/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 An equation is given, followed b... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

An equation is given, followed by one or more roots of the equation. In each case, determine the remaining roots. $$4 x^{4}-8 x^{3}+24 x^{2}-20 x+25=0 ; x=(1+3 i) / 2$$

Short Answer

Expert verified
Remaining roots are \(x = \frac{1-3i}{2}\), \(x = \frac{3+i\sqrt{11}}{2}\), and \(x = \frac{3-i\sqrt{11}}{2}\).

Step by step solution

01

Recognize the Given Root

The problem states that one root of the equation is \(x = \frac{1 + 3i}{2}\). This root is non-real and complex.
02

Identify and Use the Complex Conjugate Root Theorem

According to the Complex Conjugate Root Theorem, for any polynomial with real coefficients, if a complex number \(a + bi\) is a root, then its conjugate \(a - bi\) is also a root. Therefore, \(x = \frac{1 - 3i}{2}\) is another root of the polynomial.
03

Form a Quadratic Factor

With the two roots \(x = \frac{1 + 3i}{2}\) and \(x = \frac{1 - 3i}{2}\), form a quadratic factor. Expand \( \left(x - \frac{1 + 3i}{2} \right)\left(x - \frac{1 - 3i}{2} \right) \).
04

Simplify the Quadratic Expression

Simplify the expression: \( \left(x - \frac{1 + 3i}{2}\right)\left(x - \frac{1 - 3i}{2}\right) = \left(x - \frac{1}{2} - \frac{3i}{2}\right)\left(x - \frac{1}{2} + \frac{3i}{2}\right) = \left(x - \frac{1}{2}\right)^2 - \left(\frac{3i}{2}\right)^2 = x^2 - x + \frac{5}{4} \).
05

Perform Polynomial Division

With the quadratic factor \(x^2 - x + \frac{5}{4}\), divide the original polynomial \(4x^4 - 8x^3 + 24x^2 - 20x + 25\) by \(4(x^2 - x + \frac{5}{4})\) to find the other quadratic factor. The division results in a factor of \(x^2 - 3x + 5\).
06

Find Remaining Roots

Now solve the equation \(x^2 - 3x + 5 = 0\) using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) where \(a = 1\), \(b = -3\), \(c = 5\). Calculate the discriminant: \(b^2 - 4ac = (-3)^2 - 4(1)(5) = 9 - 20 = -11\).
07

