Chapter 5: Problem 44
Solve the equations. Express the answers in terms of natural logarithms. $$3 e^{1+t}=2$$
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Chapter 5: Problem 44
Solve the equations. Express the answers in terms of natural logarithms. $$3 e^{1+t}=2$$
These are the key concepts you need to understand to accurately answer the question.
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(a) Use a graphing utility to estimate the root(s) of the equation to the nearest one-tenth (as in Example 6). (b) Solve the given equation algebraically by first rewriting it in logarithmic form. Give two forms for each answer: an exact expression and a calculator approximation rounded to three decimal places. Check to see that each result is consistent with the graphical estimate obtained in part (a). $$e^{3 x^{2}}=112$$
Solve the inequalities. \(\log _{\pi}\left[\log _{4}\left(x^{2}-5\right)\right]<0 \quad\) Hint: In the expression \(\log _{b} y, y\) must be positive.
Solve each equation. $$\frac{\ln (\sqrt{x+4}+2)}{\ln \sqrt{x}}=2$$
Solve the inequalities. Where appropriate, give an exact answer as well as a decimal approximation. $$4^{5-x}>15$$
In the text we showed that the relative growth rate for the function \(\mathcal{N}(t)=\mathcal{N}_{0} e^{k t}\) is constant for all time intervals of unit length, \([t, t+1] .\) Recall that we did this by computing the relative change \([\mathcal{N}(t+1)-\mathcal{N}(t)] / \mathcal{N}(t)\) and noting that the result was a constant, independent of \(t .\) (If you've completed the previous exercise, you've done this calculation for yourself.) Now consider a time interval of arbitrary length, \([t, t+d] .\) The relative change in the function \(\mathcal{N}(t)=\mathcal{N}_{0} e^{k t}\) over this time interval is \([\mathcal{N}(t+d)-\mathcal{N}(t)] / \mathcal{N}(t) .\) Show that this quantity is a constant, independent of \(t .\) (The expression that you obtain for the constant will contain \(e\) and \(d\), but not \(t\) As a check on your work, replace \(d\) by 1 in the expression you obtain and make sure the result is the same as that in the text where we worked with intervals of length \(d=1 .)\)
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