/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 If \(z=1+4 i,\) compute \(z-10 i... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

If \(z=1+4 i,\) compute \(z-10 i\)

Short Answer

Expert verified
The result is \(1 - 6i\).

Step by step solution

01

Identify the given complex number

We are given the complex number \(z = 1 + 4i\). This number is composed of a real part and an imaginary part.
02

Identify the operation we need to perform

The problem asks us to compute \(z - 10i\). This requires us to subtract the imaginary part \(10i\) from the complex number \(z\).
03

Perform the subtraction on the imaginary parts

Subtract the imaginary part: \((4i - 10i)\). This results in \(-6i\).
04

Write the resulting complex number

The real part of \(z\) remains unchanged, so the result is \(1 - 6i\). Therefore, \(z - 10i = 1 - 6i\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Imaginary Part
A complex number such as \( z = 1 + 4i \) comprises two components: a real part and an imaginary part. The imaginary part is the component connected to the imaginary unit \( i \). The imaginary unit is a mathematical concept that facilitates calculations involving numbers that aren't real. It satisfies the equation \( i^2 = -1 \).

In this example, \( 4i \) is the imaginary part of the complex number \( 1 + 4i \). Often, students contend with the idea of what the imaginary part represents since it doesn't correlate directly to our number system's traditional quantities. Imaginary numbers, however, provide us with a broader set of tools for solving equations and understanding complex phenomena.
  • Imaginary part of \( 1 + 4i \): \( 4i \)
  • Always includes the variable \( i \), which represents the square root of -1
  • Multiplied by a real number, giving the full imaginary component
Real Part
In a complex number such as \( z = 1 + 4i \), the real part is the component without the imaginary unit \( i \). It is simply a regular real number.

In our exercise, the real part of the complex number \( 1 + 4i \) is \( 1 \). This portion of the complex number is akin to numbers we encounter in daily life, without any imaginary component involved. Even during operation like subtraction with another imaginary number, the real part remains unchanged unless we are directly modifying or combining real numbers.
  • Real part of \( 1 + 4i \): \( 1 \)
  • Maintains its value when only the imaginary part is altered
  • Behaves like standard real numbers in arithmetic operations
Complex Number Subtraction
Subtracting complex numbers involves the subtraction of their respective real parts and imaginary parts. If only the imaginary part is being subtracted, the real part of the original complex number remains unaffected.

In the exercise, we are tasked with calculating \( z - 10i \). Given \( z = 1 + 4i \), we subtract \( 10i \) from the imaginary portion. The calculation \( 4i - 10i \) yields \( -6i \). The real part, which is \( 1 \), stays the same.

Thus, the solution for \( z - 10i \) equals \( 1 - 6i \). This subtraction illustrates:
  • A change only affecting the imaginary part: \( 4i - 10i = -6i \)
  • No alteration to the real part: remains \( 1 \)
  • Resulting complex number: \( 1 - 6i \)
Understanding subtraction in this way helps in grasping larger concepts in mathematics and seeing how changes to one component of a complex number affect the whole entity.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You need to know that a prime number is a positive integer greater than 1 with no factors other than itself and 1. Thus the first seven prime numbers are 2,3,5,7,11,13 and 17. Find all prime numbers \(p\) for which the equation \(x^{2}+x-p=0\) has a rational root.

Determine the partial fraction decomposition for each of the given rational expressions. Hint: In Exercises \(17,18,\) and \(26,\) use the rational roots theorem to factor the denominator. $$\frac{4 x^{2}}{2 x^{3}-5 x^{2}-4 x+3}$$

Find all roots of each equation. Hints: First, factor by grouping. In Exercises 71 and 72 each equation has three roots; in Exercise 73 the equation has six roots; in Exercise 74 there are five roots. $$x^{6}-9 x^{4}+16 x^{2}-144=0$$

In a note that appeared in The Two-Year College Mathematics Journal [vol. \(12(1981), \text { pp. } 334-336],\) Professors Warren Page and Leo Chosid explain how the process of testing for rational roots can be shortened. In essence, their result is as follows. Suppose that we have a polynomial with integer coefficients and we are testing for a possible root \(p / q .\) Then, if a noninteger is generated at any point in the synthetic division process, \(p / q\) cannot be a root of the polynomial. For example, suppose we want to know whether \(4 / 3\) is a root of \(6 x^{4}-10 x^{3}+2 x^{2}-9 x+8=0\) The first few steps of the synthetic division are as follows. $$ \begin{array}{rrrrrr} 4 / 3 & 6 & -10 & 2 & -9 & 8 \\ \hline & & 8 & -8 / 3 & & \\ \hline & 6 & -2 & & & \\ \hline \end{array} $$ since the noninteger \(-8 / 3\) has been generated in the synthetic division process, the process can be stopped; \(4 / 3\) is not a root of the polynomial. Use this idea to shorten your work in testing to see whether the numbers \(3 / 4,1 / 8\). and \(-3 / 2\) are roots of the equation $$ 8 x^{5}-5 x^{4}+3 x^{2}-2 x-6=0 $$

In this exercise we verify that the remainder theorem is valid for the cubic polynomial \(g(x)=a x^{3}+b x^{2}+c x+d\). (a) Compute \(g(r)\) (b) Using synthetic division, divide \(g(x)\) by \(x-r .\) Check that the remainder you obtain is the same as the answer in part (a).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.