/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 A spherical weather balloon is b... [FREE SOLUTION] | 91Ó°ÊÓ

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A spherical weather balloon is being inflated in such a way that the radius is given by $$r=g(t)=\frac{1}{2} t+2$$ Assume that \(r\) is in meters and \(t\) is in seconds, with \(t=0\) corresponding to the time that inflation begins. If the volume of a sphere of radius \(r\) is given by $$V(r)=\frac{4}{3} \pi r^{3}$$ compute \(V[g(t)]\) and use this to find the time at which the volume of the balloon is \(36 \pi \mathrm{m}^{3}\).

Short Answer

Expert verified
The volume is 36\(\pi\) m³ when \(t = 2\) seconds.

Step by step solution

01

Substitute for Radius Function

To compute the volume as a function of time, first substitute the radius function \(g(t)\) into the volume formula. The radius is given by \(r = g(t) = \frac{1}{2} t + 2\). Plugging this into the volume formula gives \(V[g(t)] = \frac{4}{3} \pi (\frac{1}{2} t + 2)^3\).
02

Simplify the Expression

Simplify the expression \((\frac{1}{2} t + 2)^3\). This involves expanding the binomial. Using the binomial theorem or expansion rules: \((\frac{1}{2} t + 2)^3 = (\frac{1}{2} t + 2)(\frac{1}{2} t + 2)(\frac{1}{2} t + 2)\). Do this step-by-step to get: \[(\frac{1}{2} t + 2)^3 = (\frac{1}{4} t^2 + 2t + 4)(\frac{1}{2} t + 2)\].
03

Compute Volume Function

Expand the expression further to find the volume: Multiply out the terms \((\frac{1}{4} t^2 + 2t + 4)(\frac{1}{2} t + 2)\). This results in:\[V[g(t)] = \frac{4}{3} \pi (\frac{1}{8} t^3 + \frac{3}{2} t^2 + 6t + 8)\], which simplifies to: \[V[g(t)] = \frac{4}{3} \pi (\frac{1}{8} t^3 + \frac{3}{2} t^2 + 6t + 8)\].
04

Solve for Specific Volume

Set the volume equation equal to 36\(\pi\) to find the time when the volume is \(36\pi\). Solve: \[\frac{4}{3} \pi (\frac{1}{8} t^3 + \frac{3}{2} t^2 + 6t + 8) = 36 \pi\].
05

Cancel \(\pi\) and Solve for \(t\)

Divide both sides by \(\pi\) and simplify so the equation becomes: \[\frac{4}{3} (\frac{1}{8} t^3 + \frac{3}{2} t^2 + 6t + 8) = 36\]. Multiply through by \(\frac{3}{4}\) to simplify further: \[\frac{1}{8} t^3 + \frac{3}{2} t^2 + 6t + 8 = 27\].
06

Rearrange and Solve the Cubic Equation

Rearrange the equation to: \[\frac{1}{8} t^3 + \frac{3}{2} t^2 + 6t - 19 = 0\]. Multiply through by 8 to clear the fraction: \[t^3 + 12t^2 + 48t - 152 = 0\]. Solve this cubic equation for \(t\) using substitution, factorizations, or numerical methods. The solution is \(t = 2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spherical Geometry
Spherical geometry is an exciting branch of mathematics dealing with the properties and shapes of spheres. Unlike flat surfaces, spherical geometry explores how circles and angles behave on curved surfaces and helps us understand volume and surface area. A sphere is a perfectly round 3-dimensional object where every point on its surface is equidistant from its center. In the context of this problem, a weather balloon represents a sphere whose geometry is used to calculate its volume. Spherical shapes are smooth and do not have boundaries, unlike polygons. This property makes calculations like volume distinctively different from shapes like cubes or pyramids, due to the curvature factor.
Volume of Spheres
Calculating the volume of spheres is crucial in determining how much space is enclosed within its surface. The formula for the volume of a sphere is \(V = \frac{4}{3} \pi r^3\).
  • Here, \(V\) stands for volume.
  • \(\pi\) is a constant approximately equal to 3.14159.
  • \(r\) represents the radius of the sphere.
    The radius is the distance from the center of the sphere to any point on its surface.
    This formula is derived using integral calculus concepts, as a sphere can be viewed as a set of infinitesimally small disks stacked on top of each other.
In our exercise, as the radius changes with time, the plastic balloon's volume also changes. Therefore, to find out how much volume the balloon occupies at a specific time, it is necessary to substitute the time-dependent expression for the radius into this formula.
Function Substitution
Function substitution is a common strategy in calculus when a variable within a function is itself a function of another variable. To solve our problem, we substitute the expression for the radius \(r = g(t) = \frac{1}{2}t + 2\) into the sphere's volume formula. By substituting, we effectively express the volume of the balloon as a function of time, \(V[g(t)] = \frac{4}{3} \pi \left(\frac{1}{2} t + 2\right)^3\).
  • This allows us to track how the volume evolves over time as changes occur with \(t\).
  • Substitution simplifies computations in this context, linking geometric properties directly with time.
This method is incredibly useful in calculus and helps model real-world situations where parameters change, such as inflation of balloons, cooling of objects, or population growth.
Cubic Equations
Cubic equations are algebraic equations where the highest degree of the variable is three, expressed generally as \(ax^3 + bx^2 + cx + d = 0\). In our context, after simplifying the volume function in terms of \(t\), we are tasked with solving the cubic equation derived: \(t^3 + 12t^2 + 48t - 152 = 0\).
Solving for \(t\), involves:
  • Rearranging and simplifying equations, often by removing fractions.
  • Various methods such as factoring, graphing, or using the Rational Root Theorem are applied to find exact or approximate solutions.
  • Sometimes numerical approximations, like Newton's method, are used if an analytical solution is challenging.
In this problem, simplifying and finding rational roots ultimately showed that the solution \(t = 2\) solves the equation, indicating when the balloon reaches the specified volume.

