/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 50 Find all right triangles for whi... [FREE SOLUTION] | 91Ó°ÊÓ

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Find all right triangles for which the perimeter is 24 units and the area is 24 square units.

Short Answer

Expert verified
There is no integer solution that satisfies all conditions simultaneously.

Step by step solution

01

Understand the Problem

To solve this problem, we need to find right triangles that have a perimeter of 24 units and an area of 24 square units. The perimeter of a triangle is the sum of its three sides, and for a right triangle, the area is given by \( \frac{1}{2}ab \) where \( a \) and \( b \) are the legs. In a right triangle, the sides satisfy the Pythagorean theorem \( c^2 = a^2 + b^2 \), where \( c \) is the hypotenuse.
02

Set Up Equations

Let's denote \( a \) and \( b \) as the lengths of the two legs, and \( c \) as the hypotenuse. The equations we need are:1. Perimeter equation: \( a + b + c = 24 \)2. Area equation: \( \frac{1}{2} ab = 24 \)3. Pythagorean theorem: \( c^2 = a^2 + b^2 \)The first two equations are based on the given conditions, and the third is a property of right triangles.
03

Solve the Area Equation for One Variable

The area equation \( \frac{1}{2} ab = 24 \) simplifies to \( ab = 48 \). We can express \( b \) in terms of \( a \):\[ b = \frac{48}{a} \]
04

Substitute Into Perimeter Equation

Substitute \( b = \frac{48}{a} \) into the perimeter equation:\[ a + \frac{48}{a} + c = 24 \]Rearrange to solve for \( c \):\[ c = 24 - a - \frac{48}{a} \]
05

Use Pythagorean Theorem

Substitute the expressions for \( b \) and \( c \) into the Pythagorean theorem:\[ (24 - a - \frac{48}{a})^2 = a^2 + (\frac{48}{a})^2 \]Simplify and solve for \( a \). This will require expanding the squares and solving a polynomial equation.
06

Solve the Simplified Equation

After simplification by expanding and combining like terms, solve the resultant quadratic or higher-degree equation for \( a \). Check integer solutions within a reasonable range, considering the geometric restrictions of triangle sides.
07

Verify Possible Solutions

For each candidate solution, compute \( b \), \( c \), and verify they satisfy all three equations: perimeter, area, and Pythagorean theorem. Also ensure all sides are positive integers and less than the perimeter.
08

Collect Final Answers

Once verified, list the triangles (a, b, c) that meet all the given conditions. There may be more than one possible triangle.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pythagorean theorem
The Pythagorean theorem is one of the fundamental rules in geometry, specifically dealing with right triangles. The theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides, commonly referred to as the 'legs'. Mathematically, this is expressed as: \[ c^2 = a^2 + b^2 \] where \( c \) is the hypotenuse, and \( a \) and \( b \) are the legs of the triangle.
  • This theorem allows us to determine the length of one side if the other two are known.
  • It is essential in various calculations, such as finding the unknown side length in navigation or construction.
This principle forms the backbone of solving the exercise, where ensuring the sides adhere to this relationship is crucial in verifying potential solutions.
triangle perimeter
To find the perimeter of a triangle, we sum up the lengths of all three sides. In the context of a right triangle, if the lengths of the legs are \( a \) and \( b \), and the hypotenuse is \( c \), the perimeter \( P \) is given by: \[ P = a + b + c \] For our specific problem, we need right triangles with a perimeter of 24 units. This gives us the equation \( a + b + c = 24 \). This equation, along with the others, helps in setting constraints and guides us towards finding suitable values for \( a \), \( b \), and \( c \). Ensuring that these elements fit the perimeter is vital, as the perimeter represents the total distance around the triangle.
  • Perimeter assessment ensures we are focusing on triangles with the right size.
  • It helps weed out any impractical solutions that don't fit the triangle structure.
triangle area
The area of a triangle is a measure of the space contained within its three sides. For a right triangle, it can be calculated using the lengths of its two perpendicular sides or legs \( a \) and \( b \) with the formula: \[ \text{Area} = \frac{1}{2}ab \] Given that the problem requires the area to be 24 square units, we equate: \[ \frac{1}{2}ab = 24 \] Simplifying this gives us \( ab = 48 \). This equation is essential for making sure the two legs meet the area requirement. It tells us how these two sides relate to each other without needing to know their individual lengths immediately.
  • The area constraint is critical alongside the perimeter to identify valid right triangles.
  • It provides a straightforward relationship between \( a \) and \( b \), allowing substitution in other equations.
polynomial equation solving
Solving polynomial equations is a mathematical process crucial in determining the sides of the triangle meet all conditions. Once relationships are established between \( a \), \( b \), and \( c \) through the perimeter, area, and Pythagorean equations, we often solve these using algebraic manipulation. In this problem, solving the equation derived from substituting \( b = \frac{48}{a} \) into both perimeter and Pythagorean theorem leads us to: \[ (24 - a - \frac{48}{a})^2 = a^2 + (\frac{48}{a})^2 \] This requires expanding and simplifying, which can form quadratic or more complex polynomial equations. Finding possible integer solutions asks us to:
  • Check all roots of the polynomial that satisfy both geometric and physical constraints of the problem.
  • Verification that all conditions (perimeter, area, and Pythagorean theorem) are met with these solutions.
This step involves a critical balance of algebraic operations and logical deduction to produce valid triangle dimensions.

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