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If \(f(x)=a x^{2}+b x+c,\) show that \(\frac{f(x+h)-f(x)}{h}=2 a x+a h+b\).

Short Answer

Expert verified
The expression simplifies to \( 2ax + ah + b \).

Step by step solution

01

Understand the Definition of Function f(x)

The given function is a quadratic function in the form \( f(x) = ax^2 + bx + c \), where \( a, b, \) and \( c \) are constants. We need to evaluate the expression \( \frac{f(x+h)-f(x)}{h} \) for this quadratic function.
02

Substitute x+h into the Function

Substitute \( x+h \) into \( f(x) \) to get \( f(x+h) = a(x+h)^2 + b(x+h) + c \). This involves expanding and simplifying the expression.
03

Expand the Expression for f(x+h)

Expand \( f(x+h) = a(x+h)^2 + b(x+h) + c \). First, calculate \( (x+h)^2 = x^2 + 2xh + h^2 \). Substitute back to get \( f(x+h) = a(x^2 + 2xh + h^2) + bx + bh + c \). Simplify this to \( ax^2 + 2axh + ah^2 + bx + bh + c \).
04

Calculate the Difference f(x+h) - f(x)

Subtract \( f(x) = ax^2 + bx + c \) from \( f(x+h) = ax^2 + 2axh + ah^2 + bx + bh + c \). This results in \( 2axh + ah^2 + bh \) (as the terms \( ax^2 + bx + c \) cancel out).
05

Divide by h and Simplify

Divide the result from Step 4 by \( h \): \( \frac{2axh + ah^2 + bh}{h} = 2ax + ah + b \). Simplifying involves dividing each term by \( h \), leading to the final expression \( 2ax + ah + b \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Functions
Quadratic functions are a type of polynomial function where the highest degree of the variable is 2.
The general form of a quadratic function is given by:
  • \( f(x) = ax^2 + bx + c \)
Here, \( a \), \( b \), and \( c \) are constants, and \( a \) should not be zero for the function to remain quadratic. These functions are known for their distinctive parabolic graphs.
A graph of this function shape-forming a parabola that opens upward if \( a > 0 \) and downward if \( a < 0 \).
  • The vertex of the parabola is a significant point, often representing the maximum or minimum value of the function.
  • The axis of symmetry is a vertical line passing through the vertex.
  • The roots or zeroes of the quadratic function are the points where the graph crosses the x-axis, which can be found using the quadratic formula.
All these aspects make the quadratic function an essential part of differential calculus for examining changes and behaviors in curves.
Difference Quotient
The concept of a difference quotient helps in understanding how a function changes between two points. It is a crucial tool in differential calculus that leads to the derivative of a function.
The difference quotient for a function \( f(x) \) is expressed as:
  • \( \frac{f(x+h) - f(x)}{h} \)
Here, \( h \) represents a small change in \( x \). As \( h \) approaches zero, the difference quotient converges to the derivative of the function, which describes how \( f(x) \) changes at an infinitesimal level.
The original problem demonstrates this fundamental process applied to a quadratic function, displaying how specific calculations on the difference quotient simplify to form its derivative.
Understanding the difference quotient is akin to understanding the core of differentiation, leading to discoveries about the slope of tangents to graphs.
Polynomial Expansion
Polynomial expansion refers to the process of expressing a polynomial, especially in nested formats, into a simple, extended form. The exercise features this in Step 2 and Step 3 by expanding \( (x+h)^2 \) for a complete expression.
When expanding \( (x+h)^2 \), you apply the distributive property to obtain:
  • \( x^2 + 2xh + h^2 \)
With this expansion done, it's easily plugged back into the function to further simplify and evaluate expressions.
Polynomial expansion is important as it breaks down complex expressions into linearity, making it more manageable to work through in calculations like differentiation.
With quadratic functions, expansion simplifies terms and clarifies how each component behaves under algebraic manipulation—vital for deeper calculus operations like finding limits or derivatives.

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Most popular questions from this chapter

Let \(f(x)=\left(x^{3}+2 x^{2}+1\right) /\left(x^{2}+2 x\right)\) (a) Graph the function \(f\) using a viewing rectangle extending from -5 to 5 in both the \(x\) - and \(y\) -directions. (b) Add the graph of the line \(y=x\) to your picture in part (a). Note that to the right of the origin, as \(x\) increases, the graph of \(f\) begins to look more and more like the line \(y=x .\) This also occurs to the left of the origin as \(x\) decreases. (c) The results in part (b) suggest that the line \(y=x\) may be an asymptote for the graph of \(f .\) Verify this visually by changing the viewing rectangle so that it extends from -20 to 20 in both the \(x\) - and the \(y\) -directions. What do you observe? (d) Using algebra, verify the identity $$ \frac{x^{3}+2 x^{2}+1}{x^{2}+2 x}=\frac{1}{x^{2}+2 x}+x $$ Then explain why, for large values of \(|x|\), the graph of flooks more and more like the line \(y=x\). Hint: Substitute some large numbers (such as 100 or 1000 ) into the expression \(1 /\left(x^{2}+2 x\right) .\) What happens?

Sketch the graph of each rational function. Specify the intercepts and the asymptotes. (a) \(f(x)=(x-2)(x-4) /[x(x-1)]\) (b) \(g(x)=(x-2)(x-4) /[x(x-3)]\) [Compare the graphs you obtain in parts (a) and (b). Notice how a change in only one constant can radically alter the nature of the graph.]

Sketch the graph of each rational function. Specify the intercepts and the asymptotes. $$y=2 x /(x+1)^{2}$$

This exercise shows that if we have a table generated by a linear function and the \(x\) -values are equally spaced, then the first differences of the \(y\) -values are constant. (a) In the following data table, the three \(x\) -entries are equally spaced. Compute the three entries in the \(f(x)\) row assuming that \(f\) is the linear function given by \(f(x)=m x+b\) \(f(x)=m x+b .\) (Don't worry about the fact that your answers contain all four of the letters \(m, b, a, \text { and } h .)\) \begin{tabular}{llll} \hline\(x\) & \(a\) & \(a+h\) & \(a+2 h\) \\ \(f(x)\) & & & \\ \hline \end{tabular} (b) Compute the first differences for the three quantities that you listed in the \(f(x)\) row in part (a). (The two first differences that you obtain should turn out to be equal, as required.)

A piece of wire 4 m long is cut into two pieces, then each piece is bent into a square. Express the combined area of the two squares in terms of one variable.

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