/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 Use the given function and compu... [FREE SOLUTION] | 91Ó°ÊÓ

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Use the given function and compute the first six iterates of each initial input \(x_{0}\). In cases in which a calculator answer contains four or more decimal places, round the final answer to three decimal places. (However, during the calculations, work with all of the decimal places that your calculator affords.) \(g(x)=2 x+1\) (a) \(x_{0}=-2\) (b) \(x_{0}=-1\) (c) \(x_{0}=1\)

Short Answer

Expert verified
Iterates: (a) -2, -3, -5, -9, -17, -33, -65; (b) -1, -1, -1, -1, -1, -1; (c) 1, 3, 7, 15, 31, 63, 127.

Step by step solution

01

Understand the Function

The given function is \( g(x) = 2x + 1 \). This implies that for any input \( x \), the output is calculated by doubling \( x \) and then adding 1 to the result.
02

Determine Initial Values

We are given three different initial values: \( x_{0} = -2 \), \( x_{0} = -1 \), and \( x_{0} = 1 \). We need to calculate the first six iterates for each initial value.
03

Iteration for \( x_{0} = -2 \)

Starting with \( x_{0} = -2 \):- \( x_1 = g(-2) = 2(-2) + 1 = -3 \)- \( x_2 = g(-3) = 2(-3) + 1 = -5 \)- \( x_3 = g(-5) = 2(-5) + 1 = -9 \)- \( x_4 = g(-9) = 2(-9) + 1 = -17 \)- \( x_5 = g(-17) = 2(-17) + 1 = -33 \)- \( x_6 = g(-33) = 2(-33) + 1 = -65 \)
04

Iteration for \( x_{0} = -1 \)

Starting with \( x_{0} = -1 \):- \( x_1 = g(-1) = 2(-1) + 1 = -1 \)- \( x_2 = g(-1) = 2(-1) + 1 = -1 \)- Continuing this pattern, all further \( x_n \) for \( n \geq 1 \) will be \(-1\).- Thus, the sequence stabilizes at \(-1\) for \( x_3, x_4, x_5, \) and \( x_6 \).
05

Iteration for \( x_{0} = 1 \)

Starting with \( x_{0} = 1 \):- \( x_1 = g(1) = 2(1) + 1 = 3 \)- \( x_2 = g(3) = 2(3) + 1 = 7 \)- \( x_3 = g(7) = 2(7) + 1 = 15 \)- \( x_4 = g(15) = 2(15) + 1 = 31 \)- \( x_5 = g(31) = 2(31) + 1 = 63 \)- \( x_6 = g(63) = 2(63) + 1 = 127 \)
06

Conclude the Iterations

To summarize:- For \( x_{0} = -2 \), the iterates are \(-2, -3, -5, -9, -17, -33, -65\).- For \( x_{0} = -1 \), the iterates stabilize at \(-1, -1, -1, -1, -1, -1\).- For \( x_{0} = 1 \), the iterates are \(1, 3, 7, 15, 31, 63, 127\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Iteration
Function iteration is a repeated application of a function to an initial value. Imagine it like applying a recipe over and over to the outcome of the previous recipe. For example, in this exercise, we work with the linear function \( g(x) = 2x + 1 \). Starting from an initial value, you calculate successive outputs, each time taking the result from the previous step as the new input. This process continues iteratively, meaning step by step, calculating the first six outputs (or iterates) for each initial value given.When starting with, say, \( x_0 = -2 \), the first calculation involves plugging \( -2 \) into \( g(x) \) to find \( x_1 \). Then, \( x_1 \) becomes the input for finding \( x_2 \), and so forth. Hence, function iteration is crucial in scenarios where determined patterns or fixed points (like in the \( x_0 = -1 \) example) can emerge and provide meaningful insights into how functions behave and evolve over repeated applications.
Precalculus Problems
Precalculus problems often involve understanding and applying foundational concepts in mathematics that prepare students for calculus. This function iteration exercise is a classic example of a precalculus problem because it reinforces familiarity with algebra, recursion, and sequences. • **Algebraic manipulation**: As seen with \( g(x) = 2x + 1 \), you'll practice working with functions and operations like multiplying and adding, which are core algebra skills.• **Sequences and patterns**: Iterative processes help you recognize patterns and form sequences based on repeated calculations, like the series of numbers you get for each initial input.Understanding how sequences arise through iteration helps build a bridge to calculus, where limits and convergence are key concepts, stressing the importance of grasping these iterative processes now.
Numerical Methods
Numerical methods are mathematical techniques used to approximate solutions where exact solutions are difficult or impossible to find. Although this exercise doesn't necessarily delve into complex numerical methods, the iterative process used here is foundational to many numerical techniques, as iterative processes often form the backbone of numerical methods. Many real-world problems require numerical solutions due to complex functions beyond simple analytical solving. For instance, Newton's method for finding roots incorporates iteration much like the function iteration shown here. By applying a function repeatedly, we approximate solutions step by step until we reach a desired level of accuracy or stability.This exercise provides a simple insight into such processes. As you iterate with \( g(x) \), you mimic the approach taken by numerical methods in finding complex solutions and gaining insights into function behaviors that are analytically infeasible to explore directly.

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Most popular questions from this chapter

Assume that the domain of fand \(f^{-1}\) is \((-\infty, \infty) .\) Solve the equation for \(x\) or for \(t\) (whichever is appropriate ) using the given information. $$f^{-1}\left(\frac{t+1}{t-2}\right)=12 ; f(12)=13$$

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Suppose that an oil spill in a lake covers a circular area and that the radius of the circle is increasing according to the formula \(r=f(t)=15+t^{1.65},\) where \(t\) represents the number of hours since the spill was first observed and the radius \(r\) is measured in meters. (Thus when the spill was first discovered, \(t=0 \mathrm{hr}\), and the initial radius was \(\left.r=f(0)=15+0^{1.65}=15 \mathrm{~m} .\right)\) (a) Let \(A(r)=\pi r^{2},\) as in Example \(5 .\) Compute a table of values for the composite function \(A \circ f\) with \(t\) running from 0 to 5 in increments of \(0.5 .\) (Round each output to the nearest integer.) Then use the table to answer the questions that follow in parts (b) through (d). (b) After one hour, what is the area of the spill (rounded to the nearest \(10 \mathrm{~m}^{2}\) )? (c) Initially, what was the area of the spill (when \(t=0\) )? Approximately how many hours does it take for this area to double? (d) Compute the average rate of change of the area of the spill from \(t=0\) to \(t=2.5\) and from \(t=2.5\) to \(t=5\). Over which of the two intervals is the area increasing faster?

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