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Determine whether the given value for the variable is a root of the equation. $$12 x^{2}-x-20=0 ; x=5 / 4$$

Short Answer

Expert verified
The value \( x = \frac{5}{4} \) is not a root of the equation.

Step by step solution

01

Understand the Problem

We need to determine if the value \( x = \frac{5}{4} \) is a solution (or root) of the quadratic equation \( 12x^2 - x - 20 = 0 \). This means plugging \( x = \frac{5}{4} \) into the equation and checking if both sides equal zero.
02

Substitute the Value into the Equation

Substitute \( x = \frac{5}{4} \) into the equation:\[ 12\left(\frac{5}{4}\right)^2 - \frac{5}{4} - 20 = 0 \]
03

Simplify the Expression

Compute \( \left(\frac{5}{4}\right)^2 \) and then multiply by 12:\( \left(\frac{5}{4}\right)^2 = \frac{25}{16} \)Multiply by 12:\[ 12 \times \frac{25}{16} = \frac{300}{16} \]Now, simplify \( \frac{300}{16} \) to \( \frac{75}{4} \).
04

Simplify the Equation Further

Substitute \( \frac{75}{4} \) back into the equation and simplify:\[ \frac{75}{4} - \frac{5}{4} - 20 = 0 \]Combine \( \frac{75}{4} - \frac{5}{4} \):\[ \frac{70}{4} = \frac{35}{2} \]
05

Compare to the Right Side of the Equation

Now, simplify the left side further:\[ \frac{35}{2} - 20 \]Convert 20 to \( \frac{40}{2} \):\[ \frac{35}{2} - \frac{40}{2} = \frac{-5}{2} e 0 \]
06

Conclusion

Since the left side of the equation simplifies to \( \frac{-5}{2} \), which is not equal to zero, we conclude that \( x = \frac{5}{4} \) is not a root of the equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Roots of Equations
In the realm of algebra, finding the roots of an equation, especially a quadratic one, is akin to solving a puzzle. The roots are solutions that make the equation equal zero. For example, in the equation \( ax^2 + bx + c = 0 \), the roots are those specific values of \( x \) that satisfy this condition. When we refer to "finding the roots," we're essentially looking for where the graph of the equation intersects the x-axis. This is significant because these intersections represent points where the outcome of the equation is nothing, or zero.

Not all equations will have real roots; some might have complex ones. However, in our original exercise, we deal with potential real roots. By substituting a potential root, like \( x = \frac{5}{4} \), directly into the equation, we check if this value satisfies the condition of making the entire equation zero. The process is simple in concept—one puts the value into the equation and simplifies to see if the result equals zero—but it requires careful calculation at each step.

Understanding whether a specific value is indeed a root involves testing it accurately through substitution and simplification. This ensures no computational errors skew the final assessment.
Substitution Method
The substitution method is a powerful tool in solving equations, and it's especially useful when checking whether a given value is a root of an equation. The method is all about replacing variables with numbers or expressions to see if an equality holds true. It’s like replacing the scoop of the puzzle piece to see if it fits into the right spot.

In the context of our quadratic equation \(12x^2 - x - 20 = 0\), we substitute \( x = \frac{5}{4} \) into the equation. This is straightforward—every instance of \( x \) in the equation is replaced with \(\frac{5}{4}\). However, this substitution must be done with precision:
  • First, substitute the value: \(12\left(\frac{5}{4}\right)^2 - \frac{5}{4} - 20\).
  • Next, carefully follow the order of operations—first squaring the fraction, then multiplying, and finally simplifying each term.


The substitution method primarily allows us to test assumptions and verify solutions by transforming the equation with specific values. It acts as a necessary step to clearly see if our potential root is effective.
Simplification Process
Simplification is at the heart of solving and verifying solutions in mathematics. It involves reducing expressions to their simplest form, which makes them easier to work with and understand. For the quadratic equation example, simplification helped us assess whether \( x = \frac{5}{4} \) was indeed a root.

