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Fill in the blanks. (a) The functions \(f(x)=e^{x}\) and \(g(x)=\)_____are inverse functions. (b) In view of part (a) we have \(e^{\ln x}=\)_____for each positive number \(x,\) and \(\ln \left(e^{x}\right)=\)_____for all real numbers \(x\). (c) So, for example, without calculating, I know that \(e^{\ln 4 x}=\)_____and also that \(\ln \left(e^{-\pi}\right)=\)______.

Short Answer

Expert verified
(a) \(\ln(x)\), (b) \(x\), \(x\), (c) \(4x\), \(-\pi\).

Step by step solution

01

Identify the Inverse Function

For part (a), we need to determine the inverse function of \(f(x) = e^x\). The inverse of the exponential function \(e^x\) is the natural logarithm function, denoted by \(\ln(x)\). So, \(g(x) = \ln(x)\).
02

Evaluate Expressions Using Properties of Inverse Functions

In part (b), when a function and its inverse are applied consecutively, they cancel each other out, resulting in the original input. Thus:\[e^{\ln x} = x\]for each positive number \(x\), and similarly:\[\ln(e^x) = x\]for all real numbers \(x\).
03

Apply Inverses to Specific Values

In part (c), for \(e^{\ln 4x}\), the \(e\) exponential and the \(\ln\) logarithm cancel each other out, leaving us with simply \(4x\). Similarly, for \(\ln(e^{-\pi})\), the \(\ln\) and \(e\) cancel, leaving \(-\pi\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Functions
Understanding exponential functions is essential in grasping many mathematical concepts. An exponential function is typically written in the form \(f(x) = a \, e^{bx}\), where \(a\) and \(b\) are constants, and \(e\) is the base of natural logarithms, approximately equal to 2.71828. The key characteristic of an exponential function is that its rate of growth is proportional to its current value.

Exponential functions are widely used in various fields such as biology for population growth models, in finance for compound interest calculations, and in physics for radioactive decay.
  • The function \(f(x) = e^x\) is a basic form of an exponential function where the base \(e\) is the natural exponential.
  • This specific function grows very quickly, exhibiting continuous growth.
The graph of an exponential function is a curve that gets increasingly steeper as \(x\) increases, reflecting its rapid growth.
Natural Logarithm
The natural logarithm, denoted as \(\ln(x)\), is the inverse operation of the exponential function with base \(e\). It helps us solve equations where the variable is in the exponent. For instance, if you have \(e^y = x\), taking the natural logarithm of both sides, you find \(y = \ln(x)\).

The natural logarithm has several important properties:
  • \(\ln(1) = 0\), because \(e^0 = 1\).
  • \(\ln(e) = 1\), because \(e^1 = e\).
  • \(\ln(ab) = \ln(a) + \ln(b)\), which is helpful for multiplying within a logarithm.
  • \(\ln\left(\frac{a}{b}\right) = \ln(a) - \ln(b)\), allowing division to be simplified.
Solving problems with natural logarithms often involves using these properties to simplify and rearrange equations. Blending our understanding of natural logarithms with that of exponential functions enriches our mathematical toolkit.
Properties of Inverse Functions
Inverse functions are fascinating as they reverse the effect of the original function. For a function \(f\) and its inverse \(g\), applying both consecutively returns the original value: \(f(g(x)) = x\) and \(g(f(x)) = x\). This property is pivotal in manipulating equations and solving for unknowns.

With the exponential function \(f(x) = e^x\), its inverse is the natural logarithm function \(g(x) = \ln(x)\). Here's why they are considered inverses:
  • They effectively "undo" each other. For example, \(e^{\ln(x)} = x\), establishes that applying \(\ln\) and then \(e\) brings us back to \(x\).
  • Also, \(\ln(e^x) = x\), which shows that placing \(e\) inside \(\ln\) leads back to the input \(x\).
Understanding these properties allows us to simplify complex expressions and compute solutions effortlessly, much like the example where \(e^{\ln(4x)} = 4x\) or \(\ln(e^{-\pi}) = -\pi\). Mastering these concepts ensures a sound understanding of calculus and many analytical problems.

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Most popular questions from this chapter

Solve the inequalities. Where appropriate, give an exact answer as well as a decimal approximation. $$\frac{2}{3}\left(1-e^{-x}\right) \leq-3$$

Use the half-life information to complete each table. (The formula \(\mathcal{N}=\mathcal{N}_{0} e^{k t}\) is not required.) (a) Uranium-228: half-life \(=550\) seconds$$\begin{array}{llllll}t \text { (seconds) } & 0 & 550 & 1100 & 1650 & 2200 \\\\\mathcal{N} \text { (grams) } & 8 & & & \\\\\hline\end{array}$$ (b) Uranium-238: half-life \(=4.9 \times 10^{9}\) years$$\begin{array}{lcccccc}\hline \multirow{2}{*}\begin{array}{l}\text { t (years) } \\\\\mathcal{N} \text { (grams) }\end{array} & \multicolumn{2}{c}0 \\\& \multicolumn{2}{c}10 & 5 & 2.5 & 1.25 & 0.625 \\\\\hline\end{array}$$

Exercises \(55-60\) introduce a model for population growth that takes into account limitations on food and the environment. This is the logistic growth model, named and studied by the nineteenth century Belgian mathematician and sociologist Pierre Verhulst. (The word "logistic" has Latin and Greek origins meaning "calculation" and "skilled in calculation," respectively. However, that is not why Verhulst named the curve as he did. See Exercise 56 for more about this.) In the logistic model that we "I study, the initial population growth resembles exponential growth. But then, at some point owing perhaps to food or space limitations, the growth slows down and eventually levels off, and the population approaches an equilibrium level. The basic equation that we'll use for logis- tic growth is where \(\mathcal{N}\) is the population at time \(t, P\) is the equilibrium population (or the upper limit for population), and a and b are positive constants. $$\mathcal{N}=\frac{P}{1+a e^{-b t}}$$ (Continuation of Exercise 55 ) The author's ideas for this exercise are based on Professor Bonnie Shulman's article "Math-Alive! Using Original Sources to Teach Mathematics in Social Context," Primus, vol. VIII (March \(1998)\) (a) The function \(\mathcal{N}\) in Exercise 55 expresses population as a function of time. But as pointed out by Professor Shulman, in Verhulst's original work it was the other way around; he expressed time as a function of population. In terms of our notation, we would say that he was studying the function \(\mathcal{N}^{-1}\). Given \(\mathcal{N}(t)=4 /\left(1+8 e^{-t}\right)\) find \(\mathcal{N}^{-1}(t)\) (b) Use a graphing utility to draw the graphs of \(\mathcal{N}, \mathcal{N}^{-1}\), and the line \(y=x\) in the viewing rectangle [-3,8,2] by \([-3,8,2] .\) Use true portions. (Why?) (c) In the viewing rectangle [0,5,1] by \([-3,2,1],\) draw the graphs of \(y=\mathcal{N}^{-1}(t)\) and \(y=\ln t .\) Note that the two graphs have the same general shape and characteristics. In other words, Verhulst's logistic function (our \(\mathcal{N}^{-1}\) ) appears log-like, or logistique, as Verhulst actually named it in French. (For details, both historical and mathematical, see the paper by Professor Shulman cited above.)

Solve the inequalities. Where appropriate, give an exact answer as well as a decimal approximation. $$10^{-x^{2}} \leq 10^{-12}$$

Let \(f(x)=\ln (x+\sqrt{x^{2}+1}) .\) Find \(f^{-1}(x).\)

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