/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 Find the domain of each function... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the domain of each function. (a) \(y=\ln \left(2-x-x^{2}\right)\) (b) \(y=\log _{10} \frac{2 x+3}{x-5}\)

Short Answer

Expert verified
(a) Domain: \((-2, 1)\); (b) Domain: \((-\infty, -\frac{3}{2}) \cup (5, \infty)\).

Step by step solution

01

Identify the Condition for Natural Logarithm Function

For a logarithmic function to be defined, the argument of the logarithm must be greater than zero. In the case of function (a), the argument is \(2 - x - x^2\). Thus, we need to solve the inequality \(2 - x - x^2 > 0\).
02

Solve the Inequality for Function (a)

To solve \(2 - x - x^2 > 0\), first rewrite it as \(-x^2 - x + 2 > 0\). Factor the quadratic expression to get \(-(x^2 + x - 2) > 0\). The quadratic \(x^2 + x - 2\) factors as \((x - 1)(x + 2)\). So solve \((x - 1)(x + 2) < 0\) to find the intervals where this inequality holds. Test intervals between critical points: \((-\infty, -2)\), \((-2, 1)\), and \((1, \infty)\). The solution is the interval \((-2, 1)\).
03

Identify the Condition for Common Logarithm Function

For the function (b), which contains a common logarithm, the argument must also be greater than zero. This means we must have \(\frac{2x + 3}{x - 5} > 0\).
04

Solve the Inequality for Function (b)

To solve \(\frac{2x + 3}{x - 5} > 0\), find critical points where the expression equals zero or is undefined: \(2x + 3 = 0\) gives \(x = -\frac{3}{2}\) and \(x - 5 = 0\) gives \(x = 5\). Test the intervals \((-\infty, -\frac{3}{2})\), \((-\frac{3}{2}, 5)\), and \((5, \infty)\) from these critical points to find where the inequality holds true. The solution is \((-\infty, -\frac{3}{2})\) union \((5, \infty)\).
05

Combined Step: Write the Domains for Each Function

Compile the results of each solve step: - The domain of function (a) is \(-2 < x < 1\), or \((-2, 1)\).- The domain of function (b) is \(x \in (-\infty, -\frac{3}{2}) \cup (5, \infty)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithmic Functions
Logarithmic functions are special and widely used in mathematics, especially in calculations involving growth rates, regression analysis, and even in computer science logics. A logarithmic function is in the form of usually either the natural logarithm, denoted as \(\ln(x)\), or the common logarithm, \(\log_{10}(x)\). These are inverse functions of exponential functions, meaning that they allow us to express powers in terms of multipliers.
  • The key point to remember about logarithmic functions is that they require their arguments to be greater than zero.
  • This is because a log function asks "what power do I need to raise the base to in order to get this number?" and for numbers less than or equal to zero, there is no valid answer.

In more straightforward terms, when you encounter a function like \(y = \ln(u)\) or \(y = \log_{10}(u)\), the expression inside the log, represented here as \(u\), must always fulfill the condition \(u > 0\).
Knowing this, when tasked with finding the domain of a logarithmic function, begin by determining where this inequality is satisfied by the expression inside the log. This analysis helps us confidently establish safe values for \(x\) that make the logarithmic function valid.
Inequality Solving
Solving inequalities is a crucial part of determining domains for logarithmic functions. When faced with inequalities, our task is to find all possible values for which the inequality holds true. This can include complex expressions but breaks down into logical steps for simplicity.
  • Begin by rearranging the inequality if necessary for clarity. Place all terms on one side of the inequality. This puts the expression into a standard form such as \(f(x) > 0\).
  • For quadratic inequalities, like \(-(x+1)(x+2) < 0\), the process starts with finding the critical values or roots, which happen when the expression equals zero.
  • These roots will split the number line into intervals. Test each interval to see if the inequality holds.

For example, with function (a) \(2 - x - x^2 > 0\), the expression can be rearranged and factored into \((x - 1)(x + 2) < 0\). We find that the roots, or critical points, are \(x = 1\) and \(x = -2\).
To determine where the inequality is true, test values from each interval created by these points. You'll establish regions like \((-\infty, -2)\), \((-2, 1)\), and \((1, \infty)\), and check which ones satisfy the inequality.
Function Domain Determination
Determining the domain of a function involves identifying all possible inputs (or \(x\)-values) that will produce real, valid outputs. For logarithmic functions, this determination means solving for where the argument inside the log can be greater than zero.
  • Let's recall, function domains are crucial in real-world applications because they define where the function can be appropriately applied.
  • It provides the range where all transformation and function manipulations will maintain their integrity.

For function (a) \(y=\ln(2-x-x^2)\), the domain requires solving \(2-x-x^2>0\) to find the valid \(x\)-values. Using factorization and test intervals, we find that the domain is \((-2, 1)\).
In function (b) \(y=\log_{10}\left(\frac{2x+3}{x-5}\right)\), prioritize solving \( \frac{2x+3}{x-5} > 0\). Find that the function is undefined at \(x = 5\) and has a zero at \(x = -\frac{3}{2}\). Thus, the valid domain is \((-\infty, -\frac{3}{2}) \cup (5, \infty)\).
Through these examples, you see that establishing a domain is visually about finding these critical intervals and understanding where the function "works" as intended.

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Most popular questions from this chapter

An article that appeared in the August \(13,1994,\) New York Times reported German authorities have discovered.... a tiny sample of weapons-grade nuclear material believed to have been smuggled out of Russia to interest foreign governments or terrorist groups that might want to build atomic bombs..... [the police] said they had seized the material, .028 ounces of highly enriched uranium- 235 in June in ... Bavaria ... and have since arrested... \([\text { six }]\) suspects. \(\ldots\) Suppose that the suspects, in an attempt to avoid arrest, had thrown the 0.028 ounces of uranium- 235 into the Danube River, where it would sink to the bottom. How many ounces of the uranium-235 would still be in the river after 1000 years? The half-life of uranium- 235 is \(7.1 \times 10^{8}\) years.

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