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Graph the function and specify the domain, range, intercept(s), and asymptote. $$y=e^{x+1}$$

Short Answer

Expert verified
Domain: \((-\infty, \infty)\); Range: \((0, \infty)\); Intercept: y-intercept at \((0, e)\); Asymptote at \(y = 0\).

Step by step solution

01

Understand the Function

The given function is \( y = e^{x+1} \). This is an exponential function where the base \( e \approx 2.718 \) and the exponent is \( x + 1 \). The graph of such a function is an exponential curve that grows rapidly as \( x \) increases.
02

Identify the Domain

The domain of any exponential function of the form \( y = e^{f(x)} \) is all real numbers, \( x \in (-\infty, \infty) \), because there are no restrictions on the real numbers that \( x \) can take.
03

Identify the Range

For the exponential function \( y = e^{x+1} \), as \( e^x \) is always positive, the range of the function \( e^{x+1} \) is also positive and is \( (0, \infty) \).
04

Find the Intercept(s)

To find the y-intercept, set \( x = 0 \). Then, \( y = e^{0+1} = e^1 = e \). Therefore, the y-intercept is \( (0, e) \). There are no x-intercepts because an exponential function of form \( e^{x+1} \) never touches the x-axis.
05

Determine the Asymptote

The horizontal asymptote for \( y = e^{x+1} \) is the line \( y = 0 \). This is because as \( x \) approaches negative infinity, \( e^{x+1} \) approaches 0.
06

Graph the Function

To graph \( y = e^{x+1} \), start by plotting the y-intercept \( (0, e) \) and then sketch the rapidly increasing curve. It will approach the line \( y = 0 \) as x goes to negative infinity, passing through the y-intercept, and then rise sharply as x increases.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain and Range
When discussing exponential functions, like the one given by the equation \( y = e^{x+1} \), understanding the domain and range is key. The "domain" of a function refers to all the possible input values (in this case, \( x \) values) that the function can handle. For exponential functions, there are no restrictions on \( x \). This means you can substitute any real number into the equation. Therefore, the domain is all real numbers, written as \((-\infty, \infty)\).

On the other side, we have the "range," which represents all the possible output values (\( y \) values) the function can produce. Exponential functions of the form \( y = e^{x+1} \), will never yield negative values or zero because \( e \) raised to any power is always positive. This makes the range \( (0, \infty) \).

  • Domain: \( (-\infty, \infty) \)
  • Range: \( (0, \infty) \)
Intercepts
Identifying intercepts is crucial for graphing functions and understanding their behavior. For the function \( y = e^{x+1} \), let's find the intercepts.

The **y-intercept** is found by setting \( x = 0 \). Plug this into the equation to get \( y = e^{0+1} = e \). Thus, the y-intercept is the point \( (0, e) \), which you can plot on a graph. It marks where the graph of the function intersects the y-axis.

Exponential functions like \( y = e^{x+1} \) don't have an x-intercept because their graph never touches or crosses the x-axis. The value of \( y \) is always positive, no matter what value \( x \) takes.

  • Y-intercept: \( (0, e) \)
  • X-intercepts: None
Asymptotes
An asymptote is a line that a graph approaches but never touches or crosses. For exponential functions like \( y = e^{x+1} \), identifying asymptotes helps in understanding the behavior of the graph at extreme values of \( x \).

In the case of \( y = e^{x+1} \), there is a horizontal asymptote. This occurs because as \( x \) goes to negative infinity, the value \( e^{x+1} \) gets closer and closer to zero but will never actually reach it. Therefore, the horizontal asymptote is the line \( y = 0 \).

Understanding where the asymptote lies gives insight into the potential growth or decay of the function. In this function, as \( x \) increases, the graph rises exponentially and will never approach the line \( y = 0 \) from above.

  • Horizontal Asymptote: \( y = 0 \)

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