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Solve the inequalities. Suggestion: A calculator may be useful for approximating key numbers. $$2 x^{2}+9 x-1> 0$$

Short Answer

Expert verified
The solution is \(x \in (-\infty, -4.805) \cup (0.105, \infty)\).

Step by step solution

01

Identify and Set Up the Quadratic Inequality

The inequality given is \(2x^2 + 9x - 1 > 0\). This is a quadratic inequality where we need to determine where the quadratic expression is greater than zero.
02

Solve the Corresponding Quadratic Equation

Convert the inequality to an equation \(2x^2 + 9x - 1 = 0\) and solve. Use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a = 2\), \(b = 9\), and \(c = -1\).
03

Calculate the Discriminant

First, calculate the discriminant \(b^2 - 4ac = 9^2 - 4(2)(-1) = 81 + 8 = 89\). The discriminant is positive, indicating two real solutions.
04

Find the Roots Using the Quadratic Formula

Now substitute into the quadratic formula:\[x = \frac{-9 \pm \sqrt{89}}{4}\].This gives two approximate roots: \(x_1 \approx 0.105\) and \(x_2 \approx -4.805\).
05

Test Intervals Determined by the Roots

The roots divide the number line into three intervals: \((-\infty, -4.805)\), \((-4.805, 0.105)\), and \((0.105, \infty)\). Choose a test point from each interval to determine where the inequality holds.
06

Test Interval \((-\infty, -4.805)\)

Pick \(x = -5\). Substitute into the inequality:\[2(-5)^2 + 9(-5) - 1 = 50 - 45 - 1 = 4 > 0\].The inequality is true in this interval.
07

Test Interval \((-4.805, 0.105)\)

Pick \(x = 0\). Substitute into the inequality:\[2(0)^2 + 9(0) - 1 = -1 < 0\].The inequality is false in this interval.
08

Test Interval \((0.105, \infty)\)

Pick \(x = 1\). Substitute into the inequality:\[2(1)^2 + 9(1) - 1 = 2 + 9 - 1 = 10 > 0\].The inequality is true in this interval.
09

Conclusion and Solution

The quadratic inequality is true in the intervals \((-\infty, -4.805)\) and \((0.105, \infty)\). Therefore, the solution to the inequality \(2x^2 + 9x - 1 > 0\) is \(x \in (-\infty, -4.805) \cup (0.105, \infty)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Formula
When solving a quadratic inequality like \(2x^2 + 9x - 1 > 0\), one of the most powerful tools in our mathematical toolkit is the quadratic formula. The quadratic formula helps us find the roots of any quadratic equation of the form \(ax^2 + bx + c = 0\). These roots tell us where the corresponding graph of the quadratic equation intersects the x-axis.

The formula is written as:
  • \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
Here's a breakdown of each symbol in the formula:
  • \(a\), \(b\), and \(c\) are coefficients from the quadratic equation \(ax^2 + bx + c = 0\).
  • \(b^2 - 4ac\) is known as the discriminant.
  • The symbols \(\pm\) indicate two possible values for \(x\), meaning potentially two real solutions.
In the context of the inequality \(2x^2 + 9x - 1 > 0\), using the quadratic formula helps us find where the expression equals zero, which ultimately helps us determine the solution of the inequality itself.
Discriminant
The discriminant is a key component of the quadratic formula and plays a crucial role in determining the nature of the roots of a quadratic equation. Given the equation \(ax^2 + bx + c = 0\), the discriminant \(D\) is calculated as \(b^2 - 4ac\).

The value of the discriminant provides valuable insights:
  • If \(D > 0\), there are two distinct real roots. The quadratic curve crosses the x-axis at two points.
  • If \(D = 0\), there is exactly one real root, meaning the graph touches the x-axis at a single point (a perfect square trinomial).
  • If \(D < 0\), there are no real roots, indicating that the graph does not intersect the x-axis at all.
In our example, \(2x^2 + 9x - 1 > 0\), the discriminant is \(81 + 8 = 89\), a positive number. This indicates that we have two real solutions, or roots. These roots allow us to determine intervals on the number line to test for solutions to the inequality.
Interval Testing
Interval testing is a technique used to determine the solution to a quadratic inequality by evaluating the expression in different intervals derived from its roots. Once we find the roots of the corresponding equation \(2x^2 + 9x - 1 = 0\) using the quadratic formula, we segment the x-axis into several intervals.

The intervals are determined by the roots found using the quadratic formula:
  • \((-\infty, x_1)\)
  • \((x_1, x_2)\)
  • \((x_2, \infty)\)
For each interval, we pick a test point to substitute back into the original inequality \(2x^2 + 9x - 1 > 0\):
  • Choose a point like \(-5\) in \((-\infty, x_1)\) to see if the inequality holds.
  • Try \(0\) in \((x_1, x_2)\) to check the sign.
  • Evaluate \(1\) in \((x_2, \infty)\) for the truth of the inequality.
Based on the test results, you can determine in which intervals the inequality is true. In this example, the inequality holds true in the intervals \((-\infty, -4.805)\) and \((0.105, \infty)\), providing us with the complete solution to the inequality problem.

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