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Carry out the indicated operations. Express your results in rectangular form for those cases in which the trigonometric functions are readily evaluated without tables or a calculator. $$(1+i)^{16}$$

Short Answer

Expert verified
(1+i)^{16} = 256.

Step by step solution

01

Convert to Polar Form

First, express the complex number \(1+i\) in polar form. Recall that a complex number \(z=a+bi\) can be rewritten in polar form as \(r(\cos\theta + i\sin\theta)\). The modulus \(r\) is given by \(r=\sqrt{a^2+b^2}\), and the angle \(\theta\) is given by \(\tan^{-1}(b/a)\).
02

Calculate the Modulus and Angle

For \(1+i\), calculate the modulus:\[r = \sqrt{1^2 + 1^2} = \sqrt{2}\]The angle \(\theta\) is:\[\theta = \tan^{-1}(1/1) = \pi/4\].Thus, \(1+i=\sqrt{2}(\cos\frac{\pi}{4} + i\sin\frac{\pi}{4})\).
03

Apply De Moivre's Theorem

To find \((1+i)^{16}\), use De Moivre’s Theorem, which states that \([r(\cos\theta + i\sin\theta)]^n = r^n(\cos(n\theta) + i\sin(n\theta))\). Here, \(n=16\), \(r=\sqrt{2}\), and \(\theta=\frac{\pi}{4}\).Calculate \(r^{16} = (\sqrt{2})^{16} = 2^8 = 256\).
04

Calculate the New Angle

We compute the new angle \(16\theta\):\[16\cdot\frac{\pi}{4} = 4\pi\].This angle corresponds to a full rotation (multiples of \(2\pi\)), so \(\cos(4\pi) + i\sin(4\pi) = \cos(0) + i\sin(0)\).
05

Simplify Final Expression

Since \(\cos(0) = 1\) and \(\sin(0) = 0\), we find:\[256 \cdot (1 + i0) = 256\].Thus, the operation \((1+i)^{16}\) simplifies to 256 in rectangular form.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Form
Polar form is a way to represent complex numbers that is particularly useful for multiplication, division, and finding powers and roots. **A complex number**, which is usually expressed as \(a + bi\), can be transformed into polar form using two key components:
  • The modulus \(r\), which is the distance of the complex number from the origin in the complex plane.
  • The angle \(\theta\), which is the angle formed with the positive x-axis.
To convert from rectangular form \(a + bi\) to polar form \(r(\cos\theta + i\sin\theta)\), you calculate:
  • The modulus \(r = \sqrt{a^2 + b^2}\).
  • The argument \(\theta = \tan^{-1}(b/a)\).
For example, the complex number \(1+i\) has a modulus \(\sqrt{2}\) and an angle \(\pi/4\), resulting in the polar form \(\sqrt{2}(\cos(\pi/4) + i\sin(\pi/4))\). This is particularly helpful when using De Moivre's Theorem, which we will explore next.
De Moivre's Theorem
Understanding De Moivre's Theorem can simplify computations involving powers and roots of complex numbers. **The theorem states** that for any complex number in polar form \(r(\cos\theta + i\sin\theta)\) and a positive integer \(n\),:\[[r(\cos\theta + i\sin\theta)]^n = r^n(\cos(n\theta) + i\sin(n\theta))\]This powerful formula allows us to raise complex numbers to a power seamlessly. For example, raising \(1+i\) to the 16th power:
  • First, convert \(1+i\) to polar form: \(\sqrt{2}(\cos(\pi/4) + i\sin(\pi/4))\).
  • Apply De Moivre's Theorem: \((\sqrt{2})^{16} = 256\) and calculate \(16 \cdot \pi/4 = 4\pi\).
Since \(4\pi\) is a full rotation on the unit circle, the cos and sin values revert to those at \(0\), yielding \((1, 0)\) in Cartesian coordinates. Thus, the final answer in rectangular form is \(256\). This theorem makes even cumbersome calculations feel more approachable.
Rectangular Form
Rectangular form, or Cartesian form, expresses a complex number using the standard coordinates \(a + bi\). Here, \(a\) represents the real part and \(bi\) represents the imaginary part of the complex number. **It's often used** for addition and subtraction of complex numbers due to its straightforward approach. However, converting complex results back into rectangular form from polar form can help intuitively verify your results.For example, to express \((1+i)^{16}\) in rectangular form, after using De Moivre's Theorem, you find:
  • The complex number in polar form simplifies to \(256(\cos(0) + i\sin(0))\), since \(4\pi\) corresponds effectively to \(0\).
  • Since \(\cos(0) = 1\) and \(\sin(0) = 0\), the operation simplifies directly to \(256(1+0i)\), which is simply \(256\).
Understanding how to switch between polar and rectangular forms is essential for complex number operations, confirming results, and gaining a deeper insight into calculations.

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