/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 The domain of a function \(f\) c... [FREE SOLUTION] | 91Ó°ÊÓ

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The domain of a function \(f\) consists of the numbers -1, 0, 1, 2, and 3. The following table shows the output that \(f\) assigns to each input. $$\begin{array}{llllll} \hline x & 1 & 0 & 1 & 2 & 3 \\ f(x) & 2 & 2 & 0 & 3 & 1 \\ \hline \end{array}$$ The domain of a function \(g\) consists of the numbers 0, 1, 2, 3 and 4. The following table shows the output that \(g\) assigns to each input. $$\begin{array}{llllll} \hline x & 0 & 1 & 2 & 3 & 4 \\ g(x) & 3 & 2 & 0 & 4 & -1 \\ \hline \end{array}$$ Use this information to complete the following tables for \(f \circ g\) and \(g \circ f .\) Note: Two of the entries will be undefined. $$\begin{array}{llllll} \hline x & 0 & 1 & 2 & 3 & 4 \\ \hline(f \circ g)(x) & & & & & \\ \hline \end{array}$$ $$\begin{array}{lllllll} \hline x & -1 & 0 & 1 & 2 & 3 & 4 \\ \hline(g \circ f)(x) & & & & & & \\ \hline \end{array}$$

Short Answer

Expert verified
\((f \circ g)(x) = [1, 3, 2, \text{undefined}, 2]\) and \((g \circ f)(x) = [0, 0, 3, 4, 2, \text{undefined}]\).

Step by step solution

01

Calculate \( (f \circ g)(0) \)

First, find \( g(0) \) from the table of function \( g \), which gives us \( g(0) = 3 \). Next, substitute \( 3 \) into function \( f \): \( f(3) = 1 \). So, \( (f \circ g)(0) = 1 \).
02

Calculate \( (f \circ g)(1) \)

Find \( g(1) \) from the table of function \( g \), which is \( g(1) = 2 \). Then, find \( f(2) \) from the table of function \( f \), which is \( f(2) = 3 \). Therefore, \( (f \circ g)(1) = 3 \).
03

Calculate \( (f \circ g)(2) \)

First, find \( g(2) \) which gives \( g(2) = 0 \). Then, substitute \( 0 \) into function \( f \): \( f(0) = 2 \). Thus, \( (f \circ g)(2) = 2 \).
04

Calculate \( (f \circ g)(3) \)

Find \( g(3) \) from the table of function \( g \), which is \( g(3) = 4 \). However, \( f(4) \) is undefined because \( f \) is only defined for \(-1, 0, 1, 2,\) and \(3\). Thus, \( (f \circ g)(3) = \text{undefined} \).
05

Calculate \( (f \circ g)(4) \)

Find \( g(4) \) which is \(-1 \). Then, get \( f(-1) \) from the table of \( f \), giving \( f(-1) = 2 \). Therefore, \( (f \circ g)(4) = 2 \).
06

Calculate \( (g \circ f)(-1) \)

First, find \( f(-1) \) which is \( 2 \). Then, substitute into \( g \): \( g(2) = 0 \). Therefore, \( (g \circ f)(-1) = 0 \).
07

Calculate \( (g \circ f)(0) \)

Find \( f(0) \), which is \( 2 \). Then \( g(2) = 0 \). Thus, \( (g \circ f)(0) = 0 \).
08

Calculate \( (g \circ f)(1) \)

Find \( f(1) \), which is \( 0 \). Then \( g(0) = 3 \). Thus, \( (g \circ f)(1) = 3 \).
09

Calculate \( (g \circ f)(2) \)

Find \( f(2) \) which is \( 3 \). Then \( g(3) = 4 \). So, \( (g \circ f)(2) = 4 \).
10

Calculate \( (g \circ f)(3) \)

Find \( f(3) \), which is \( 1 \). Then \( g(1) = 2 \). Thus, \( (g \circ f)(3) = 2 \).
11

Calculate \( (g \circ f)(4) \)

Function \( f \) is undefined for \( 4 \) because \( 4 \) is not in the domain of \( f \). Therefore, \( (g \circ f)(4) = \text{undefined} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain of a Function
The **domain of a function** refers to all the possible input values that a function can accept. For example, if you think about feeding your pet only certain foods, the domain is like the list of acceptable foods you can give to your pet. In a mathematical function, the domain includes all the values of \( x \) for which the function is defined.

Let's look at function \( f \) from our exercise. Its domain consists of the numbers
  • -1
  • 0
  • 1
  • 2
  • 3
These are the only inputs for which we can calculate \( f(x) \). Similarly, the domain of function \( g \) consists of
  • 0
  • 1
  • 2
  • 3
  • 4
Understanding the domain is crucial because if you try to use a value outside of this set, like trying to find \( f(4) \), it would be like trying to feed your pet chocolate—it's just not allowed.

