/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Find a polynomial \(f(x)\) with ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find a polynomial \(f(x)\) with leading coefficient 1 such that the equation \(f(x)=0\) has the given roots and no others. If the degree of \(f(x)\) is 7 or more, express \(f(x)\) in factored form; otherwise, express \(f(x)\) in the form \(a_{n} x^{n}+a_{n-1} x^{n-1}+\cdots+a_{1} x+a_{0}\). $$\begin{array}{lcccc} \hline \text { Root } & \sqrt{3} & -\sqrt{3} & 4 i & -4 i \\ \text { Multiplicity } & 2 & 2 & 1 & 1 \\ \hline \end{array}$$

Short Answer

Expert verified
The polynomial is \((x^2 - 3)^2 (x^2 + 16)\).

Step by step solution

01

Identify the Roots and Multiplicities

The roots of the polynomial are given as \( \sqrt{3} \) with multiplicity 2, \( -\sqrt{3} \) with multiplicity 2, \( 4i \) with multiplicity 1, and \( -4i \) with multiplicity 1. This means each root will be used to create a factor in the polynomial corresponding to its multiplicity.
02

Write Factors from Roots

Since the polynomial has roots \( \sqrt{3} \) and \( -\sqrt{3} \) each with multiplicity 2, this provides the factor \( (x - \sqrt{3})^2(x + \sqrt{3})^2 \). Similarly, for the roots \( 4i \) and \( -4i \), the factors are \((x - 4i)(x + 4i)\).
03

Expand the Quadratic with Real Roots

For the quadratic portion with roots \( \sqrt{3} \) and \( -\sqrt{3} \), we have \((x - \sqrt{3})(x + \sqrt{3}) = x^2 - 3\). Therefore, \( (x - \sqrt{3})^2(x + \sqrt{3})^2 = (x^2 - 3)^2 \).
04

Expand the Quadratic with Complex Roots

The roots \( 4i \) and \( -4i \) yield the factor \((x - 4i)(x + 4i) = x^2 + 16 \). This step uses the identity \( (a-b)(a+b) = a^2 - b^2 \), where \( a = x \) and \( b = 4i \).
05

Construct the Polynomial

Now the polynomial can be expressed in factored form, combining all the factors: \[ f(x) = (x^2 - 3)^2 (x^2 + 16) \]. This is the polynomial since it encapsulates all roots and their multiplicities provided, with a leading coefficient of 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Roots of Polynomial
The roots of a polynomial are the values of the variable that make the polynomial equal to zero. In our exercise, the given roots are \( \sqrt{3} \), \( -\sqrt{3} \), \( 4i \), and \( -4i \) with specific multiplicities. Roots can be real or complex numbers and are fundamental to shaping the polynomial's structure.
Multiple roots with the same value indicate that these roots affect the polynomial multiple times, as denoted by their multiplicity. For example, if \( \sqrt{3} \) is a root with multiplicity 2, it appears twice in the factorization of the polynomial. This affects the polynomial's behavior and factorization.
Understanding the multiplicity of roots helps in constructing the polynomial and gives insight into the graph of the polynomial, such as whether it will touch or cross the x-axis at the root point.
Factored Form
Factored form refers to expressing a polynomial as a product of its factors. Writing a polynomial in its factored form reveals its roots easily, as each factor corresponds to a root of the polynomial. In our problem, each root contributes a factor.
  • Real Roots: For \( \sqrt{3} \) and \( -\sqrt{3} \), the factors are \( (x - \sqrt{3}) \) and \( (x + \sqrt{3}) \).
  • Complex Roots: For \( 4i \) and \( -4i \) the factors are \( (x - 4i) \) and \( (x + 4i) \).
By multiplying these factors together, considering the multiplicity of each root, we achieve the polynomial's factored form. The real beauty of the factored form is it clearly displays the roots, which are the solutions to the polynomial equation \( f(x) = 0 \).
Complex Numbers
Complex numbers extend our number system beyond real numbers. They are composed of a real part and an imaginary part. In this exercise, \( 4i \) and \( -4i \) are complex roots, where "i" is the imaginary unit representing \( \sqrt{-1} \).
When a polynomial has complex roots, they come in conjugate pairs if the coefficients of the polynomial are real numbers. This ensures the polynomial evaluates to real values for real inputs. So, when we have the complex roots \( 4i \) and \( -4i \), they form a pair that can be multiplied:
\((x - 4i)(x + 4i) = x^2 + 16.\)
This identity transforms the complex conjugate pair into a quadratic expression with real coefficients. Thus, complex numbers allow us to find solutions to polynomials that wouldn't be possible with only real numbers.
Quadratic Identities
Quadratic identities are used to simplify expressions and solve equations involving squared terms. Two important identities we used in this problem include the difference of squares and its application in the context of complex roots.
The difference of squares states that \((a-b)(a+b) = a^2 - b^2\). This identity allows us to handle both real and complex roots efficiently.
For example, to incorporate \(\sqrt{3}\) and \(-\sqrt{3} \) as roots, we use \((x - \sqrt{3})(x + \sqrt{3}) = x^2 - 3\). This identity simplifies the expression into a manageable quadratic with real coefficients.
Similarly, with complex roots \(x - 4i\) and \(x + 4i\), applying this identity yields \(x^2 + 16\). Quadratic identities are thus crucial to expressing polynomials in a simplifyed manner, to easily identify roots and solve polynomial equations.

