/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Simplify each expression. (a) ... [FREE SOLUTION] | 91Ó°ÊÓ

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Simplify each expression. (a) \(\ln e^{4}\) (b) \(\ln (1 / e)\) (c) \(\ln \sqrt{e}\)

Short Answer

Expert verified
(a) 4; (b) -1; (c) 1/2

Step by step solution

01

Simplify Expression (a)

The expression given is \( \ln e^{4} \). Using the property \( \ln e^{x} = x \), simplify the expression to \( 4 \).
02

Simplify Expression (b)

The expression given is \( \ln \left( \frac{1}{e} \right) \). First, rewrite it using the property of logarithms: \( \ln \left( \frac{1}{e} \right) = \ln e^{-1} \). Then, apply the property \( \ln e^{x} = x \), which simplifies it to \( -1 \).
03

Simplify Expression (c)

The expression given is \( \ln \sqrt{e} \). The square root can be expressed as a power: \( \sqrt{e} = e^{1/2} \). Apply the property \( \ln e^{x} = x \) to get \( \frac{1}{2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Natural Logarithm
The natural logarithm, often denoted as \( \ln \), is a special type of logarithm with the base \( e \). Euler's number \( e \) is an irrational and transcendental number approximately equal to 2.71828. The natural logarithm is the inverse of the exponential function with base \( e \).
When you see \( \ln(x) \), you're essentially asking: "To what power must \( e \) be raised to get \( x \)?" For example, solving \( \ln e^{4} \) means finding the exponent that \( e \) needs to be taken to, which in this case is 4. Hence, \( \ln e^{4} = 4 \).
The natural logarithm is often used in both pure math and practical applications such as compound interest, population growth, and radioactive decay, where quantities change at rates proportional to their size.
Understanding \( \ln \) fully allows you to solve complex problems involving exponential growth and decay by simplifying expressions and solving equations with ease.
Logarithm Properties
Logarithms have several important properties that help simplify complex expressions. A key property is the power rule: \( \ln(a^b) = b \ln(a) \). This rule allows us to bring down the exponent, simplifying expressions involving powers.
Another useful property is the addition and subtraction of logarithms: \( \ln(a) + \ln(b) = \ln(ab) \) and \( \ln(a) - \ln(b) = \ln\left(\frac{a}{b}\right) \). This aids in transforming products and quotients of numbers into sums and differences of logarithms.
For the exercise, we used the identity \( \ln e^{x} = x \) to directly find solutions. This property is invaluable because it turns exponential expressions into simple numerical values. In particular, it's applicable for expression (a) \( \ln e^4 \), which directly simplifies to 4, for expression (b) \( \ln\left(\frac{1}{e}\right) = -1 \), and for expression (c) \( \ln\left(\sqrt{e}\right) = \frac{1}{2} \).
Mastering these properties makes solving logarithmic equations and simplifying expressions easier and more intuitive.
Exponential Functions
Exponential functions are mathematical functions of the form \( f(x) = a^x \), where \( a \) is a constant and \( x \) appears as the exponent. These functions are characterized by their rapid growth or decay.
In exponential functions with base \( e \), such as \( e^x \), the rate of growth is proportional to the value of the function itself. This makes them ideal for modeling continuous growth processes, like population increase, financial interest, or natural phenomena like radioactive decay.
One crucial aspect of exponential functions is their relationship with logarithms. The natural logarithm \( \ln \) is the inverse of the exponential function with base \( e \). This means that applying \( \ln \) to \( e^x \) returns \( x \). In the exercise, we repeatedly used this relationship to simplify the expressions from their exponential forms to simple numbers.
Understanding how exponential functions behave and their interaction with logarithms provides a fundamental toolset for analyzing situations involving growth, decay, or any process that changes exponentially.

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Most popular questions from this chapter

You are given an equation and a root that was obtained in an example in the text. In each case: (a) verify (algebraically) that the root indeed satisfies the equation; and (b) use a calculator to check that the root satisfies the equation. [From Example \(3(a)] \quad \ln (\ln x)=2 ; x=e^{e^{2}}\)

Solve each equation. $$3(\ln x)^{2}-\ln \left(x^{2}\right)-8=0$$

Use the following information on \(p H\) Chemists define pH by the formula pH \(=-\log _{10}\left[\mathrm{H}^{+}\right],\) where [H \(^{+}\) ] is the hydrogen ion concentration measured in moles per liter. For example, if \(\left[\mathrm{H}^{+}\right]=10^{-5},\) then \(p H=5 .\) Solutions with \(a\) pH of 7 are said to be neutral; a p \(H\) below 7 indicates an acid: and a pH above 7 indicates a base. (A calculator is helpful for Exercises 49 and 50.1 What is the hydrogen ion concentration for black coffee if the pH is \(5.9 ?\)

Find the domain of the function \(g\) defined by \(g(x)=\ln (\ln (\ln x))\)

The Chernobyl nuclear explosion (in the former Soviet Union, on April 26,1986 ) released large amounts of radioactive substances into the atmosphere. These substances included cesium-137, iodine-131, and strontium-90. Although the radioactive material covered many countries, the actual amount and intensity of the fallout varied greatly from country to country, due to vagaries of the weather and the winds. One area that was particularly hard hit was Lapland, where heavy rainfall occurred just when the Chernobyl cloud was overhead. (a) Many of the pastures in Lapland were contaminated with cesium-137, a radioactive substance with a half- life of 33 years. If the amount of cesium- 137 was found to be ten times the normal level, how long would it take until the level returned to normal? Hint: Let \(\mathcal{N}_{0}\) be the amount that is ten times the normal level. Then you want to find the time when \(\mathcal{N}(t)=\mathcal{N}_{0} / 10\) (b) Follow part (a), but assume that the amount of cesium-137 was 100 times the normal level. Remark: Several days after the explosion, it was reported that the level of cesium- 137 in the air over Sweden was 10,000 times the normal level. Fortunately there was little or no rainfall.

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