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(a) Determine the \(x\) - and \(y\) -intercepts and the excluded regions for the graph of the given function. Specify your results using a sketch similar to Figure \(16(a) .\) In Exercises \(31-34\) you will first need to factor the polynomial. (b) Graph each function. $$y=x^{3}-4 x^{2}-5 x$$

Short Answer

Expert verified
The x-intercepts are -1, 0, and 5; the y-intercept is 0.

Step by step solution

01

Factor the Polynomial

The given function is \( y = x^3 - 4x^2 - 5x \). First, factor out the greatest common factor, which is \( x \). Thus, we have \( y = x(x^2 - 4x - 5) \). Next, factor the quadratic part \( x^2 - 4x - 5 \). We need two numbers that multiply to \(-5\) and add up to \(-4\), which are \(-5\) and \(1\). So, we factor it as \( (x - 5)(x + 1) \). Therefore, the complete factored form is \( y = x(x - 5)(x + 1) \).
02

Determine the x-intercepts

To find the \( x \)-intercepts, set \( y = 0 \) and solve for \( x \). We have \( x(x - 5)(x + 1) = 0 \). Therefore, the \( x \)-intercepts are the roots of the equation: \( x = 0 \), \( x = 5 \), and \( x = -1 \).
03

Determine the y-intercept

To find the \( y \)-intercept, set \( x = 0 \) in the original equation, \( y = x^3 - 4x^2 - 5x \). This results in \( y = 0^3 - 4(0)^2 - 5(0) = 0 \). Thus, the \( y \)-intercept is \( y = 0 \), which is at the origin (0,0).
04

Identify Excluded Regions

Excluded regions refer to values that make the function undefined, which aren't applicable in this context since it's a polynomial and polynomials are defined for all real numbers. Thus, there are no excluded regions.
05

Sketch the Graph

Using the intercepts found, sketch the graph. Begin at the origin, then note the \( x \)-intercepts at \(-1\), \(0\), and \(5\). The behavior of the cubic function indicates it will extend down to the left and up to the right, crossing through the intercepts. The graph will have a turning point between these intercepts due to the cubic nature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

x-intercepts
The term "x-intercept" refers to the points where the graph of a function crosses the x-axis. To find these intercepts, set the output of the function, typically denoted by "y", to zero. For our polynomial function, \( y = x(x - 5)(x + 1) \), we will solve the equation \( x(x - 5)(x + 1) = 0 \).

- The first intercept happens when \( x = 0 \).
- The second when \( x - 5 = 0 \), so \( x = 5 \).
- The third when \( x + 1 = 0 \), so \( x = -1 \).

Thus, the x-intercepts for the function are at \( x = 0 \), \( x = 5 \), and \( x = -1 \). These points show where the function crosses or touches the x-axis.
y-intercepts
Finding the y-intercept involves setting \( x = 0 \) and determining the corresponding value of \( y \). This tells us where the graph intersects the y-axis.

For our function \( y = x^3 - 4x^2 - 5x \), substituting \( x = 0 \) results in:

\[y = (0)^3 - 4(0)^2 - 5(0) = 0\]

This computation reveals that the y-intercept is at \( y = 0 \), also known as the origin (\(0, 0\)). It's a special point because it's the starting position from which the graph begins, depending on the behavior dictated by the polynomial degree and coefficients.
factoring polynomials
Factoring polynomials is crucial for simplifying equations and uncovering key properties like intercepts. In polynomial algebra, factoring allows us to break down complex polynomial expressions into simpler factors that multiply together to give the original expression.

Our initial function is \( y = x^3 - 4x^2 - 5x \). Here, we identified \( x \) as a common factor of all terms, so we factored it out right away, resulting in:

\[y = x(x^2 - 4x - 5)\]

Next, the quadratic \( x^2 - 4x - 5 \) needs factoring. We need two numbers that multiply to -5 and add up to -4. These numbers are -5 and 1, simplifying our polynomial further to:

\[y = x(x - 5)(x + 1)\]

Factoring makes intercept-finding more manageable by simplifying the original equation and directly exposing the roots, which are critical for graphing and analysis in calculus and beyond.
graphical analysis
Graphical analysis involves understanding what the plot of a particular function represents on the Cartesian plane. For our polynomial function \( y = x^3 - 4x^2 - 5x \), we start with key points like intercepts and analyze the behavior between these points.

This polynomial is of degree three, indicating it’s a cubic function. Such functions typically have one or two turning points, much like this one, where the curve changes direction once. Analyzing its end behavior, it begins by going down to the left and moves upwards to the right, crossing the x-axis at \( x = -1 \), \( x = 0 \), and \( x = 5 \).

During graphical analysis, intercepts serve as critical checkpoints. Also, since there are no excluded regions (polynomials are defined for all real numbers), the graph is continuous. Understanding these function properties aids in crafting a precise, intuitive graph that reflects the full story of the equation on paper.

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Most popular questions from this chapter

By completing the square, show that the coordinates of the vertex of the parabola \(y=a x^{2}+b x+c\) are \((-b / 2 a,-D / 4 a),\) where \(D=b^{2}-4 a c\).

(a) Determine the \(x\) - and \(y\) -intercepts and the excluded regions for the graph of the given function. Specify your results using a sketch similar to Figure \(16(a) .\) In Exercises \(31-34\) you will first need to factor the polynomial. (b) Graph each function. $$y=x^{3}+3 x^{2}-4 x-12$$

The following table and scatter plot show global coal consumption for the years \(1990-1995\). $$\begin{array}{cc} \hline \text { Year } x & \text { Coal consumption } y \\ \hline x=0 \leftrightarrow 1990 & \text { (billion tons) } \\ \hline 0 & 3.368 \\ 1 & 3.285 \\ 2 & 3.258 \\ 3 & 3.243 \\ 4 & 3.261 \\ 5 & 3.311 \\ \hline \end{array}$$ (GRAPH CAN'T COPY) (a) Use a graphing utility to find a quadratic model for the data. Then use the model to make estimates for global coal consumption in 1989 and 1996 (b) Use the following information to show that, in terms of percentage error, the 1996 estimate is better than the 1989 estimate, but in both cases the percentage error is less than \(2 \% .\) The actual figures for coal consumption in 1989 and 1996 are 3.408 and 3.428 billion tons, respectively. (c) Use the model to project worldwide coal consumption in \(1998 .\) Then show that the percentage error is more than \(9 \%,\) given that the actual 1998 consumption was 3.329 billion tons.

(a) Determine the \(x\) - and \(y\) -intercepts and the excluded regions for the graph of the given function. Specify your results using a sketch similar to Figure \(16(a) .\) In Exercises \(31-34\) you will first need to factor the polynomial. (b) Graph each function. $$y=x^{3}-5 x^{2}-x+5$$

Graph the functions. Note: In each case, the graph crosses its horizontal asymptote once. To find the point where the rational function \(y=f(x)\) crosses its horizontal asymptote \(y=k,\) you \(1 /\) need to solve the equation \(f(x)=k\). $$y=\frac{(x-1)(x-3)}{(x+1)^{2}}$$

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