/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 50 $$\text { Let } k(x)=5 x^{3}+\fr... [FREE SOLUTION] | 91Ó°ÊÓ

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$$\text { Let } k(x)=5 x^{3}+\frac{5}{x^{3}}-x-\frac{1}{x} . \text { Show that } k(x)=k(1 / x)$$

Short Answer

Expert verified
The function \( k(x) = 5x^3 + \frac{5}{x^3} - x - \frac{1}{x} \) is equal to its reciprocal function \( k\left(\frac{1}{x}\right) \).

Step by step solution

01

Understand the Problem

We need to prove that the function \( k(x) = 5x^3 + \frac{5}{x^3} - x - \frac{1}{x} \) is equal to \( k\left(\frac{1}{x}\right) \). This means substituting \( \frac{1}{x} \) into the function and ensuring the expression simplifies back to \( k(x) \).
02

Substitute \( \frac{1}{x} \) into the Function

Replace every \( x \) in the original function \( k(x) \) with \( \frac{1}{x} \). This gives: \[ k\left(\frac{1}{x}\right) = 5\left(\frac{1}{x}\right)^3 + \frac{5}{\left(\frac{1}{x}\right)^3} - \frac{1}{x} - x \]
03

Simplify the Expression

Simplify the expression for \( k\left(\frac{1}{x}\right) \):- \( 5\left(\frac{1}{x}\right)^3 = \frac{5}{x^3} \).- \( \frac{5}{\left(\frac{1}{x}\right)^3} = 5x^3 \).- \( -\frac{1}{x} \) remains as it is.- Replace \( -x \) with \( -x \).Thus, the expression becomes: \[ k\left(\frac{1}{x}\right) = \frac{5}{x^3} + 5x^3 - \frac{1}{x} - x \]
04

Compare \( k(x) \) and \( k\left(\frac{1}{x}\right) \)

The expression for \( k(x) \) is: \[ 5x^3 + \frac{5}{x^3} - x - \frac{1}{x} \]and the expression for \( k\left(\frac{1}{x}\right) \) we simplified to is: \[ 5x^3 + \frac{5}{x^3} - x - \frac{1}{x} \].Both expressions are identical, which proves that \( k(x) = k\left(\frac{1}{x}\right) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial functions
A polynomial function is an expression that involves only the arithmetic operations of addition, subtraction, multiplication, and non-negative integer exponents of variables. They are significant in mathematics due to their versatility in modeling various real-world situations and their profound properties such as symmetry. In this exercise, the given function, \( k(x) = 5x^3 + \frac{5}{x^3} - x - \frac{1}{x} \), combines polynomial terms and terms with reciprocal powers, highlighting that polynomial-type expressions can extend to functions involving reciprocal powers while still retaining specific algebraic properties. Polynomial functions are generally continuous and differentiable, which makes them crucial for both theoretical mathematics and practical applications.
Function symmetry
Function symmetry pertains to a situation where a function exhibits mirrored properties. The symmetry displayed in the problem reflects what is known as reciprocal symmetry. Specifically, this dictates that for the function \( k(x) \), swapping \( x \) with \( \frac{1}{x} \) yields the same functional output without affecting the overall expression. In simpler terms, for every value of \( x \), the transformation \( k(\frac{1}{x}) \) results in the same outcome as the original function \( k(x) \). This particular kind of symmetry shows a relationship in the function that is equivalent across different representations. Identifying symmetry helps simplify complex evaluations of functions and enables deeper insights into their structural properties.
Algebraic manipulation
Algebraic manipulation involves rearranging and simplifying expressions to find equivalent formulations or solve equations. In the exercise at hand, algebraic manipulation is key to proving \( k(x) = k(\frac{1}{x}) \). By substituting \( \frac{1}{x} \) into the function and applying rules of exponents, we can simplify the function step by step:
  • Recognize that raising reciprocal to the power results in obtaining reciprocal terms: \( \left(\frac{1}{x}\right)^3 = \frac{1}{x^3} \).
  • Simplify the coefficient multiplications: \( 5\left(\frac{1}{x}\right)^3 = \frac{5}{x^3} \) and \( \frac{5}{\left(\frac{1}{x}\right)^3} = 5x^3 \).
  • Keep other terms consistent, ensuring the algebraic transformation remains valid without altering the sign or the position: \(-\frac{1}{x}\) and \(-x\) stay the same.
Ultimately, through precise manipulation, the expressions \( k(x) \) and \( k\left(\frac{1}{x}\right) \) are both effectively simplified to be equal, evidencing the symmetry using straightforward algebra.

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Most popular questions from this chapter

(a) Find the difference quotient \(\frac{f(x)-f(a)}{x-a}\) for each function, as in Example 4. (b) Find the difference quotient \(\frac{f(x+h)-f(x)}{h}\) for each function, as in Example \(5 .\) $$f(x)=1-x^{3}$$

A function \(f\) is given. Say how the graph of each of the related functions can be obtained from the graph of \(f\), and then use a graphing utility to verify your statement (as in Figure 11 ). \(f(x)=x^{3}+3 x^{2}-4\) (a) \(y=-x^{3}+3 x^{2}-4\) (b) \(y=-x^{3}+3 x^{2}+1\)

\(\pi=3.141592653589793 \ldots\) and so on! For each natural number \(n,\) let \(G(n)\) be the digit in the \(n\) th decimal place of \(\pi .\) For instance, according to the expression for \(\pi\) given above, we have \(G(1)=1, G(2)=4,\) and \(G(5)=9\) (a) Use the expression for \(\pi\) given above to evaluate \(G(10)\) and \(G(14)\) (b) Use the Internet to help you evaluate \(G(100), G(750)\) and \(G(1000) .\) Suggestions: Using any of the common search engines on the World Wide Web, under the categories of mathematics or science, search for "pi." Here, for example, are two sites that contain the information you need. (They were accessible at the time of this writing, March 2004 .)

The \(3 x+1\) conjecture Define a function \(f,\) with domain the positive integers, as follows: $$f(x)=\left\\{\begin{array}{ll} 3 x+1 & \text { if } x \text { is odd } \\ x / 2 & \text { if } x \text { is even } \end{array}\right.$$ (a) Compute \(f(1), f(2), f(3), f(4), f(5),\) and \(f(6)\) (b) Compute the first three iterates of \(x_{0}=1\) (c) Compute the iterates of \(x_{0}=3\) until you obtain the value \(1 .\) [After this, the iterates will recycle through the simple pattern obtained in part (b). \(]\) (d) The \(3 x+1\) conjecture asserts that for any positive integer \(x_{0}\), the iterates eventually return to the value \(1 .\) Verify that this conjecture is valid for each of the following values of \(x_{0}: 2,4,5,6,\) and 7 Remark: At present, the \(3 x+1\) conjecture is indeed a conjecture, not a theorem. No one yet has found a proof that the assertion is valid for every positive integer. Computer checks, however, have verified the conjecture on a case-by-case basis for very large values of \(x_{0}\) As of April 2000, the conjecture had been verified for all values of \(x_{0}\) up to approximately \(1.8 \times 10^{16}\).

Use a graphing utility to graph each function and then apply the horizontal line test to see whether the function is one-to-one. $$y=x^{3}+2 x$$

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