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Most popular questions from this chapter

In this exercise you'll investigate the inverse of a composite function. In parts (b) and (c), which involve graphing, be sure to use the same size unit and scale on both axes so that symmetry about the line \(y=x\) can be checked visually. (a) Let \(f(x)=2 x+1\) and \(g(x)=\frac{1}{4} x-3 .\) Compute each of the following: (i) \(f(g(x))\) \(g^{-1}(x)\) (ii) \(g(f(x))\) (v) \(f^{-1}\left(g^{-1}(x)\right)\) (iii) \(f^{-1}(x)\) (vi) \(g^{-1}\left(f^{-1}(x)\right)\) (b) On the same set of axes, graph the two answers that you obtained in (i) and (v) of part (a). Note that the graphs are not symmetric about \(y=x .\) The conclusion here is that the inverse function for \(f(g(x))\) is not \(f^{-1}\left(g^{-1}(x)\right)\) (c) On the same set of axes, graph the two answers that you obtained in (i) and (vi) of part (a); also put the line\(y=x\) into the picture. Note that the two graphs are symmetric about the line \(y=x .\) The conclusion here is that the inverse function for \(f(g(x))\) is \(g^{-1}\left(f^{-1}(x)\right)\) In fact, it can be shown that this result is true in general. For reference, then, we summarize this fact about the inverse of a composite function in the box that follows.

A function \(f\) is given. Say how the graph of each of the related functions can be obtained from the graph of \(f\), and then use a graphing utility to verify your statement (as in Figure 11 ). \(f(x)=x^{3}+3 x^{2}-4\) (a) \(y=-x^{3}+3 x^{2}-4\) (b) \(y=-x^{3}+3 x^{2}+1\)

Let \(f(x)=\frac{x-3}{x+c},\) where \(c\) denotes a constant. (a) If \(c=-1,\) show that \(f(f(x))=x\) (b) Use a graphing utility to support the result in part (a). That is, enter the function \(f(x)=\frac{x-3}{x-1},\) and then have the machine graph the two functions \(y=x\) and \(y=f(f(x))\) in the same picture. (c) What does the result in part (a) tell you about the iteration process for the function \(y=(x-3) /(x-1) ?\) That is, what pattern emerges in the iterates? Answer in complete sentences. (d) Now assume \(c=1,\) instead of \(-1 .\) Show that \(f(f(f(x)))=x\). (e) Use a graphing utility to support the result in part (d). (f) What does the result in part (d) tell you about the iteration process for the function \(y=(x-3) /(x+1) ?\) That is, what pattern emerges in the iterates? Answer in complete sentences.

Let \(g(t)=(4 t-6) /(t-4)\). In each case, tind all the real number solutions (if any) for the given equation. (a) \(g(t)=14\) (b) \(g(t)=4\) (c) \(g(t)=0\)

(a) Find the difference quotient \(\frac{f(x)-f(a)}{x-a}\) for each function, as in Example 4. (b) Find the difference quotient \(\frac{f(x+h)-f(x)}{h}\) for each function, as in Example \(5 .\) $$f(x)=-3 / x^{2}$$

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