Chapter 2: Problem 26
Solve the inequalities. Suggestion: A calculator may be useful for approximating key numbers. $$2 x^{2}+9 x-1> 0$$
Short Answer
Expert verified
The solution is \(x \in (-\infty, -4.805) \cup (0.105, \infty)\).
Step by step solution
01
Identify and Set Up the Quadratic Inequality
The inequality given is \(2x^2 + 9x - 1 > 0\). This is a quadratic inequality where we need to determine where the quadratic expression is greater than zero.
02
Solve the Corresponding Quadratic Equation
Convert the inequality to an equation \(2x^2 + 9x - 1 = 0\) and solve. Use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a = 2\), \(b = 9\), and \(c = -1\).
03
Calculate the Discriminant
First, calculate the discriminant \(b^2 - 4ac = 9^2 - 4(2)(-1) = 81 + 8 = 89\). The discriminant is positive, indicating two real solutions.
04
Find the Roots Using the Quadratic Formula
Now substitute into the quadratic formula:\[x = \frac{-9 \pm \sqrt{89}}{4}\].This gives two approximate roots: \(x_1 \approx 0.105\) and \(x_2 \approx -4.805\).
05
Test Intervals Determined by the Roots
The roots divide the number line into three intervals: \((-\infty, -4.805)\), \((-4.805, 0.105)\), and \((0.105, \infty)\). Choose a test point from each interval to determine where the inequality holds.
06
Test Interval \((-\infty, -4.805)\)
Pick \(x = -5\). Substitute into the inequality:\[2(-5)^2 + 9(-5) - 1 = 50 - 45 - 1 = 4 > 0\].The inequality is true in this interval.
07
Test Interval \((-4.805, 0.105)\)
Pick \(x = 0\). Substitute into the inequality:\[2(0)^2 + 9(0) - 1 = -1 < 0\].The inequality is false in this interval.
08
Test Interval \((0.105, \infty)\)
Pick \(x = 1\). Substitute into the inequality:\[2(1)^2 + 9(1) - 1 = 2 + 9 - 1 = 10 > 0\].The inequality is true in this interval.
09
Conclusion and Solution
The quadratic inequality is true in the intervals \((-\infty, -4.805)\) and \((0.105, \infty)\). Therefore, the solution to the inequality \(2x^2 + 9x - 1 > 0\) is \(x \in (-\infty, -4.805) \cup (0.105, \infty)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
When solving a quadratic inequality like \(2x^2 + 9x - 1 > 0\), one of the most powerful tools in our mathematical toolkit is the quadratic formula. The quadratic formula helps us find the roots of any quadratic equation of the form \(ax^2 + bx + c = 0\). These roots tell us where the corresponding graph of the quadratic equation intersects the x-axis.
The formula is written as:
The formula is written as:
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
- \(a\), \(b\), and \(c\) are coefficients from the quadratic equation \(ax^2 + bx + c = 0\).
- \(b^2 - 4ac\) is known as the discriminant.
- The symbols \(\pm\) indicate two possible values for \(x\), meaning potentially two real solutions.
Discriminant
The discriminant is a key component of the quadratic formula and plays a crucial role in determining the nature of the roots of a quadratic equation. Given the equation \(ax^2 + bx + c = 0\), the discriminant \(D\) is calculated as \(b^2 - 4ac\).
The value of the discriminant provides valuable insights:
The value of the discriminant provides valuable insights:
- If \(D > 0\), there are two distinct real roots. The quadratic curve crosses the x-axis at two points.
- If \(D = 0\), there is exactly one real root, meaning the graph touches the x-axis at a single point (a perfect square trinomial).
- If \(D < 0\), there are no real roots, indicating that the graph does not intersect the x-axis at all.
Interval Testing
Interval testing is a technique used to determine the solution to a quadratic inequality by evaluating the expression in different intervals derived from its roots. Once we find the roots of the corresponding equation \(2x^2 + 9x - 1 = 0\) using the quadratic formula, we segment the x-axis into several intervals.
The intervals are determined by the roots found using the quadratic formula:
The intervals are determined by the roots found using the quadratic formula:
- \((-\infty, x_1)\)
- \((x_1, x_2)\)
- \((x_2, \infty)\)
- Choose a point like \(-5\) in \((-\infty, x_1)\) to see if the inequality holds.
- Try \(0\) in \((x_1, x_2)\) to check the sign.
- Evaluate \(1\) in \((x_2, \infty)\) for the truth of the inequality.