/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 Write the expression as a single... [FREE SOLUTION] | 91Ó°ÊÓ

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Write the expression as a single logarithm with a coefficient of \(1 .\) $$2 \log _{10} x-3 \log _{10} y$$

Short Answer

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\( \log_{10} (x^2 y^3) \)

Step by step solution

01

Apply the Power Rule for Logarithms

The power rule for logarithms states that if you have a coefficient in front of a logarithm, you can move it as an exponent inside the logarithm: \( a \log_b M = \log_b M^a \). - Apply this rule to each term: - For \( 2 \log_{10} x \), it becomes \( \log_{10} x^2 \). - For \(-3 \log_{10} y \), it becomes \( \log_{10} y^{-3} \).
02

Use the Quotient Rule for Logarithms

The quotient rule for logarithms states: \( \log_b M - \log_b N = \log_b \left( \frac{M}{N} \right) \). - Apply this rule to the terms obtained from the previous step: - You have \( \log_{10} x^2 - \log_{10} y^{-3} \), so it becomes \( \log_{10} \left( \frac{x^2}{y^{-3}} \right) \).
03

Simplify the Expression

Simplify the expression inside the logarithm:- The term \( \frac{x^2}{y^{-3}} \) simplifies to \( x^2 \times y^3 \) because dividing by \( y^{-3} \) is the same as multiplying by \( y^3 \).- So the logarithmic expression becomes \( \log_{10} (x^2 y^3) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule for Logarithms
The power rule for logarithms is a very useful property. It allows us to manipulate logarithmic expressions in a way that simplifies computation.
When you have a coefficient in front of a logarithm, like in expressions of the form \(a \log_b M\), it can be transformed. This coefficient becomes an exponent over the argument of the logarithm itself. For instance, \(2 \log_{10} x\) turns into \( \log_{10} x^2\).
This transformation occurs because logarithms essentially represent powers. By using the power rule, we are essentially reversing the extraction of the exponent, making it possible to simplify expressions neatly. Similarly, for a negative coefficient such as \(-3 \log_{10} y\), it becomes \( \log_{10} y^{-3}\).
Understanding this rule is vital as it lays the foundation for more advanced logarithmic operations and can significantly reduce complexity when dealing with exponential expressions.
Quotient Rule for Logarithms
The quotient rule for logarithms is another fundamental tool for simplifying expressions. It aids in combining separate logarithmic terms into a single expression.
According to this rule, if you have a difference between two logarithms, like \(\log_b M - \log_b N\), it can be combined into one: \(\log_b \left( \frac{M}{N} \right)\).
This helps when simplifying expressions. For example, after applying the power rule, transforming \(\log_{10} x^2 - \log_{10} y^{-3}\) into one single logarithmic term becomes possible.
  • The expression \(\log_{10} x^2\) and \(-\log_{10} y^{-3}\) translates to \(\log_{10} \left( \frac{x^2}{y^{-3}} \right)\).
The quotient rule is all about understanding subtraction in terms of division – subtracting logs is the same as taking the log of a quotient.
Single Logarithm
Writing an expression as a single logarithm is often the goal in logarithmic simplification. This leads to more concise and easily interpretable expressions.
Once you've used the power and quotient rules, you may find terms like \(\log_{10} \left( \frac{x^2}{y^{-3}} \right)\). Often, further simplification is possible.
Inside the logarithm, simplify the expression: \(\frac{x^2}{y^{-3}}\) is equivalent to \(x^2 \times y^3\) because dividing by a negative exponent converts it into a multiplication.
Therefore, the single logarithmic expression becomes \(\log_{10} (x^2 y^3)\). The final result is a neat, single expression with a coefficient of one, which is easier to handle in practical applications.

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Most popular questions from this chapter

This exercise demonstrates the very slow growth of the natural logarithm function \(y=\ln x .\) We consider the following question: How large must \(x\) be before the graph of \(y=\ln x\) reaches a height of \(10 ?\) (a) Graph the function \(y=\ln x\) using a viewing rectangle that extends from 0 to 10 in the \(x\) -direction and 0 to 12 in the \(y\) -direction. Note how slowly the graph rises. Use the graphing utility to estimate the height of the curve (the \(y\) -coordinate) when \(x=10\) (b) since we are trying to see when the graph of \(y=\ln x\) reaches a height of 10 , add the horizontal line \(y=10\) to your picture. Next, adjust the viewing rectangle so that \(x\) extends from 0 to \(100 .\) Now use the graphing utility to estimate the height of the curve when \(x=100 .\) [As both the picture and the \(y\) -coordinate indicate, we're still not even halfway to \(10 .\) Go on to part (c).] (c) Change the vicwing rectangle so that \(x\) extends to \(1000,\) then estimate the \(y\) -coordinate corresponding to \(x=1000 .\) (You'll find that the height of the curve is almost \(7 .\) We're getting closer.) (d) Repeat part (c) with \(x\) extending to \(10,000 .\) (You'll find that the height of the curve is over \(9 .\) We're almost there. \()\) (e) The last step: Change the viewing rectangle so that \(x\) extends to \(100,000,\) then use the graphing utility to estimate the \(x\) -value for which \(\ln x=10 .\) As a check on your estimate, rewrite the equation \(\ln x=10\) in exponential form, and evaluate the expression that you obtain for \(x\)

A sound level of \(\beta=120 \mathrm{db}\) is at the threshold of pain. (Some loud rock concerts reach this level.) The sound intensity that corresponds to \(\beta=120 \mathrm{db}\) is \(1 \mathrm{W} / \mathrm{m}^{2}\). Use this information and the equation \(\beta=10 \log _{10}\left(I / I_{0}\right)\) to determine \(I_{0}\), the intensity of a barely audible sound at the threshold of hearing. What is the decibel level, \(\beta\), of a barely audible sound?

Solve each equation. $$\frac{\ln (\sqrt{x+4}+2)}{\ln \sqrt{x}}=2$$

Use the following information on \(p H\) Chemists define pH by the formula pH \(=-\log _{10}\left[\mathrm{H}^{+}\right],\) where [H \(^{+}\) ] is the hydrogen ion concentration measured in moles per liter. For example, if \(\left[\mathrm{H}^{+}\right]=10^{-5},\) then \(p H=5 .\) Solutions with \(a\) pH of 7 are said to be neutral; a p \(H\) below 7 indicates an acid: and a pH above 7 indicates a base. (A calculator is helpful for Exercises 49 and 50.1 An unknown substance has a hydrogen ion concentration of \(3.5 \times 10^{-9} .\) Classify the substance as acid or base.

Solve each equation and solve for \(x\) in terms of the other letters. $$y=a /\left(1+b e^{-k x}\right)$$

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