Let’s break down the simplification process detailed in the solution:
  • First, perform any operations within the equation such as squaring \(\left(\frac{5}{4}\right)^2\) to get \(\frac{25}{16}\).
  • Next, handle multiplication: \(12 \times \frac{25}{16}\) resulting in \(\frac{75}{4}\).
  • Finally, combine and reduce like terms: \(\frac{75}{4} - \frac{5}{4} - 20\).


By converting 20 into a fraction \(\frac{40}{2}\) and subtracting from \(\frac{35}{2}\), it became clear through simplification that the equation didn't equal zero. Thus, \( x = \frac{5}{4} \) was not a root.

Such simplification steps are critical because they uncover the truth about whether a potential solution solves the equation by reducing all complexity, allowing us to focus solely on solving the problem.

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Most popular questions from this chapter

In a note that appeared in The College Mathematics Journal [vol. \(20(1989), \text { pp. } 139-141]\), Professor Don Redmond proved the following interesting result. Consider the polynomial equation \(f(x)=a_{n} x^{n}+a_{n-1} x^{n-1}+\cdots+a_{1} x+a_{0}=0,\) and sup- pose that the degree of \(f(x)\) is at least 2 and that all of the coefficients are integers. If the three numbers \(a_{0}\) \(a_{n},\) and \(f(1)\) are all odd, then the given equation has no rational roots. Use this result to show that the following equations have no rational roots. (a) \(9 x^{5}-8 x^{4}+3 x^{2}-2 x+27=0\) (b) \(5 x^{5}+5 x^{4}-11 x^{2}-3 x-25=0\)

The following result is a particular case of a theorem proved by Professor David C. Kurtz in The American Mathematical Monthly [vol. \(99(1992), \text { pp. } 259-263]\) Suppose we have a cubic equation \(a_{3} x^{3}+a_{2} x^{2}+a_{1} x+a_{0}=0\) in which all of the coefficients are positive real numbers. Furthermore, suppose that the following two inequalities hold. $$ a_{1}^{2}>4 a_{0} a_{2} \quad \text { and } \quad a_{2}^{2}>4 a_{1} a_{3} $$ Then the cubic equation has three distinct real roots. (a) Check that these inequalities are valid in the case of the equation \(2 x^{3}+8 x^{2}+7 x+1=0 .\) This implies that the equation has three distinct real roots. Use a graphing utility to verify this and to estimate each root to the nearest one hundredth. (b) Follow part (a) for the equation \(3 x^{3}+40 x^{2}+100 x+30=0\) (c) Use a graphing utility to demonstrate that the graph of \(y=6 x^{3}+15 x^{2}+11 x+2\) has three distinct \(x\) -intercepts. Thus, the equation \(6 x^{3}+15 x^{2}+11 x+2=0\) has three distinct real roots. Now check that the condition \(a_{2}^{2}>4 a_{1} a_{3}\) fails to hold in this case. Explain why this does not contradict the result from Professor Kurtz stated above.

You are given an improper rational expression. First, use long division to rewrite the expression in the form (polynomial) \(+\) (proper rational expression) Next, obtain the partial fraction decomposition for the proper rational expression. Finally, rewrite the given improper rational expression in the form (polynomial) \(+\) (partial fractions) $$\frac{x^{6}+3 x^{5}+9 x^{3}+26 x^{2}+3 x+8}{x^{3}+8}$$

Each equation has exactly one positive root. In each case, locate the root between successive hundredths. Determine the successive integer bounds by computing \(f(0), f(1), f(2),\) and so on, until you find a sign change. $$2 x^{4}-x^{3}-12 x^{2}-16 x-8=0$$

Find a quadratic equation with the given roots. Write your answers in the form \(A x^{2}+B x+C=0\) Suggestion: Make use of Table 2. $$r_{1}=a+\sqrt{b}, r_{2}=a-\sqrt{b} \quad(b>0)$$

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