When composing functions, the domain of the composite function \( f \circ g \) is determined by the domain of \( g \) but further restricted by the domain of \( f \). This means \( (f \circ g)(x) \) is only defined if \( g(x) \) is a part of the domain of \( f \). This is important for ensuring that every step of function composition works smoothly.
Range of a Function
The **range of a function** is the set of all possible outputs. Just like the domain tells us where we can start, the range tells us where we can end up. Think of it like the destinations you can reach with the vehicles available to you. With a function, this is the collection of values \( f(x) \) can take.

For instance, in the table for function \( f \), we have outputs:
  • 2
  • 0
  • 3
  • 1
This is the range of \( f \). Similarly, the range of function \( g \) includes
  • 3
  • 2
  • 0
  • 4
  • -1
In the context of composing functions like \( f \circ g \), the range of the final composition also depends on the range of \( g \) and how those outputs fit into the domain of \( f \).

By understanding both functions’ domains and ranges, you'll see how the composite function only allows certain outputs, reflected in the composite function's range.
Undefined Values in Functions
**Undefined values in functions** occur when an operation in a function doesn't result in a valid real number outcome. It's like trying to read a GPS map for a foreign city without an internet connection—you're missing essential details! In mathematics, something is undefined if it doesn't produce a meaningful result based on the given domain and operation conditions.

In our exercise, when we compute \( (f \circ g)(3) \), we see that \( g(3) = 4 \). However, when we try to find \( f(4) \), it becomes undefined because 4 isn't in the domain of \( f \). Similarly, for \( g \circ f \), \( f(4) \) is undefined, making \( (g \circ f)(4) \) undefined as well.

This highlights the importance of respecting a function's domain and range to avoid undefined values. If an input or output steps outside the function's boundaries, the result is undefined. Remember to always check these limitations to know when a function might fail to provide a valid result.

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Most popular questions from this chapter

Use the given function and compute the first six iterates of each initial input \(x_{0}\). In cases in which a calculator answer contains four or more decimal places, round the final answer to three decimal places. (However, during the calculations, work with all of the decimal places that your calculator affords.) \(G(x)=x^{2}+0.25\) (a) \(x_{0}=0.4\) (b) \(x_{0}=0.5\) (c) \(x_{0}=0.6\)

In this exercise you'll investigate the inverse of a composite function. In parts (b) and (c), which involve graphing, be sure to use the same size unit and scale on both axes so that symmetry about the line \(y=x\) can be checked visually. (a) Let \(f(x)=2 x+1\) and \(g(x)=\frac{1}{4} x-3 .\) Compute each of the following: (i) \(f(g(x))\) \(g^{-1}(x)\) (ii) \(g(f(x))\) (v) \(f^{-1}\left(g^{-1}(x)\right)\) (iii) \(f^{-1}(x)\) (vi) \(g^{-1}\left(f^{-1}(x)\right)\) (b) On the same set of axes, graph the two answers that you obtained in (i) and (v) of part (a). Note that the graphs are not symmetric about \(y=x .\) The conclusion here is that the inverse function for \(f(g(x))\) is not \(f^{-1}\left(g^{-1}(x)\right)\) (c) On the same set of axes, graph the two answers that you obtained in (i) and (vi) of part (a); also put the line\(y=x\) into the picture. Note that the two graphs are symmetric about the line \(y=x .\) The conclusion here is that the inverse function for \(f(g(x))\) is \(g^{-1}\left(f^{-1}(x)\right)\) In fact, it can be shown that this result is true in general. For reference, then, we summarize this fact about the inverse of a composite function in the box that follows.

(a) Find the difference quotient \(\frac{f(x)-f(a)}{x-a}\) for each function, as in Example 4. (b) Find the difference quotient \(\frac{f(x+h)-f(x)}{h}\) for each function, as in Example \(5 .\) $$f(x)=1-x^{3}$$

Let \(g(t)=|t-4| .\) Find \(g(3) .\) Find \(g(x+4)\)

Let \(a(x)=1 / x, b(x)=\sqrt[3]{x}, c(x)=2 x+1,\) and \(d(x)=x^{2}\). Express each of the following functions as a composition of two of the given functions. (a) \(f(x)=\sqrt[3]{2 x+1}\) (d) \(K(x)=2 \sqrt[3]{x}+1\) (b) \(g(x)=1 / x^{2}\) (e) \(l(x)=\frac{2}{x}+1\) (c) \(h(x)=2 x^{2}+1\) (f) \(m(x)=\frac{1}{2 x+1}\)

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