/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 Determine all of the real-number... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine all of the real-number solutions for each equation. (Remember to check for extraneous solutions.) $$\sqrt{1-3 x}=2$$

Short Answer

Expert verified
The solution is \( x = -1 \).

Step by step solution

01

Remove the square root

To eliminate the square root in the equation \( \sqrt{1-3x} = 2 \), square both sides. This gives us: \[ \left( \sqrt{1-3x} \right)^2 = 2^2 \] which simplifies to: \[ 1 - 3x = 4 \]
02

Isolate the variable

Rearrange the equation to solve for \(x\). Start by moving \(1\) to the other side by subtracting it: \[ -3x = 4 - 1 \] This simplifies to: \[ -3x = 3 \] Next, divide both sides by \(-3\) to isolate \(x\): \[ x = \frac{3}{-3} \] Simplify the fraction to find: \[ x = -1 \]
03

Check for extraneous solutions

Substitute \(x = -1\) back into the original equation to ensure it is a valid solution: \[ \sqrt{1 - 3(-1)} = \sqrt{1 + 3} = \sqrt{4} = 2 \] Since the left-hand side equals the right-hand side, \(x = -1\) is a valid solution.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Equations
Solving equations is like solving a puzzle where you try to find the value of the unknown, usually denoted as \( x \). In the given exercise, the unknown is buried inside a square root, making it a bit trickier. To solve the equation \( \sqrt{1-3x} = 2 \), the first move is to eliminate the square root.
This typically involves squaring both sides of the equation. By doing this, the square root on the left is "undone," simplifying the equation to a more manageable form: \( 1 - 3x = 4 \). With the square root gone, you are left with a linear equation.
\
Next, isolate \( x \) by performing arithmetic operations. Subtract \( 1 \) from both sides, then divide by \(-3\) to solve for \( x \). Always remember the goal: you want to get \( x \) by itself on one side of the equation so you know exactly what value it takes. This systematic method is key to solving most algebraic equations.
Extraneous Solutions
Extraneous solutions can pop up when dealing with equations involving square roots or other functions that aren't one-to-one. But, what exactly are extraneous solutions? They are solutions that seem correct when you solve mathematically, but don't actually satisfy the original equation.
In our exercise, after squaring both sides to eliminate the square root, it might appear like any \( x \) found would be a valid solution. However, it's vital to check each potential answer by substituting it back into the original equation. This ensures the left-hand side equals the right-hand side, confirming its validity.
In this case, plugging \( x = -1 \) back into the original equation results in \( \sqrt{4} = 2 \), which is true. Thus, \( x = -1 \) is not extraneous, but a valid solution. Always conduct this critical last step to validate your answers.
Square Root Equations
Square root equations involve finding unknowns that are locked inside a square root. The main challenge here is to get rid of the square root so that you can solve for the variable straight forward.
The common method, as seen in our example, is to square both sides of the equation. This allows you to remove the square root and simplify the problem. However, it's crucial to remember that squaring both sides can introduce extraneous solutions. Why does this happen? Because squaring eliminates any sign, it might falsely imply some numbers fit the equation when they don't actually satisfy the original condition.
Always go back to check if the solution still holds true when substituted into the original equation. This double-check ensures that you haven't caught an extraneous solution in your process, preserving the integrity of your mathematical solution.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Solve each equation. \(\sqrt{x^{2}+3 x-4}-\sqrt{x^{2}-5 x+4}=x-1,\) where \(x>4\) Hint: Factor the expressions beneath the radicals. Then note that \(\sqrt{x-1}\) is a factor of both sides of the equation.

Solve each equation. $$\begin{aligned} &\sqrt{x^{2}-x-1}-\frac{2}{\sqrt{x^{2}-x-1}}=1\\\ &\text { Hint: Let } t=x^{2}-x-1 \end{aligned}$$

Hint: Let \(t=x^{2}-x-1\) \(\sqrt{\frac{x-a}{x}}+4 \sqrt{\frac{x}{x-a}}=5,\) where \(a \neq 0\) Hint: Let \(t=\frac{x-a}{x} ;\) then \(\frac{1}{t}=\frac{x}{x-a}\)

In the United States over the years \(1980-2000\), sulfur dioxide emissions due to the burning of fossil fuels can be approximated by the equation $$y=-0.4743 t+24.086$$ where \(y\) represents the sulfur dioxide emissions (in millions of tons) for the year \(t\), with \(t=0\) corresponding to \(1980 .\) Source: This equation (and the equation in Exercise 48) were computed using data from the book Vital Signs 1999 Lester Brown et al. (New York: W. W. Norton \& \(\mathrm{Co} ., 1999\) ). (a) Use a graphing utility to graph the equation \(y=-0.4743 t+24.086\) in the viewing rectangle [0,25,5] by \([0,30,5] .\) According to the graph, sulfur dioxide emissions are decreasing. What piece of information in the equation \(y=-0.4743 t+24.086\) tells you this even before looking at the graph? (b) Assuming this equation remains valid, estimate the year in which sulfur dioxide emissions in the United States might fall below 10 million tons per year. (You need to solve the inequality \(-0.4743 t+24.086 \leq 10 .)\)

Solve the inequalities Suggestion: A calculator may be useful for approximating key numbers. $$20 \geq x^{2}\left(9-x^{2}\right)$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.