/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 Find all the real-number roots o... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find all the real-number roots of each equation. In each case, give an exact expression for the root and also (where appropriate) a calculator approximation rounded to three decimal places. $$\ln 4-\ln x=(\ln 4) /(\ln x)$$

Short Answer

Expert verified
The real roots are approximately \( x \approx 4.808 \) and \( x \approx 0.832 \).

Step by step solution

01

Understand the Equation

We begin with the equation \( \ln 4 - \ln x = \frac{\ln 4}{\ln x} \). Our goal is to find the values of \( x \) that satisfy this equation.
02

Simplify the Logarithmic Equation

Notice that \( \ln 4 - \ln x = \ln \left(\frac{4}{x}\right) \). So, our equation becomes \( \ln \left(\frac{4}{x}\right) = \frac{\ln 4}{\ln x} \).
03

Explore Function Transformation

Interestingly, the equation can also be seen as a function transformation. Consider \( y = \ln x \), then we have \( \ln \left(\frac{4}{e^y}\right) = \frac{\ln 4}{y} \), simplifying to \( \ln 4 - y = \frac{\ln 4}{y} \). Set this as \( f(y) = y - \frac{\ln 4}{y} \) and solve for roots.
04

Solve via Quadratic Substitution

Let \( z = \ln x \). Substitute in to get the equation \( \ln 4 - z = \frac{\ln 4}{z} \), or rearranging, \( z^2 - z \ln 4 - \ln 4 = 0 \). This is a quadratic equation in \( z \).
05

Apply the Quadratic Formula

Use the quadratic formula \( z = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), with \( a = 1 \), \( b = -\ln 4 \), \( c = -\ln 4 \). Substituting these values gives: \[ z = \frac{\ln 4 \pm \sqrt{(\ln 4)^2 + 4\ln 4}}{2} \].
06

Simplify Solutions for \( z \)

Calculate the solutions for \( z \):\[ z = \frac{\ln 4 + \sqrt{(\ln 4)^2 + 4\ln 4}}{2} \] and \[ z = \frac{\ln 4 - \sqrt{(\ln 4)^2 + 4\ln 4}}{2} \].
07

Back-Substitute to Find \( x \)

Recall \( z = \ln x \), so the solutions for \( x \) are: \[ x_1 = e^{\frac{\ln 4 + \sqrt{(\ln 4)^2 + 4\ln 4}}{2}} \] and \[ x_2 = e^{\frac{\ln 4 - \sqrt{(\ln 4)^2 + 4\ln 4}}{2}} \].
08

Approximating the Roots

Calculate these solutions using a calculator for approximate values:\( x_1 \approx 4.808 \) and \( x_2 \approx 0.832 \), rounded to three decimal places.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithmic Equations
In mathematics, logarithms are the inverse operations to exponentiation. That means they allow us to undo the process of taking powers.

If you have an equation involving logarithms, you need to understand how to simplify them effectively. For example, the logarithmic identity \( \ln a - \ln b = \ln \left(\frac{a}{b}\right) \) helps in simplifying expressions by combining separate logs into a single one.

The given problem starts with the equation \( \ln 4 - \ln x = \frac{\ln 4}{\ln x} \). Using the logarithmic property of subtraction allows us to rewrite the left side as a single logarithm: \( \ln \frac{4}{x} \). This makes it easier to see how both sides compare and solve for \( x \).
Quadratic Equations
Quadratic equations are polynomial equations of the form \( ax^2 + bx + c = 0 \). These equations can often be solved by factoring, completing the square, or using the quadratic formula.

In our problem, a clever substitution transforms the logarithmic equation into a quadratic form. By letting \( z = \ln x \), the problem becomes \( z^2 - z \ln 4 - \ln 4 = 0 \).

Solving this requires using the quadratic formula: \( z = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). Plugging in the values \( a = 1 \), \( b = -\ln 4 \), and \( c = -\ln 4 \) leads to the solutions for \( z \), which then help us find the values of \( x \).
Real-Number Roots
Real-number roots are solutions to an equation that are real numbers. They're the values that make the equation true when substituted back into it.

