Chapter 11: Problem 21
Graph the equations. $$9 x^{2}-24 x y+16 y^{2}-400 x-300 y=0$$
Short Answer
Expert verified
The equation represents a degenerate conic, which graphs as a straight line.
Step by step solution
01
Identify Conic Section Type
The given equation is quadratic in both x and y. We need to identify whether it represents a circle, ellipse, hyperbola, or parabola. To do this, we look at the discriminant, given by the formula: \(B^2 - 4AC\), where A, B, and C are coefficients from the general equation \(Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0\). For our equation, \(A = 9\), \(B = -24\), and \(C = 16\). Calculating the discriminant, we find \((-24)^2 - 4 \cdot 9 \cdot 16 = 0\), which indicates the degenerate case of a conic.
02
Complete the Square
To simplify the equation, we will complete the square for both the x and y terms. First, for the x terms, factor out the 9: \(9(x^2 - \frac{8}{3}x)\), then complete the square: \(9(x - \frac{4}{3})^2 - \frac{16}{3}\cdot 9\). Next, factor the 16 out of the y terms: \(16(y^2 - \frac{3}{4}y)\), then complete the square: \(16(y - \frac{3}{8})^2 - \frac{9}{16}\cdot 16\). Incorporate these into the full equation: \(9(x - \frac{4}{3})^2 + 16(y - \frac{3}{8})^2 = 400x + 300y\).
03
Rearrange the Equation
Rearrange the completed square equation to isolate the constant terms: \(9(x - \frac{4}{3})^2 + 16(y - \frac{3}{8})^2 = 9\frac{16}{3} + 16\frac{9}{16} + 400(x - \frac{4}{3}) + 300(y - \frac{3}{8})\). Simplify by combining and moving the terms: \((x - \frac{4}{3}) + (y - \frac{3}{8}) = 0\)).
04
Graph the Degenerate Conic
A degenerate conic is a straight line in this case. The equation simplifies to a linear form, suggesting the plot will result in a straight line. Graph the equation \(x = -\frac{4}{3}y - \frac{3}{8} + 9\frac{16}{3} + 16\frac{9}{16}\) in the xy-plane. The line passes through points derived from evaluating the simplified equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Completing the Square
The method of completing the square is a powerful tool used to transform quadratic expressions into a form that is easier to manipulate and understand. This technique is crucial when dealing with equations of conic sections, which can include circles, ellipses, parabolas, and hyperbolas.
When you have a quadratic equation, such as those involving terms like \(x^2\) or \(y^2\), completing the square enables you to rewrite these equations into a perfected square form. This form is much simpler to analyze and graph.
To complete the square for a given term, follow these steps:
When you have a quadratic equation, such as those involving terms like \(x^2\) or \(y^2\), completing the square enables you to rewrite these equations into a perfected square form. This form is much simpler to analyze and graph.
To complete the square for a given term, follow these steps:
- Identify the quadratic term and linear term in either \(x\) or \(y\).
- Factor out any coefficients that are present with the quadratic term.
- Take half of the coefficient of the linear term, square it, and add/subtract inside the equation to balance it out.
- Re-write the quadratic expression in its completed square form.
Discriminant of Conics
The discriminant is a mathematical formula used to determine the nature of a conic section represented by a quadratic equation. By calculating the discriminant, you can identify the type of conic section: ellipse, parabola, hyperbola, or a degenerate case.
For a general second-degree polynomial equation \(Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0\), the discriminant is given by the expression: \(B^2 - 4AC\). This single value gives insight into the equation’s geometric representation on the plane.
The value of the discriminant tells you:
For a general second-degree polynomial equation \(Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0\), the discriminant is given by the expression: \(B^2 - 4AC\). This single value gives insight into the equation’s geometric representation on the plane.
The value of the discriminant tells you:
- If \(B^2 - 4AC > 0\), the conic is a hyperbola.
- If \(B^2 - 4AC = 0\), the conic is degenerate, meaning it doesn't form a typical conic shape but could represent a point, a line, or intersecting lines.
- If \(B^2 - 4AC < 0\), the conic represents an ellipse, and when \(A = C\) and \(B = 0\), it’s a circle.
Degenerate Conic Sections
Degenerate conic sections are an interesting category of conics which occur when the so-called usual two-dimensional shapes (like circles, parabolas, ellipses, and hyperbolas) don't appear as expected. Instead, these equations can resolve into simpler constructs such as points, lines, or overlapping lines.
A degenerate conic is produced when the discriminant \(B^2 - 4AC = 0\). This means that the equation doesn't graph into any of the well-known conic sections on the plane. Instead, it might represent:
A degenerate conic is produced when the discriminant \(B^2 - 4AC = 0\). This means that the equation doesn't graph into any of the well-known conic sections on the plane. Instead, it might represent:
- A single point, when the terms simplify to an equation like \((x - a)^2 + (y - b)^2 = 0\).
- A line or pair of lines, for example, when equation tweaks resolve to something analogous to \((x + y)^2 = 0\), effectively becoming \(x = -y\).
- No points, if the equation fails to form any legitimate graphable solution.