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Determine the angle of inclination of each line. Express the answer in both radians and degrees. In cases in which a calculator is necessary, round the answer to two decimal places. $$y=\sqrt{3} x+4$$

Short Answer

Expert verified
The angle of inclination is \( \frac{\pi}{3} \) radians or 60°.

Step by step solution

01

Understand the slope of the line

The equation of the line is given as \( y = \sqrt{3} x + 4 \). In this equation, the slope \( m \) of the line is \( \sqrt{3} \). The angle of inclination \( \theta \) of the line is the angle that the line makes with the positive x-axis.
02

Use the tangent formula for the angle of inclination

The tangent of the angle of inclination of a line \( \theta \) is equal to the slope \( m \). Using the formula \( \tan(\theta) = m \), we have: \[ \tan(\theta) = \sqrt{3} \].
03

Calculate the angle in radians

To find \( \theta \), we take the arctangent of the slope: \( \theta = \tan^{-1}(\sqrt{3}) \). Using this, \( \theta \approx \frac{\pi}{3} \) radians, since the tangent of \( 60^\circ \) or \( \frac{\pi}{3} \) is \( \sqrt{3} \).
04

Convert the radian measurement to degrees

To convert from radians to degrees, use the conversion formula: \( \theta_{degrees} = \theta_{radians} \times \frac{180}{\pi} \). Substituting, we get: \[ \theta_{degrees} = \frac{\pi}{3} \times \frac{180}{\pi} = 60^\circ \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Slope of a Line
The slope of a line is a crucial concept in geometry and algebra. It's the measure of the steepness or the incline of the line. When we talk about the slope, we're usually referring to the change in the vertical direction (often called the "rise") divided by the change in the horizontal direction (the "run"). In mathematical terms, the slope is denoted by \( m \), which is found in the line equation \( y = mx + b \). Here, \( m = \sqrt{3} \).

The slope tells us how much \( y \) changes for a unit change in \( x \).
  • If the slope is positive, the line inclines upwards as you move from left to right.
  • If the slope is negative, the line declines.
  • If the slope is zero, the line is horizontal.
  • The greater the absolute value of the slope, the steeper the line.
Understanding the slope is foundational in determining a line's behavior and properties, including its angle of inclination. This angle is essentially how tilted a line is relative to the x-axis in a coordinate system.
Exploring the Tangent Formula
The tangent formula plays a vital role in finding the angle of inclination of a line. Here, we use an important trigonometric principle: the tangent of an angle in a right triangle equals the opposite side over the adjacent side. In the context of a line on a graph, this corresponds to the rise and run, or more geometrically, to the slope of the line.

To find the angle of inclination \( \theta \), we use the formula \( \tan(\theta) = m \), where \( m \) is the slope.
  • This means that \( \theta = \tan^{-1}(m) \), which is the arctangent or inverse tangent.
  • For example, if the slope \( m = \sqrt{3} \), then \( \tan(\theta) = \sqrt{3} \).
  • This implies that \( \theta = \tan^{-1}(\sqrt{3}) \).
This calculation gives us the angle in radians initially. The value obtained from \( \tan^{-1} \) depending on the slope, not only determines the angle's size but also reflects how tilted the line is as it crosses through the Cartesian plane.
Radian to Degree Conversion
Often, angles are measured in radians, but we frequently need to convert these radians to degrees because degrees are more intuitive for most people. The formula for converting radians to degrees is straightforward: multiply by \( \frac{180}{\pi} \).
  • This conversion uses the fact that \( \pi \) radians equals 180 degrees.
  • For instance, if \( \theta \) is given as \( \frac{\pi}{3} \) radians, we find the degree measure by calculating \( \theta_{\text{degrees}} = \frac{\pi}{3} \times \frac{180}{\pi} \).
  • As a result, \( \theta_{\text{degrees}} = 60^{\circ} \).
This process ensures that we can express the angle of inclination in any unit needed for different applications, whether in mathematics, engineering, or everyday scenarios. Having a clear understanding of both radian and degree measures broadens the applications and interpretations of angle related problems.

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Most popular questions from this chapter

Graph the equations. $$3 x^{2}+10 x y+3 y^{2}-2 \sqrt{2} x+2 \sqrt{2} y-10=0$$

In this exercise you will look at the graph of the hyperbola \(16 x^{2}-9 y^{2}=144\) from two perspectives. (a) Solve the given equation for \(y,\) then graph the two resulting functions in the standard viewing rectangle. (b) Determine the equations of the asymptotes. Add the graphs of the asymptotes to your picture from part (a). (c) Looking at your picture from part (b), you can see that the hyperbola seems to be moving closer and closer to its asymptotes as \(|x|\) gets large. To see more dramatic evidence of this, change the viewing rectangle so that both \(x\) and \(y\) extend from -100 to \(100 .\) At this scale, the hyperbola is virtually indistinguishable from its asymptotes.

Graph the equations. $$x^{2}+4 x y+4 y^{2}=1$$

Determine the equation of the hyperbola satisfying the given conditions. Write each answer in the form \(A x^{2}-B y^{2}=\) Cor in the form \(A y^{2}-B x^{2}=C\). Length of the transverse axis \(6 ;\) length of the conjugate axis \(2 ;\) foci on the \(y\) -axis; center at the origin

Make the substitutions \(x=x^{\prime} \cos \theta-y^{\prime} \sin \theta\) and \(y=x^{\prime} \sin \theta+y^{\prime} \cos \theta\) in the equation\(A x^{2}+B x y+C y^{2}+D x+E y+F=0\) and show that the result is \(A^{\prime}\left(x^{\prime}\right)^{2}+B^{\prime} x^{\prime} y^{\prime}+C^{\prime}\left(y^{\prime}\right)^{2}+D^{\prime} x^{\prime}+E^{\prime} y^{\prime}+F^{\prime}=0\) where $$\begin{array}{l}A^{\prime}=A \cos ^{2} \theta+B \sin \theta \cos \theta+C \sin ^{2} \theta \\\B^{\prime}=2(C-A) \sin \theta \cos \theta+B\left(\cos ^{2} \theta-\sin ^{2} \theta\right) \\\C^{\prime}=A \sin ^{2} \theta-B \sin \theta \cos \theta+C \cos ^{2} \theta \\\D^{\prime}=D \cos \theta+E \sin \theta \\\E^{\prime}=E \cos \theta-D \sin \theta \\\F^{\prime}=F\end{array}$$

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