In this case, after solving the quadratic equation for \( z \), we have values for \( z \) that correspond to real-number solutions of our original logarithmic equation. These relate back to \( x \) via the exponential function \( x = e^z \).

Once calculated, we find that \( x_1 \approx 4.808 \) and \( x_2 \approx 0.832 \), both of which are real numbers indicating that these solutions exist on the number line and not as imaginary or complex numbers.
Function Transformation
Function transformation involves changing the appearance or position of a function on a graph. It's an important concept in solving complex equations.

In our problem setup, the function \( y = \ln x \) transforms the original equation. We express \( \ln x \) as \( y \) which simplifies the problem into finding the roots for \( f(y) = y - \frac{\ln 4}{y} \).

By transforming the logarithmic equation into a form involving a transformation function, it becomes easier to identify the solutions, leading to simpler substitutions and calculations. This technique is essential for breaking down complex problems into more understandable parts.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Exercises \(55-60\) introduce a model for population growth that takes into account limitations on food and the environment. This is the logistic growth model, named and studied by the nineteenth century Belgian mathematician and sociologist Pierre Verhulst. (The word "logistic" has Latin and Greek origins meaning "calculation" and "skilled in calculation," respectively. However, that is not why Verhulst named the curve as he did. See Exercise 56 for more about this.) In the logistic model that we "I study, the initial population growth resembles exponential growth. But then, at some point owing perhaps to food or space limitations, the growth slows down and eventually levels off, and the population approaches an equilibrium level. The basic equation that we'll use for logis- tic growth is where \(\mathcal{N}\) is the population at time \(t, P\) is the equilibrium population (or the upper limit for population), and a and b are positive constants. $$\mathcal{N}=\frac{P}{1+a e^{-b t}}$$ The following figure shows the graph of the logistic function \(\mathcal{N}(t)=4 /\left(1+8 e^{-t}\right) .\) Note that in this equation the equilibrium population \(P\) is 4 and that this corresponds to the asymptote \(\mathcal{N}=4\) in the graph. (a) Use the graph and your calculator to complete the following table. For the values that you read from the graph, estimate to the nearest \(0.25 .\) For the calculator values, round to three decimal places. (b) As indicated in the graph, the line \(\mathcal{N}=4\) appears to be an asymptote for the curve. Confirm this empirically by computing \(\mathcal{N}(10), \mathcal{N}(15),\) and \(\mathcal{N}(20) .\) Round each answer to eight decimal places. (c) Use the graph to estimate, to the nearest integer, the value of \(t\) for which \(\mathcal{N}(t)=3\) (d) Find the exact value of \(t\) for which \(\mathcal{N}(t)=3 .\) Evaluate the answer using a calculator, and check that it is consistent with the result in part (c). TABLE AND GRAPH CANT COPY

Decide which of the following properties apply to each function. (More than one property may apply to a function.)A. The function is increasing for \(-\infty

Solve the inequality \(\log _{10}\left(x^{2}-6 x-6\right)>0.\)

A function \(f\) with domain \((1, \infty)\) is defined by the equation \(f(x)=\log _{x} 2\) (a) Find a value for \(x\) such that \(f(x)=2\) (b) Is the number that you found in part (a) a fixed point of the function \(f ?\)

Use the following information on \(p H\) Chemists define pH by the formula pH \(=-\log _{10}\left[\mathrm{H}^{+}\right],\) where [H \(^{+}\) ] is the hydrogen ion concentration measured in moles per liter. For example, if \(\left[\mathrm{H}^{+}\right]=10^{-5},\) then \(p H=5 .\) Solutions with \(a\) pH of 7 are said to be neutral; a p \(H\) below 7 indicates an acid: and a pH above 7 indicates a base. (A calculator is helpful for Exercises 49 and 50.1 A chemist adds some acid to a solution changing the \(\mathrm{pH}\) from 6 to \(4 .\) By what factor does the hydrogen ion concentration change? Note: Lower pH corresponds to higher hydrogen ion concentration.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.