Chapter 13: Problem 43
Find the coefficient of the term containing \(a^{4}\) in the expansion of \((\sqrt{a}-\sqrt{x})^{10}\).
Short Answer
Expert verified
The coefficient of the term containing \(a^{4}\) is 45.
Step by step solution
01
Identify the Expansion Formula
To find the coefficient of a specific term in a binomial expansion, we use the Binomial Theorem, which states that \[(x+y)^n = \sum_{k=0}^{n} \binom{n}{k} x^{n-k} y^k.\] Here, we have \((\sqrt{a} - \sqrt{x})^{10}\), meaning \(x = \sqrt{a}\), \(y = -\sqrt{x}\), and \(n = 10\).
02
Determine the Specific Term
We need the term containing \(a^4\). The variable \(a\) appears as \((\sqrt{a})^{10-k}\), meaning \[((\sqrt{a})^{10-k} = a^{(10-k)/2}).\] We want \(a^{(10-k)/2} = a^4\).
03
Solve for k
Set the exponents of \(a\) equal: \[\frac{10-k}{2} = 4.\] Multiply each side by 2 to clear the fraction: \[10 - k = 8.\] Solve for \(k\): \[k=2.\]
04
Identify the Term's Coefficient
Once we have \(k=2\), plug this into the binomial coefficient:\[\binom{10}{2} \times (\sqrt{a})^{10-2} \times (-\sqrt{x})^{2}.\] Evaluate each part. The binomial coefficient is:\[\binom{10}{2} = \frac{10 \times 9}{2 \times 1} = 45.\] The powers are:\[(\sqrt{a})^{8} = a^4 \text{ and } (-\sqrt{x})^2 = x.\]
05
Conclusion
The full term is:\[45 \times a^4 \times x.\] Thus, the coefficient of the term containing \(a^4\) in the expansion is \(45.\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Expansion
The binomial expansion is a powerful algebraic method used to expand expressions that are raised to a power. The Binomial Theorem provides us with a systematic approach to do this. It says that for any positive integer \(n\), a binomial expression like \((x+y)^n\) can be expanded into a sum of terms involving coefficients, powers of \(x\), and powers of \(y\).
For example, if we have \((\sqrt{a} - \sqrt{x})^{10}\), we can expand this using the Binomial Theorem. In general form, the theorem provides:\[(x+y)^n = \sum_{k=0}^{n} \binom{n}{k} x^{n-k} y^k\]
Here, \(x\) and \(y\) are parts of the binomial, and \(n\) is the exponent. The summation term includes a binomial coefficient \(\binom{n}{k}\), which is key for coefficient calculation. The expansion includes one term for each integer \(k\) from 0 to \(n\). Understanding this theorem is essential for solving problems involving powers of binomials, such as our exercise question.
For example, if we have \((\sqrt{a} - \sqrt{x})^{10}\), we can expand this using the Binomial Theorem. In general form, the theorem provides:\[(x+y)^n = \sum_{k=0}^{n} \binom{n}{k} x^{n-k} y^k\]
Here, \(x\) and \(y\) are parts of the binomial, and \(n\) is the exponent. The summation term includes a binomial coefficient \(\binom{n}{k}\), which is key for coefficient calculation. The expansion includes one term for each integer \(k\) from 0 to \(n\). Understanding this theorem is essential for solving problems involving powers of binomials, such as our exercise question.
Coefficient Calculation
Calculating the coefficient of a term in a binomial expansion involves a few clear steps. The binomial coefficient, denoted \(\binom{n}{k}\), is a central component. It represents the number of ways to choose \(k\) elements from a set of \(n\) elements, and mathematically given by:\[\binom{n}{k} = \frac{n!}{k! \cdot (n-k)!}\]
In our specific task, to find the coefficient of the term with \(a^4\) in the expansion of \((\sqrt{a} - \sqrt{x})^{10}\), we first determined suitable \(k\) based on the power of \(a\). We solved for \(k\) by ensuring the power of \(a\) is exactly 4. This was done by solving:\[\frac{10-k}{2} = 4\]
This step gave us \(k = 2\), meaning we used \(\binom{10}{2}\) for coefficient calculation. Plugging this into our formula yields \(\binom{10}{2} = 45\). Such straightforward analysis can help determine specific coefficients in binomial expansions effectively.
In our specific task, to find the coefficient of the term with \(a^4\) in the expansion of \((\sqrt{a} - \sqrt{x})^{10}\), we first determined suitable \(k\) based on the power of \(a\). We solved for \(k\) by ensuring the power of \(a\) is exactly 4. This was done by solving:\[\frac{10-k}{2} = 4\]
This step gave us \(k = 2\), meaning we used \(\binom{10}{2}\) for coefficient calculation. Plugging this into our formula yields \(\binom{10}{2} = 45\). Such straightforward analysis can help determine specific coefficients in binomial expansions effectively.
Polynomial Expression
A polynomial expression is a mathematical expression involving a sum of powers in one or more variables multiplied by coefficients. Polynomials include terms like \(a^4\), which consist of a variable raised to an exponent and a corresponding coefficient.
In our exercise, the binomial expansion results in polynomial terms of different powers of \(a\) and \(x\). When expanding \((\sqrt{a} - \sqrt{x})^{10}\), each term in the expansion represents a part of the polynomial, like \(a^4 \times x\).
Each term's structure follows:
In our exercise, the binomial expansion results in polynomial terms of different powers of \(a\) and \(x\). When expanding \((\sqrt{a} - \sqrt{x})^{10}\), each term in the expansion represents a part of the polynomial, like \(a^4 \times x\).
Each term's structure follows:
- A coefficient derived from the binomial coefficient \(\binom{n}{k}\)
- Terms involving powers of the variables, like \((\sqrt{a})^{10-k}\) and \((\sqrt{x})^k\)