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According to the fundamental theorem of algebra, which of the equations in Exercises 1 and 2 have at least one root? (a) \(x^{5}-14 x^{4}+8 x+53=0\) (b) \(4.17 x^{3}+2.06 x^{2}+0.01 x+1.23=0\) (c) \(i x^{2}+(2+3 i) x-17=0\) (d) \(x^{21}+3 x^{0.3}+1=0\)

Short Answer

Expert verified
All four equations have at least one root.

Step by step solution

01

Understand the Fundamental Theorem of Algebra

The Fundamental Theorem of Algebra states that every non-zero polynomial equation of degree \( n \) has exactly \( n \) roots in the complex number system (when counted with multiplicities). This implies that any polynomial equation of degree at least 1 has at least one root.
02

Determine the Degree of Each Polynomial

- For (a) \( x^{5}-14 x^{4}+8 x+53=0 \), the degree is 5.- For (b) \( 4.17 x^{3}+2.06 x^{2}+0.01 x+1.23=0 \), the degree is 3.- For (c) \( i x^{2}+(2+3 i) x-17=0 \), the degree is 2.- For (d) \( x^{21}+3 x^{0.3}+1=0 \), the degree is 21.
03

Apply the Fundamental Theorem

Since the Fundamental Theorem of Algebra applies to all polynomial equations of degree 1 or more, each of these equations, having degrees of 5, 3, 2, and 21 respectively, are guaranteed to have at least one root.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial Degree
The degree of a polynomial is a critical concept in understanding many algebraic properties. It refers to the highest power of the variable present in the polynomial. For instance, in a polynomial like \(x^5 - 14x^4 + 8x + 53\), the term with the highest exponent, \(x^5\), determines the degree. Here, the degree is 5.
Polynomials are classified based on their degree:
  • Linear polynomials have a degree of 1.
  • Quadratic polynomials have a degree of 2.
  • Cubic polynomials are of degree 3.
  • Higher degree polynomials follow the same pattern (quartic, quintic, etc.).
Understanding the degree helps us apply the Fundamental Theorem of Algebra, which indicates that a polynomial of degree \( n \) will have exactly \( n \) roots in the complex number system. This includes all roots, real and complex, as well as their multiplicities.
Complex Roots
Complex roots can be a bit perplexing at first. They are numbers in the form \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i\) is the imaginary unit, equal to the square root of -1. Complex numbers are essential because they ensure that every polynomial equation can be solved.
The interesting part of complex roots is that they often come in conjugate pairs. If a polynomial with real coefficients has a complex root \(a + bi\), it will also have the root \(a - bi\). For example, a quadratic polynomial like \(ix^2 + (2 + 3i)x - 17 = 0\) may have complex solutions due to the presence of the imaginary unit \(i\).
Understanding complex roots is crucial when dealing with non-real solutions, as they allow polynomials to have the complete range of solutions as dictated by their degrees.
Equation Roots
The roots of an equation are the solutions that satisfy the equation when substituted in place of the variable. According to the Fundamental Theorem of Algebra, a non-zero polynomial equation of degree \( n \) will have \( n \) roots when counted with multiplicities and including complex numbers. This guarantees that for polynomials equations like those given in the exercise, each will have at least one root.
Here's how you can think about roots:
  • Real roots are found where the polynomial crosses or touches the x-axis.
  • Complex roots, which occur in conjugate pairs, do not correspond to a point on the traditional graph but are crucial in providing a full set of solutions.
  • Repeated roots occur when the polynomial touches the x-axis but doesn't cross it, indicating a multiplicity greater than one.
Being able to identify the type and number of roots helps solve polynomials efficiently, whether through algebraic methods or modern computational tools.

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Most popular questions from this chapter

Each polynomial equation has exactly one negative root. (a) Use a graphing utility to determine successive integer bounds for the root. (b) Use the method of successive approximations to locate the root between successive thousandths. (Make use of the graphing utility to generate the required tables. ) $$x^{3}+x^{2}-2 x+1=0$$

This exercise outlines a proof of the rational roots theorem. At one point in the proof, we will need to rely on the following fact, which is proved in courses on number theory. FACT FROM NUMBER THEORY Suppose that \(A, B\), and \(C\) are integers and that \(A\) is a factor of the number \(B C .\) If \(A\) has no factor in common with \(C\) (other than ±1 ), then \(A\) must be a factor of \(B\) (a) Let \(A=2, B=8,\) and \(C=5 .\) Verify that the fact from number theory is correct here. (b) Let \(A=20, B=8,\) and \(C=5 .\) Note that \(A\) is a factor of \(B C,\) but \(A\) is not a factor of \(B .\) Why doesn't this contradict the fact from number theory? (c) Now we're ready to prove the rational roots theorem. We begin with a polynomial equation with integer coefficients: \(-a_{n} x^{n}+a_{n-1} x^{n-1}+\cdots+a_{1} x+a_{0}=0 \quad\left(n \geq 1, a_{n} \neq 0\right)\) We assume that the rational number \(p / q\) is a root of the equation and that \(p\) and \(q\) have no common factors other than \(1 .\) Why is the following equation now true? \(a_{n}\left(\frac{p}{q}\right)^{n}+a_{n-1}\left(\frac{p}{q}\right)^{n-1}+\cdots+a_{1}\left(\frac{p}{q}\right) a_{0}=0\) (d) Show that the last equation in part (c) can be written \(p\left(a_{n} p^{n-1}+a_{n-1} q p^{n-2}+\cdots+a_{1} q^{n-1}\right)=-a_{0} q^{n}\) since \(p\) is a factor of the left-hand side of this last equation, \(p\) must also be a factor of the right-hand side. That is, \(p\) must be a factor of \(a_{0} q^{n}\). But since \(p\) and \(q\) have no common factors, neither do \(p\) and \(q^{n}\) Our fact from number theory now tells us that \(p\) must be a factor of \(a_{0}\), as we wished to show. (The proof that \(q\) is a factor of \(a_{n}\) is carried out in a similar manner.)

Find a polynomial equation \(f(x)=0\) satisfying the given conditions. If no such equation is possible, state this. Degree \(4 ; 1 / 2\) is a root of multiplicity three; \(x^{2}-3 x-4\) is a factor of \(f(x)\)

Find a polynomial equation \(f(x)=0\) satisfying the given conditions. If no such equation is possible, state this. Degree \(3 ;\) the coefficient of \(x^{3}\) is \(1 ;\) three roots are 3,-4 and 5

Find a polynomial equation \(f(x)=0\) satisfying the given conditions. If no such equation is possible, state this. Degree \(3 ;-1\) is a root of multiplicity two; \(x+6\) is a factor of \(f(x)\)

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