/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Use the remainder theorem to eva... [FREE SOLUTION] | 91Ó°ÊÓ

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Use the remainder theorem to evaluate \(f(x)\) for the given value of \(x\). $$f(x)=2 x^{3}-x-4 ; x=4$$

Short Answer

Expert verified
The value of \(f(4)\) is 120.

Step by step solution

01

Understand the Remainder Theorem

The Remainder Theorem states that for a polynomial \(f(x)\), when it is divided by \(x-c\), the remainder of the division is \(f(c)\). This means we can find the value of \(f(c)\) by simply calculating \(f(c)\) directly instead of performing the entire division.
02

Substitute the Given Value

To find \(f(4)\), substitute \(x = 4\) into the polynomial \(f(x) = 2x^3 - x - 4\).
03

Calculate the Cubic Term

Compute the term \(2x^3\) at \(x=4\):\[ 2(4)^3 = 2 imes 64 = 128 \]
04

Calculate the Linear and Constant Terms

Next, calculate the linear term \(-x\) and constant term \(-4\) at \(x=4\): \[ -4 = -4 \]\[-1 imes 4 = -4 \]
05

Compute the Polynomial Value

Sum the results from the previous steps:\[ 128 - 4 - 4 = 120 \]Thus, \(f(4) = 120\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial Division
The concept of polynomial division is similar to dividing numbers but involves polynomials. Understanding how polynomial division works is crucial when studying functions and algebraic expressions.
Consider this: when a polynomial, say \( f(x) \), is divided by another polynomial, \( g(x) \), a quotient polynomial \( q(x) \) and a remainder \( r \) is obtained. The relationship between these can be expressed as:
  • \( f(x) = g(x) \cdot q(x) + r \)
where \( r \), the remainder, is either zero or has a degree lesser than \( g(x) \).
Using this idea is important because it simplifies complex polynomial operations to a more digestible form.Whether performing polynomial long division or using synthetic division, it helps break down high-degree polynomials.This foundation later aids in understanding concepts like the Remainder Theorem, explaining why instead of dividing to find a remainder, you can directly evaluate the polynomial at a specific value, \( x=c \).
Substitution Method
The substitution method provides a straightforward approach to solving equations and evaluating functions.
For polynomials, substitution involves replacing the variable \( x \) with a given number.This shift turns an abstract function into a concrete numeric expression, making it easier to solve.
When you substitute a value into a polynomial, make sure to follow these steps:
  • Identify the polynomial and the value you must substitute.
  • Replace every instance of the variable \( x \) with the specified value.
  • Calculate by following basic arithmetic operations like addition, subtraction, and exponentiation on those terms.
In the context of the Remainder Theorem, the substitution method eliminates the need for dividing the polynomial and neatly gives the remainder.As seen in the original exercise, substituting \( x = 4 \) into \( f(x) = 2x^3 - x - 4 \) simplifies finding \( f(4) \) directly.
Polynomial Evaluation
Polynomial evaluation involves calculating the value of a polynomial function given a specific input.
This is a fundamental skill in algebra, and its simplicity can often mask its power, particularly when combined with the Remainder Theorem.To evaluate a polynomial like \( f(x) = 2x^3 - x - 4 \) for \( x=4 \), each term in the polynomial is calculated separately when \( x \) is replaced by 4:
  • First, evaluate the highest-degree term: \( 2(4)^3 = 128 \).
  • Next, handle the remaining linear and constant terms: substitute and calculate \( -4 \) and \( -4 \) as outlined earlier.
Add up these calculated values to get the final evaluated value of the polynomial, which is crucial for tasks like graph plotting or finding function behavior.
Utilizing polynomial evaluation, students can better grasp how polynomials function and interact, providing a clearer understanding of how outputs are derived from inputs.

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Most popular questions from this chapter

Determine the partial fraction decomposition for each of the given rational expressions. Hint: In Exercises \(17,18,\) and \(26,\) use the rational roots theorem to factor the denominator. $$\frac{x}{x^{3}+8}$$

Find all roots of each equation. Hints: First, factor by grouping. In Exercises 71 and 72 each equation has three roots; in Exercise 73 the equation has six roots; in Exercise 74 there are five roots. $$x^{5}+4 x^{3}+8 x^{2}+32=0$$

The following result is a particular case of a theorem proved by Professor David C. Kurtz in The American Mathematical Monthly [vol. \(99(1992), \text { pp. } 259-263]\) Suppose we have a cubic equation \(a_{3} x^{3}+a_{2} x^{2}+a_{1} x+a_{0}=0\) in which all of the coefficients are positive real numbers. Furthermore, suppose that the following two inequalities hold. $$ a_{1}^{2}>4 a_{0} a_{2} \quad \text { and } \quad a_{2}^{2}>4 a_{1} a_{3} $$ Then the cubic equation has three distinct real roots. (a) Check that these inequalities are valid in the case of the equation \(2 x^{3}+8 x^{2}+7 x+1=0 .\) This implies that the equation has three distinct real roots. Use a graphing utility to verify this and to estimate each root to the nearest one hundredth. (b) Follow part (a) for the equation \(3 x^{3}+40 x^{2}+100 x+30=0\) (c) Use a graphing utility to demonstrate that the graph of \(y=6 x^{3}+15 x^{2}+11 x+2\) has three distinct \(x\) -intercepts. Thus, the equation \(6 x^{3}+15 x^{2}+11 x+2=0\) has three distinct real roots. Now check that the condition \(a_{2}^{2}>4 a_{1} a_{3}\) fails to hold in this case. Explain why this does not contradict the result from Professor Kurtz stated above.

Find all roots of each equation. Hints: First, factor by grouping. In Exercises 71 and 72 each equation has three roots; in Exercise 73 the equation has six roots; in Exercise 74 there are five roots. $$2 x^{3}+4 x^{2}+3 x+6=0$$

You need to know that a prime number is a positive integer greater than 1 with no factors other than itself and 1. Thus the first seven prime numbers are 2,3,5,7,11,13 and 17. Find all prime numbers \(p\) for which the equation \(x^{3}+x^{2}+x-p=0\) has at least one rational root. For each value of \(p\) that you find, find the corresponding real roots of the equation.

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