Solve Using the Quadratic Formula

Since the discriminant is negative, the remaining roots are complex: \(x = \frac{3 \pm \sqrt{-11}}{2} = \frac{3 \pm i\sqrt{11}}{2}\). Thus, the roots are \(x = \frac{3 + i\sqrt{11}}{2}\) and \(x = \frac{3 - i\sqrt{11}}{2}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial Roots
Polynomial roots are solutions to a polynomial equation. These are the values of \( x \) that satisfy the equation, making the polynomial equal to zero. For example, in the given polynomial equation \( 4x^4 - 8x^3 + 24x^2 - 20x + 25 = 0 \), each root is a value for \( x \) for which the polynomial evaluates to zero.
Roots can be real or complex numbers. Real roots are common, while complex roots arise in certain polynomial equations with real coefficients. When we solve a polynomial, we aim to find all its roots, revealing insights into the polynomial's behavior.
For a polynomial of degree \( n \), like our quartic polynomial with degree 4, there can be up to \( n \) roots. These roots explain intersections with the x-axis in the real number plane, whereas complex roots indicate intersections with the complex plane. Understanding polynomial roots is crucial for solving higher-degree equations.
Complex Conjugate Theorem
The Complex Conjugate Theorem is a significant tool when dealing with polynomials with real coefficients. This theorem states that if a polynomial has real coefficients and a complex number \( a + bi \) as a root, its complex conjugate \( a - bi \) must also be a root.
This theorem ensures that complex roots appear in conjugate pairs. Applied to our problem, since \( x = \frac{1 + 3i}{2} \) is a root, its conjugate \( x = \frac{1 - 3i}{2} \) is also a root.
In practical terms, the theorem simplifies calculations. By recognizing complex conjugate pairs early, one can form quadratic factors that are easier to work with. Quadratics formed from conjugate pairs maintain real coefficients, making polynomial division and factorization smoother processes. Understanding this theorem is essential for tackling polynomials involving complex numbers.
Quadratic Formula
The quadratic formula is a fundamental tool for finding the roots of quadratic equations, those in the form \( ax^2 + bx + c = 0 \). The formula is expressed as:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
This formula provides an efficient way to calculate the roots whether they are real or complex. In the case where the discriminant \( b^2 - 4ac \) is positive, the roots are real and distinct. If it is zero, the roots are real and repeated. However, when the discriminant is negative, the roots become complex conjugates.
For our polynomial equation, the quadratic formula allows us to solve the remaining quadratic \( x^2 - 3x + 5 = 0 \). The discriminant in this case is -11, indicating the roots are complex. The solution gives us \( x = \frac{3 \pm i\sqrt{11}}{2} \). The simplicity and power of the quadratic formula make it a go-to tool in algebra and calculus for solving second-degree polynomials.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You are given an improper rational expression. First, use long division to rewrite the expression in the form (polynomial) \(+\) (proper rational expression) Next, obtain the partial fraction decomposition for the proper rational expression. Finally, rewrite the given improper rational expression in the form (polynomial) \(+\) (partial fractions) \frac{6 x^{3}-16 x^{2}-13 x+25}{x^{2}-4 x+3}

Find all roots of each equation. Hints: First, factor by grouping. In Exercises 71 and 72 each equation has three roots; in Exercise 73 the equation has six roots; in Exercise 74 there are five roots. $$2 x^{3}+4 x^{2}+3 x+6=0$$

The following result is a particular case of a theorem proved by Professor David C. Kurtz in The American Mathematical Monthly [vol. \(99(1992), \text { pp. } 259-263]\) Suppose we have a cubic equation \(a_{3} x^{3}+a_{2} x^{2}+a_{1} x+a_{0}=0\) in which all of the coefficients are positive real numbers. Furthermore, suppose that the following two inequalities hold. $$ a_{1}^{2}>4 a_{0} a_{2} \quad \text { and } \quad a_{2}^{2}>4 a_{1} a_{3} $$ Then the cubic equation has three distinct real roots. (a) Check that these inequalities are valid in the case of the equation \(2 x^{3}+8 x^{2}+7 x+1=0 .\) This implies that the equation has three distinct real roots. Use a graphing utility to verify this and to estimate each root to the nearest one hundredth. (b) Follow part (a) for the equation \(3 x^{3}+40 x^{2}+100 x+30=0\) (c) Use a graphing utility to demonstrate that the graph of \(y=6 x^{3}+15 x^{2}+11 x+2\) has three distinct \(x\) -intercepts. Thus, the equation \(6 x^{3}+15 x^{2}+11 x+2=0\) has three distinct real roots. Now check that the condition \(a_{2}^{2}>4 a_{1} a_{3}\) fails to hold in this case. Explain why this does not contradict the result from Professor Kurtz stated above.

Find a polynomial equation \(f(x)=0\) satisfying the given conditions. If no such equation is possible, state this. Degree \(4 ; 1 / 2\) is a root of multiplicity three; \(x^{2}-3 x-4\) is a factor of \(f(x)\)

(a) factor the denominator of the given \(\mathrm{ra}\) tional expression; (b) determine the form of the partial fraction decomposition for the given rational expression; and (c) determine the values of the constants in the partial fraction decomposition that you gave in part (b). To help you in spotting errors, use the fact that in part (c), each of the required constants turns out to be an integer. $$\frac{11 x^{3}+35 x-7}{x^{4}+6 x^{2}+9}$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.