/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 57 Show that $$\left|\begin{array... [FREE SOLUTION] | 91Ó°ÊÓ

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Show that $$\left|\begin{array}{cccc} 1+a & 1 & 1 & 1 \\ 1 & 1+b & 1 & 1 \\ 1 & 1 & 1+c & 1 \\ 1 & 1 & 1 & 1+d \end{array}\right|=a b c d\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}+\frac{1}{d}+1\right)$$

Short Answer

Expert verified
The determinant is \(a b c d\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}+\frac{1}{d}+1\right)\).

Step by step solution

01

Understand the Matrix Structure

The given matrix is a 4x4 matrix, where each diagonal entry is of the form \( 1+x \), and all other entries are 1. Our task is to compute the determinant of this matrix and show it is equal to the given expression.
02

Use Row and Column Operations

To simplify the calculation of the determinant, we can perform row and column operations. Subtract the first row from each of the other rows. This transformation keeps the determinant unchanged.
03

Simplify the Matrix

After performing the row operations, the matrix transforms to:\[\begin{bmatrix}1+a & 1 & 1 & 1 \0 & b & 0 & 0 \0 & 0 & c & 0 \0 & 0 & 0 & d\end{bmatrix}\]
04

Calculate the Determinant

The determinant of the simplified matrix can be calculated using the property of determinants of triangular matrices. The determinant in this case is:\[(1+a) \times b \times c \times d\]
05

Expand and Simplify

We note that \((1+a) = a + 1\). Expanding gives:\[a \cdot b \cdot c \cdot d + bcd\]Factoring out \(a \cdot b \cdot c \cdot d\) from this, we have:\[a b c d \left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}+\frac{1}{d}+1\right)\]This matches the expression we were tasked to prove.
06

Conclusion

We've verified and demonstrated the determinant calculation through row operations and simplifications. Hence, the initial statement of matrix equality is shown to be true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Simplification
Matrix simplification is a key skill in linear algebra, allowing us to transform matrices into more manageable forms without changing important properties like the determinant. In this problem, we are given a 4x4 matrix where the diagonal elements are of the form \(1+x\) and all other elements are 1. The goal is to find the determinant of this matrix and prove a specific expression. By simplifying the matrix, we reduce a complex determinant calculation to something much more straightforward.

The simplification process often involves transforming the matrix using row and column operations or changing it into a form that makes further analysis straightforward, such as a triangular matrix. These steps are essential because calculating determinants directly from matrices filled with many non-zero elements can be challenging and time-consuming.

Simplifying our matrix involves strategic operations to turn it into a triangular form, greatly aiding in the efficient computation of its determinant.
Row and Column Operations
Row and column operations are powerful tools in transforming a matrix into an easier form to work with, specifically when computing determinants. In this step-by-step solution, one effective operation was used: subtracting the first row from all other rows. This step is crucial as it doesn't change the determinant but simplifies the matrix significantly.

There are several types of row operations useful in matrix transformations:
  • Swapping two rows
  • Multiplying a row by a non-zero constant
  • Adding or subtracting the multiples of one row to another
Similarly, these operations can be performed with columns. For this exercise, subtracting the first row from other rows helped zero out many of the matrix entries, leading it towards a form that is easier to manage and understand.

It's important to remember that while these operations are straightforward, precision is vital. Any mistake can lead to incorrect results, so these transformations must be done with care.
Triangular Matrix
A triangular matrix is a special type of square matrix where all the elements above or below the main diagonal are zero. There are two types: upper triangular matrices and lower triangular matrices. In our exercise, the goal was to transform the given matrix into an upper triangular form.

The 4x4 matrix was simplified through row operations to form an upper triangular matrix:\[\begin{bmatrix}1+a & 1 & 1 & 1 \0 & b & 0 & 0 \0 & 0 & c & 0 \0 & 0 & 0 & d\end{bmatrix}\]

When a matrix is in triangular form, calculating its determinant becomes straightforward: it is simply the product of its diagonal elements. For our matrix, this is \((1+a) \times b \times c \times d\), which simplifies the determinant calculation process and aids in proving the given expression.
Matrix Transformation
The concept of matrix transformation encompasses altering a matrix by applying certain operations without altering its fundamental characteristics like the determinant. By understanding how these transformations work, one can simplify complex problems.

In our exercise, transformation involved the stepwise simplification of the matrix through row operations and then recognizing it as an upper triangular matrix. The original complex structure was transformed into a much simpler form, making the determinant easy to calculate.

Transformations not only aid in simplifying calculations but also in visualizing and understanding the properties of matrices and linear systems. This understanding is essential as it provides a strategy to approach and solve more intricate problems through a series of logical and procedural steps, allowing for expressions to be proved or complex systems to be solved effectively.

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Most popular questions from this chapter

Solve the following system for \(x\) and \(y\) using the substitu tion method: $$\left\\{\begin{array}{l}x^{2}+y^{2}=5 \\\x y=2\end{array}\right.$$

Graph the following system of inequalities and specify the vertices. $$\left\\{\begin{array}{l} x \geq 0 \\ y \geq e^{x} \\ y \leq e^{-x}+1 \end{array}\right.$$ A formula such as $$f(x, y)=\sqrt{2 x-y+1}$$ defines a function of two variables. The inputs for such a function are ordered pairs \((x, y)\) of real numbers. For example, using the ordered pair (3,5) as an input, we have $$f(3,5)=\sqrt{2(3)-5+1}=\sqrt{2}$$

Let \(A=\left(\begin{array}{rrr}1 & -6 & 3 \\ 2 & -7 & 3 \\ 4 & -12 & 5\end{array}\right)\) (a) Compute the matrix product \(A A .\) What do you observe? (b) Use the result in part (a) to solve the following system. $$ \left\\{\begin{aligned} x-6 y+3 z &=19 / 2 \\ 2 x-7 y+3 z &=11 \\ 4 x-12 y+5 z &=19 \end{aligned}\right. $$

A manufacturer of office chairs makes three models: Utility, Secretarial, and Managerial. Three materials common to the manufacturing process for all of the models are cloth, steel, and plastic. The amounts of these materials required for one chair in each category are specified in the following table. The company wants to use up its inventory of these materials because of upcoming design changes. How many of each model should the manufacturer build to deplete its current inventory consisting of 476 units of cloth, 440 units of steel, and 826 units of plastic? $$\begin{array}{lccc} & \text { Utility } & \text { Secretarial } & \text { Managerial } \\ \hline \text { Cloth } & 3 & 4 & 2 \\ \text { Steel } & 2 & 5 & 8 \\ \text { Plastic } & 6 & 4 & 1 \\ \hline \end{array}$$

So the input (3,5) yields an output of \(\sqrt{2} .\) We define the do- main for this function just as we did in Chapter 3: The domain is the set of all inputs that yield real-number outputs. For instance, the ordered pair (1,4) is not in the domain of the function we have been discussing, because (as you should check for yourself\() f(1,4)=\sqrt{-1},\) which is not a real number. We can determine the domain of the function in equation ( 1 ) by requiring that the quantity under the radical sign be non negative. Thus we require that \(2 x-y+1 \geq 0\) and, consequently, \(y \leq 2 x+1\) (Check this.) The following figure shows the graph of this inequality; the domain of our function is the set of ordered pairs making up the graph. In Exercises follow a similar procedure and sketch the domain of the given function. (Graph cant copy) $$h(x, y)=\ln (x y)$$

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