally considered effective only for objects older than 10 million years. In contrast, archeologists and geologists rely on the radiocarbon dating method in assigning ages ranging from 500 to 50,000 years. Two types of carbon occur naturally in our environment: carbon-12, which is nonradioactive, and carbon-14, which has a half-life of 5730 years. All living plant and animal tissue contains both types of carbon, always in the same ratio. (The ratio is one part carbon- 14 to \(10^{12}\) parts carbon-12.) As long as the plant or animal is living, this ratio is maintained. When the organism dies, however, no new carbon-14 is absorbed, and the amount of carbon-14 begins to decrease exponentially. since the amount of carbon-14 decreases exponentially, it follows that the level of radioactivity also must decrease exponentially. The formula describing this situation is $$\mathcal{N}=\mathcal{N}_{0} e^{k T}$$ where \(T\) is the age of the sample, \(\mathcal{N}\) is the present level of radioactivity (in units of disintegrations per hour per gram of carbon), and \(\mathcal{N}_{0}\) is the level of radioactivity \(T\) years ago, when the organism was alive. Given that the half-life of carbon-14 is 5730 years and that \(\mathcal{N}_{0}=920\) disintegrations per hour per gram, show that the age \(T\) of a sample is given by $$T=\frac{5730 \ln (\mathcal{N} / 920)}{\ln (1 / 2)}$$

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