Chapter 12: Problem 56
(a) Compute the discriminant of the quadratic and note that it is negative (and therefore the equation has no real-number roots). (b) Use the quadratic formula to obtain the two complex conjugate roots of each equation. $$-10 z^{2}+4 z-2=0$$
Short Answer
Expert verified
The quadratic equation has complex conjugate roots: \(z = \frac{1}{5} + \frac{2i}{5}\) and \(z = \frac{1}{5} - \frac{2i}{5}\).
Step by step solution
01
Identify coefficients
The given quadratic equation is \(-10z^2 + 4z - 2 = 0\). Here, \(a = -10\), \(b = 4\), and \(c = -2\). These coefficients will be used in further calculations.
02
Compute the discriminant
The formula for the discriminant \(D\) of a quadratic equation \(ax^2 + bx + c = 0\) is \(D = b^2 - 4ac\). Substitute the coefficients: \(D = 4^2 - 4(-10)(-2)\). Calculate the expression: \(D = 16 - 80 = -64\). The discriminant is \(-64\), which is negative.
03
Conclude about roots with respect to the discriminant
Since the discriminant \(-64\) is negative, the quadratic equation will have no real-number roots but two complex conjugate roots.
04
Apply the quadratic formula
The quadratic formula is \(z = \frac{-b \pm \sqrt{D}}{2a}\). Here, \(D = -64\), hence \(z = \frac{-4 \pm \sqrt{-64}}{2(-10)}\).
05
Simplify the expression
Calculate the square root of \(-64\): \(\sqrt{-64} = 8i\), where \(i\) is the imaginary unit. Substitute back into the quadratic formula: \(z = \frac{-4 \pm 8i}{-20}\).
06
Simplify further
Separate the fraction: \(z = \frac{-4}{-20} \pm \frac{8i}{-20}\). Simplify: \(z = \frac{1}{5} \pm \frac{2i}{5}\). Thus, the roots are \(z = \frac{1}{5} + \frac{2i}{5}\) and \(z = \frac{1}{5} - \frac{2i}{5}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a fundamental tool in algebra that allows us to solve quadratic equations of the form \( ax^2 + bx + c = 0 \). It is expressed as:
In using this formula, there are usually three possible scenarios for the nature of the roots:
- \( z = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
In using this formula, there are usually three possible scenarios for the nature of the roots:
- If the discriminant (explained later) is positive, the equation has two distinct real roots.
- If the discriminant is zero, the equation has exactly one real root, also known as a repeated or double root.
- If the discriminant is negative, as in the given example, the roots are complex numbers (involving the imaginary unit \( i \)).
Discriminant
The discriminant is an important algebraic expression found within the quadratic formula under the square root symbol: \( b^2 - 4ac \).It provides critical information about the nature of the roots of the quadratic equation.
In the exercise, after computing the discriminant \( D \) as \( 4^2 - 4(-10)(-2) = -64 \),we confirmed that it is negative, indicating that our quadratic equation does not have real roots, but instead has complex conjugates.
Understanding the Discriminant:
- If the discriminant is positive, the quadratic will have two distinct real roots.- If the discriminant is zero, there will be one real root, which means the parabola touches the x-axis at exactly one point.- If the discriminant is negative, the roots are not real but rather complex numbers. These roots occur in pairs as complex conjugates.In the exercise, after computing the discriminant \( D \) as \( 4^2 - 4(-10)(-2) = -64 \),we confirmed that it is negative, indicating that our quadratic equation does not have real roots, but instead has complex conjugates.
Why it Matters:
The sign of the discriminant is crucial in predicting the type of solutions without solving the equation fully, saving time and effort in many problem-solving scenarios.Complex Conjugates
Complex roots appear when the discriminant of a quadratic equation is negative.These solutions are known as complex conjugates.Each complex number has a corresponding conjugate that mirror its real part but has an opposite imaginary part.
In our quadratic equation example, the computed roots are \( \frac{1}{5} + \frac{2i}{5} \) and \( \frac{1}{5} - \frac{2i}{5} \).These solutions clearly show the complex conjugate relationship:
Definition:
A complex number is expressed as \( a + bi \), where \( a \) is the real part and \( b \) is the imaginary part (with \( i \) being the square root of \(-1\)).A complex conjugate takes the form \( a - bi \).In our quadratic equation example, the computed roots are \( \frac{1}{5} + \frac{2i}{5} \) and \( \frac{1}{5} - \frac{2i}{5} \).These solutions clearly show the complex conjugate relationship:
- The real parts \( \frac{1}{5} \) are the same.
- The imaginary parts are \( +\frac{2i}{5} \) and \( -\frac{2i}{5} \).