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Graph the ellipses. In case, specify the lengths of the major and minor axes, the foci, and the eccentricity. For Exercises \(13-24,\) also specify the center of the ellipse. $$\frac{(x-5)^{2}}{5^{2}}+\frac{(y+1)^{2}}{3^{2}}=1$$

Short Answer

Expert verified
Center: (5,-1), Major axis: 10, Minor axis: 6, Foci: (9,-1) and (1,-1), Eccentricity: 0.8.

Step by step solution

01

Identify the General Equation of the Ellipse

The equation of an ellipse in standard form is given by \( \frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1 \), where \((h, k)\) is the center of the ellipse. In the given equation \( \frac{(x-5)^{2}}{5^{2}} + \frac{(y+1)^{2}}{3^{2}} = 1 \), we identify \( (h, k) = (5, -1) \), \( a = 5 \), and \( b = 3 \). This means the ellipse is centered at (5, -1).
02

Determine the Lengths of the Major and Minor Axes

For an ellipse, the major axis corresponds to the larger of \(a\) or \(b\). Since \(a = 5\) and \(b = 3\), the major axis is along the x-direction with length \(2a = 10\) and the minor axis is along the y-direction with length \(2b = 6\).
03

Calculate the Foci of the Ellipse

The distance of the foci from the center in the direction of the major axis is given by \(c = \sqrt{a^2 - b^2} \). Here, \(c = \sqrt{5^2 - 3^2} = \sqrt{25 - 9} = \sqrt{16} = 4\). Thus, the foci are at points \((5 + 4, -1) = (9, -1)\) and \((5 - 4, -1) = (1, -1)\).
04

Calculate the Eccentricity

The eccentricity \(e\) of an ellipse is given by \( e = \frac{c}{a} \). In this case, \(e = \frac{4}{5} = 0.8\).
05

Summarize the Properties of the Ellipse

The center of the ellipse is at (5, -1). The major axis is 10 units long and lies along the x-axis, and the minor axis is 6 units long and lies along the y-axis. The foci are at (9, -1) and (1, -1). The eccentricity of the ellipse is 0.8.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ellipse Properties
Ellipses are fascinating and important shapes in geometry and algebra that resemble stretched-out circles. Understanding their properties is crucial for graphing and analyzing these curves. Some key properties of an ellipse include its symmetry, dimensions, and orientation. An ellipse is symmetrical around both its major and minor axes. This means that if you were to fold an ellipse along either of these axes, the two halves of the ellipse would match exactly. The dimensions of the ellipse are determined by the lengths of the major and minor axes, which dictate how elongated the shape is. Another interesting property is the position of the foci, or focal points, which play a critical role in defining the shape and path of an ellipse. Each point on the ellipse is at a constant total distance from the two foci. This unique property is what gives ellipses their characteristic shape.
Equation of Ellipse
The equation of an ellipse in standard form is often represented as \( \frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1 \). This formula helps identify several geometric characteristics of the ellipse:
  • \((h, k)\) is the center of the ellipse, indicating the point around which the ellipse is symmetric.
  • The values \(a\) and \(b\) represent the semi-major and semi-minor axes of the ellipse, respectively.
  • If \(a > b\), the ellipse is elongated along the x-axis, and if \(b > a\), it is elongated along the y-axis.
  • When plotted, the ellipse's orientation and size can be quickly visualized through the equation parameters.
For the exercise given, \(a = 5\) and \(b = 3\), with the ellipse's center at \((5, -1)\). Thus, it stretches more along the x-axis than it does along the y-axis, giving it that distinctive elliptical appearance.
Foci and Eccentricity
An ellipse has two foci (singular: focus), essential points that impact the ellipse's shape. The distance between the center of the ellipse and each focus, \(c\), is derived from the equation \(c = \sqrt{a^2 - b^2}\). Using this formula, we find that \(c = 4\) for our problem, which places the foci at \((9, -1)\) and \((1, -1)\). The concept of eccentricity, denoted by \(e\), quantifies how much an ellipse deviates from being a perfect circle. Calculated as \( e = \frac{c}{a} \), it provides insight into the ellipse's "flatness." For the relevant exercise, the eccentricity is \(0.8\), meaning it is moderately elongated. A value closer to 0 indicates a shape closer to a circle, while values approaching 1 indicate a more elongated or "stretched" shape.
Major and Minor Axis
An ellipse's axes define its structure, with two main axes: the major and minor axes. The major axis is the longest diameter of the ellipse and runs through its center, focusing along the direction of the largest expanse of the ellipse. In this case, since \(a = 5 > b = 3\), the major axis is along the x-axis with a total length of \(2a = 10\). The minor axis is the shortest diameter and is perpendicular to the major axis. It stretches from one side of the ellipse to the other through the center, providing a cross-section of the shorter span. Here, the minor axis has a length of \(2b = 6\), lying along the y-axis. Both axes intersect at the center \((5, -1)\), and together they help in visualizing the complete shape and orientation of the ellipse.

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Most popular questions from this chapter

Solve for \(x\) and \(y\) $$\left\\{\begin{aligned}(\cos \theta) x+(\sin \theta) y &=x^{\prime} \\\\(-\sin \theta) x+(\cos \theta) y &=y^{\prime} \\\\\text {Answer: } & x=x^{\prime} \cos \theta-y^{\prime} \sin \theta \\\y &=x^{\prime} \sin \theta+y^{\prime} \cos \theta\end{aligned}\right.$$

Let \(P\left(x_{1}, y_{1}\right)\) be a point on the ellipse \(b^{2} x^{2}+a^{2} y^{2}=a^{2} b^{2}\) Suppose that the tangent to the ellipse at \(P\) meets the \(y\) axis at \(A\) and the \(x\) -axis at \(B .\) If \(A P=P B,\) what are \(x_{1}\) and \(y_{1}(\text { in terms of } a \text { and } b) ?\)

A normal to an ellipse is a line drawn perpendicular to the tangent at the point of tangency. Show that the equation of the normal to the ellipse \(\left(x^{2} / a^{2}\right)+\left(y^{2} / b^{2}\right)=1\) at the point \(\left(x_{1}, y_{1}\right)\) can be written $$a^{2} y_{1} x-b^{2} x_{1} y=\left(a^{2}-b^{2}\right) x_{1} y_{1}$$

Find \(\sin \theta\) and \(\cos \theta,\) where \(\theta\) is the (acute) angle of rotation that eliminates the \(x^{\prime} y^{\prime}\) -term. Note: You are not asked to graph the equation. $$4 x^{2}-5 x y+4 y^{2}+2=0$$

In this exercise you will look at the graph of the hyperbola \(16 x^{2}-9 y^{2}=144\) from two perspectives. (a) Solve the given equation for \(y,\) then graph the two resulting functions in the standard viewing rectangle. (b) Determine the equations of the asymptotes. Add the graphs of the asymptotes to your picture from part (a). (c) Looking at your picture from part (b), you can see that the hyperbola seems to be moving closer and closer to its asymptotes as \(|x|\) gets large. To see more dramatic evidence of this, change the viewing rectangle so that both \(x\) and \(y\) extend from -100 to \(100 .\) At this scale, the hyperbola is virtually indistinguishable from its asymptotes.

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