/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 Write the expression as a single... [FREE SOLUTION] | 91Ó°ÊÓ

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Write the expression as a single logarithm with a coefficient of \(1 .\) $$p \log _{b} A-q \log _{b} B+r \log _{b} C$$

Short Answer

Expert verified
\( \log_b\left( \frac{A^p C^r}{B^q} \right) \)

Step by step solution

01

Apply the Power Rule for Logarithms

The power rule for logarithms states that for any logarithm \( \log_b(x^p) = p \log_b(x) \). Therefore, apply this rule to each term in the expression: \( p \log_b A = \log_b(A^p) \), \( q \log_b B = \log_b(B^q) \), and \( r \log_b C = \log_b(C^r) \).
02

Combine the Logs Using the Quotient Rule

The expression now becomes \( \log_b(A^p) - \log_b(B^q) + \log_b(C^r) \). Use the quotient and product rules for logarithms to combine the terms: \( \log_b(A^p) + \log_b(C^r) - \log_b(B^q) \). This can be rewritten as a single logarithm: \( \log_b\left( \frac{A^p \cdot C^r}{B^q} \right) \).
03

Verify the Expression has Coefficient 1

The combined logarithm \( \log_b\left( \frac{A^p C^r}{B^q} \right) \) is already expressed as a single logarithm where the coefficient is 1, confirming the problem's requirement is satisfied.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule for Logarithms
When dealing with logarithmic expressions, the power rule is a handy tool to simplify and solve problems more efficiently. The power rule states that you can bring the exponent of the inside term to the front as a coefficient. Mathematically, it’s written as:\[ p \log_b(x) = \log_b(x^p) \]This is particularly useful when working with expressions that contain coefficients in front of the log term. Instead of calculating directly, you first raise the base of the logarithm to the power of the coefficient.
  • Example: If you encounter an expression like \(3 \log_b(2)\), you apply the power rule to rewrite it as \(\log_b(2^3)\) which is \(\log_b(8)\).
  • This helps in simplifying further operations, such as combining the logs in a later step.
By using the power rule, each term in our original expression can be rewritten without extra coefficients affecting the simple single-log form. This forms the foundation for combining logarithms effectively in subsequent steps.
Quotient Rule for Logarithms
The quotient rule for logarithms simplifies expressions where logs are being subtracted. It states:\[ \log_b(x) - \log_b(y) = \log_b\left(\frac{x}{y}\right) \]This rule allows you to write a single logarithm expression by transforming the subtraction of two logs into a division inside one log. This can be particularly useful when you have multiple log terms to consolidate.
  • If initially, you have \(\log_b(15) - \log_b(3)\), then applying the quotient rule, you have \(\log_b\left(\frac{15}{3}\right)\) which simplifies to \(\log_b(5)\).
Understanding this rule is crucial when working with problems that involve both multiplication and division of the arguments within logarithms. It streamlines the process of combining them into a neater form, which is easier to manage.
Combining Logarithms
Combining logarithmic terms into a single expression is an essential skill for simplifying complex equations. This involves using both the power and quotient rules for logarithms.After applying the power rule to eliminate coefficients, the next step is usually merging the logs into one. Once you have similar base logs, use both the product and quotient rules accordingly:
  • First, apply the product rule: If adding, you multiply the numbers inside the logs.
  • Then, apply the quotient rule: If subtracting, you divide the numbers inside the logs.
In our example, we rearranged terms to apply these principles. The original separate logarithms of \(p\log_b(A)\), \(q\log_b(B)\), and \(r\log_b(C)\) are combined by rearranging into one single log:\[ \log_b\left( \frac{A^p \cdot C^r}{B^q} \right) \]This result is a single logarithm, elegantly capturing the full essence of the equation, with no coefficients, fulfilling the requirement for a coefficient of one. It is a powerful example of using logarithm properties to streamline complex expressions into simplified forms.

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Most popular questions from this chapter

(a) Use a graphing utility to estimate the root(s) of the equation to the nearest one-tenth (as in Example 6). (b) Solve the given equation algebraically by first rewriting it in logarithmic form. Give two forms for each answer: an exact expression and a calculator approximation rounded to three decimal places. Check to see that each result is consistent with the graphical estimate obtained in part (a). $$e^{t-1}=16$$

Find the domain of the function \(g\) defined by \(g(x)=\ln (\ln (\ln x))\)

Solve the inequalities. Where appropriate, give an exact answer as well as a decimal approximation. $$3\left(2-0.6^{x}\right) \leq 1$$

Let \(\mathcal{N}=\mathcal{N}_{0 e^{k t}} .\) In this exercise we show that if \(\Delta t\) is very small, then \(\Delta \mathcal{N} / \Delta t \approx k \mathcal{N} .\) In other words, over very small intervals of time, the average rate of change of \(\mathcal{N}\) is proportional to \(\mathcal{N}\) itself. (a) Show that the average rate of change of the function \(\mathcal{N}=\mathcal{N}_{0} e^{t t}\) on the interval \([t, t+\Delta t]\) is given by $$\frac{\Delta \mathcal{N}}{\Delta t}=\frac{\mathcal{N}_{0} e^{k t}\left(e^{k \Delta t}-1\right)}{\Delta t}=\frac{\mathcal{N}\left(e^{k \Delta t}-1\right)}{\Delta t}$$ (b) In Exercise 26 of Section 5.2 we saw that \(e^{x} \approx x+1\) when \(x\) is close to zero. Thus, if \(\Delta t\) is sufficiently small, we have \(e^{k \Delta t} \approx k \Delta t+1 .\) Use this approximation and the result in part (a) to show that \(\Delta \mathcal{N} / \Delta t \approx k N\) when \(\Delta t\) is sufficiently close to zero.

(a) Specify the domain of the function \(y=\ln x+\ln (x-4).\) (b) Solve the inequality \(\ln x+\ln (x-4) \leq \ln 21.\)

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