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Most popular questions from this chapter

Provides an example in which an error in a partial fraction decomposition is not easily detected with a graphical approach. Indeed, this may be an example of a case in which, to check your partial fractions work, it’s easier to repeat the algebra than to experiment with numerous viewing rectangles. Decide for yourself after completing the problem. There is an error in the following partial fraction decomposition: $$\frac{1}{(x+2)(x+5)(x-14)}=\frac{-1 / 48}{x+2}+\frac{1 / 57}{x+5}+\frac{1 / 305}{x-14}$$ (a) Let \(f\) and \(g\) denote the two functions defined by the expressions on the left side and the right side, respectively, in the above equation. Use a graphing utility to graph \(f\) and \(g,\) first in the standard viewing rectangle and then in the rectangle [-15,15,5] by \([-0.02,0.04,0.02] .\) In this latter rectangle, note that the graphs do appear to be identical. (People using a software graphing application and looking at the curves on a computer monitor may have a little advantage here over those drawing the graphs on a relatively small graphing calculator screen.) (b) Find a viewing rectangle clearly demonstrating that the graphs of \(f\) and \(g\) are not identical. (c) Find the correct partial fraction decomposition, given that the form is $$\frac{1}{(x+2)(x+5)(x-14)}=\frac{A}{x+2}+\frac{B}{x+5}+\frac{C}{x-14}$$

The following result is a particular case of a theorem proved by Professor David C. Kurtz in The American Mathematical Monthly [vol. \(99(1992), \text { pp. } 259-263]\) Suppose we have a cubic equation \(a_{3} x^{3}+a_{2} x^{2}+a_{1} x+a_{0}=0\) in which all of the coefficients are positive real numbers. Furthermore, suppose that the following two inequalities hold. $$ a_{1}^{2}>4 a_{0} a_{2} \quad \text { and } \quad a_{2}^{2}>4 a_{1} a_{3} $$ Then the cubic equation has three distinct real roots. (a) Check that these inequalities are valid in the case of the equation \(2 x^{3}+8 x^{2}+7 x+1=0 .\) This implies that the equation has three distinct real roots. Use a graphing utility to verify this and to estimate each root to the nearest one hundredth. (b) Follow part (a) for the equation \(3 x^{3}+40 x^{2}+100 x+30=0\) (c) Use a graphing utility to demonstrate that the graph of \(y=6 x^{3}+15 x^{2}+11 x+2\) has three distinct \(x\) -intercepts. Thus, the equation \(6 x^{3}+15 x^{2}+11 x+2=0\) has three distinct real roots. Now check that the condition \(a_{2}^{2}>4 a_{1} a_{3}\) fails to hold in this case. Explain why this does not contradict the result from Professor Kurtz stated above.

Find all roots of each equation. Hints: First, factor by grouping. In Exercises 71 and 72 each equation has three roots; in Exercise 73 the equation has six roots; in Exercise 74 there are five roots. $$x^{3}-3 x^{2}+4 x-12=0$$

Determine the partial fraction decomposition for each of the given expressions. $$\frac{1}{(x-a)(x-b)} \quad(a \neq b)$$

Determine the partial fraction decomposition for each of the given rational expressions. Hint: In Exercises \(17,18,\) and \(26,\) use the rational roots theorem to factor the denominator. $$\frac{x^{3}+2}{x^{4}+8 x^{2}+16}$$

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