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List the possibilities for rational roots. $$\frac{2}{3} x^{3}-x^{2}-5 x+2=0$$

Short Answer

Expert verified
Possible rational roots: ±1, ±2, ±3, ±6, ±1/2, ±3/2.

Step by step solution

01

Identifying the Polynomial

The given polynomial is \( \frac{2}{3} x^{3} - x^{2} - 5x + 2 = 0 \). For root analysis using the Rational Root Theorem, multiply through by 3 to eliminate the fraction: \( 2x^{3} - 3x^{2} - 15x + 6 = 0 \).
02

Rational Root Theorem

According to the Rational Root Theorem, any rational solution, or root, of the polynomial equation \( 2x^{3} - 3x^{2} - 15x + 6 = 0 \) is of the form \( \frac{p}{q} \), where \( p \) is a factor of the constant term and \( q \) is a factor of the leading coefficient.
03

Finding Factors of Constant Term

The constant term in the polynomial is 6. The factors of 6 are \( \pm 1, \pm 2, \pm 3, \pm 6 \).
04

Finding Factors of Leading Coefficient

The leading coefficient of the polynomial is 2. The factors of 2 are \( \pm 1, \pm 2 \).
05

Listing Possible Rational Roots

List the possible rational roots by forming fractions using the factors of the constant term over the factors of the leading coefficient. This gives you: \( \pm 1, \pm 2, \pm 3, \pm 6, \pm \frac{1}{2}, \pm \frac{3}{2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial Roots
Understanding polynomial roots is a fundamental concept in algebra, especially when solving polynomial equations. Simply put, a root of a polynomial is a value of the variable that makes the polynomial equal to zero. In our exercise, we are concerned with the polynomial \( \frac{2}{3} x^{3} - x^{2} - 5x + 2 = 0 \). By finding its roots, we determine the \( x \)-values at which the polynomial crosses or touches the \( x \)-axis.

It's important to note that polynomials can have different types of roots:
  • Real roots: These are roots that are real numbers and can be rational or irrational.
  • Complex roots: These are roots that involve imaginary numbers and appear in conjugate pairs when coefficients are real.

For this exercise, we're specifically looking for rational roots, which are possibly expressible as simple fractions.
Rational Solutions
Rational solutions, also known as rational roots, are solutions that can be expressed as a quotient of two integers. When using the Rational Root Theorem to find such solutions for a polynomial, we're essentially narrowing down potential candidates that can be checked. The theorem states that if a polynomial has a rational root \( \frac{p}{q} \), then:
  • \( p \) is a factor of the constant term of the polynomial.
  • \( q \) is a factor of the leading coefficient of the polynomial.

In our exercise, the polynomial \( 2x^{3} - 3x^{2} - 15x + 6 = 0 \) was derived after eliminating fractions for simplicity. Here, we observed that the constant term is 6 and the leading coefficient is 2.

After finding their factors (\( \pm 1, \pm 2, \pm 3, \pm 6 \) for 6, and \( \pm 1, \pm 2 \) for 2), we can form possible rational roots: \( \pm 1, \pm 2, \pm 3, \pm 6, \pm \frac{1}{2}, \pm \frac{3}{2} \). These are potential candidates to be verified using substitution or other methods like synthetic division.
Factor Analysis
Factor analysis in the context of solving polynomial equations is a method to simplify the finding of roots. By identifying factors, we can break down complex expressions into simpler products—much like simplifying fractions in arithmetic.

The first crucial step in our exercise was performing factor analysis on the polynomial by eliminating fractions. This resulted in a cleaner expression \( 2x^{3} - 3x^{2} - 15x + 6 = 0 \). With fractions removed, identifying factors becomes easier.

Next comes finding the factors of the constant and the leading coefficient:
  • Constant term (6): Factors are \( \pm 1, \pm 2, \pm 3, \pm 6 \).
  • Leading coefficient (2): Factors are \( \pm 1, \pm 2 \).

Once these are known, they guide the formation of potential rational roots by pairing all factors of the constant term with all factors of the leading coefficient. This systematic approach reduces guesswork and efficiently highlights possible solutions for thorough verification.

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Most popular questions from this chapter

(a) Let \(\theta=2 \pi / 7 .\) Use the reference angle concept to explain why \(\cos 3 \theta=\cos 4 \theta,\) then use your calculator to confirm the result. (b) For this portion of the exercise, assume as given the following two trigonometric identities: $$ \begin{array}{l} \cos 3 \theta=4 \cos ^{3} \theta-3 \cos \theta \\ \cos 4 \theta=8 \cos ^{4} \theta-8 \cos ^{2} \theta+1 \end{array} $$ Use these identities and the result in part (a) to show that \(\cos (2 \pi / 7)\) is a root of the equation $$ 8 x^{4}-4 x^{3}-8 x^{2}+3 x+1=0 $$ (c) List the prossibilities for the rational roots of equation (1). Then use synthetic division and the remainder theorem to show that there is only one rational root. Check that the reduced equation in this case is $$ 8 x^{3}+4 x^{2}-4 x-1=0 $$ (d) The work in parts (a) through (c) shows that the number \(\cos (2 \pi / 7)\) is a root of equation (2). By following the same technique, it can be shown that the numbers \(\cos (4 \pi / 7)\) and \(\cos (6 \pi / 7)\) also are roots of equation(2). Use this fact, along with Table 2 in Section \(12.4,\) to evaluate each of the following quantities. Then use a calculator to check your answers. (i) \(\cos \frac{2 \pi}{7} \cos \frac{4 \pi}{7} \cos \frac{6 \pi}{7}\) (ii) \(\cos \frac{2 \pi}{7}+\cos \frac{4 \pi}{7}+\cos \frac{6 \pi}{7}\)

Let \(a\) and \(b\) be real numbers. Find the real and imaginary parts of the quantity $$ \frac{a+b i}{a-b i}+\frac{a-b i}{a+b i} $$

Determine the partial fraction decomposition for each of the given rational expressions. Hint: In Exercises \(17,18,\) and \(26,\) use the rational roots theorem to factor the denominator. $$\frac{x^{3}-5}{x^{4}-81}$$

Determine the partial fraction decomposition for each of the given rational expressions. Hint: In Exercises \(17,18,\) and \(26,\) use the rational roots theorem to factor the denominator. $$\frac{4 x^{2}}{2 x^{3}-5 x^{2}-4 x+3}$$

First graph the two functions. Then use the method of successive approximations to locate, between successive thousandths, the \(x\)-coordinate of the point where the graphs intersect.Use a graphing utility to draw the graphs as well as to check your final answer. $$y=x^{3} ; y=4-x^{2}$$

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