/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 Compute the inverse matrix, if i... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Compute the inverse matrix, if it exists, using elementary row operations (as shown in Example 3 ). $$\left(\begin{array}{rrr} 2 & 1 & 3 \\ 4 & 5 & -7 \\ 2 & 1 & 3 \end{array}\right)$$

Short Answer

Expert verified
Matrix A is singular and does not have an inverse.

Step by step solution

01

Set Up the Augmented Matrix

To find the inverse of a matrix using elementary row operations, we start by setting up the augmented matrix consisting of the matrix itself and the identity matrix. This helps us track the series of operations. For matrix \( A \): \[ \left(\begin{array}{rrr|rrr} 2 & 1 & 3 & 1 & 0 & 0 \ 4 & 5 & -7 & 0 & 1 & 0 \ 2 & 1 & 3 & 0 & 0 & 1 \end{array}\right) \]
02

Attempt to Obtain an Upper Triangular Matrix

The next step is to perform row operations to transform the left side of the augmented matrix into an upper triangular form. Let's first make the elements below the first pivot (which is 2) in column 1 to be zero. Subtract row 1 from row 3: \( R_3 = R_3 - R_1 \). Subtract 2 times row 1 from row 2: \( R_2 = R_2 - 2R_1 \). This gives us: \[ \left(\begin{array}{rrr|rrr} 2 & 1 & 3 & 1 & 0 & 0 \ 0 & 3 & -13 & -2 & 1 & 0 \ 0 & 0 & 0 & -1 & 0 & 1 \end{array}\right) \]
03

Determine if the Matrix is Invertible

Notice that the entire third row became zero on the left side, indicating that the rank of the matrix is less than 3. Since we cannot form a complete identity matrix on the left, matrix \( A \) is singular and does not have an inverse.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Elementary Row Operations
When computing the inverse of a matrix, elementary row operations are fundamental. These operations are simple manipulations that we perform on the rows of a matrix. There are three types of elementary row operations:
  • Switching two rows.
  • Multiplying a row by a non-zero scalar.
  • Adding a multiple of one row to another row.
These operations are crucial because they allow us to transform a matrix into different forms, such as the identity matrix, which is essential when trying to determine the inverse.
By performing these operations, we can methodically simplify the matrix and change its form while preserving its essential properties. This is how we verify if the original matrix is invertible.
Augmented Matrix
The concept of an augmented matrix is instrumental when finding the inverse of a matrix using row operations. An augmented matrix combines two matrices into a single matrix representation. In the context of finding an inverse, we combine the original matrix with the identity matrix of the same size.
For example, if we have a 3x3 matrix, we augment it with a 3x3 identity matrix, resulting in a single matrix with 3 rows and 6 columns.
  • The left half contains the original matrix.
  • The right half contains the identity matrix.
This setup allows us to perform row operations simultaneously on both matrices. If we successfully transform the left matrix into the identity matrix, the right side will become the inverse if one exists. However, as shown in the solution, if we cannot achieve this transformation, it indicates that the matrix is singular.
Upper Triangular Matrix
An upper triangular matrix is a special form of a square matrix where all elements below the main diagonal are zero. When using row operations to find an inverse, one of the key steps is attempting to transform the matrix on the left side of the augmented matrix into an upper triangular form.
This transformation simplifies further operations, making it easier to assess the invertibility of the matrix.
  • It involves creating zeros below each leading entry, or pivot, in each column.
  • Once the upper triangular form is achieved, it helps in back substitution processes.
In our case, transforming the matrix didn't produce an upper triangular form beyond the first two rows. The entire third row turned to zero, revealing that the original matrix does not have the required full rank for an inverse, confirming it as singular.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Show that $$\left|\begin{array}{llll} a & 1 & 1 & 1 \\ 1 & a & 1 & 1 \\ 1 & 1 & a & 1 \\ 1 & 1 & 1 & a \end{array}\right|=(a-1)^{3}(a+3)$$

The matrices \(A, B, C, D, E, F,\) and \(G\) are defined as follows: $$ A=\left(\begin{array}{rr} 2 & 3 \\ -1 & 4 \end{array}\right) \quad B=\left(\begin{array}{rr} 1 & -1 \\ 3 & 0 \end{array}\right) \quad C=\left(\begin{array}{ll} 1 & 0 \\ 0 & 1 \end{array}\right) $$ $$\begin{aligned} &D=\left(\begin{array}{rrr} -1 & 2 & 3 \\ 4 & 0 & 5 \end{array}\right) \quad E=\left(\begin{array}{rr} 2 & 1 \\ 8 & -1 \\ 6 & 5 \end{array}\right)\\\ &F=\left(\begin{array}{rr} 5 & -1 \\ -4 & 0 \\ 2 & 3 \end{array}\right) \quad G=\left(\begin{array}{ll} 0 & 0 \\ 0 & 0 \\ 0 & 0 \end{array}\right) \end{aligned}$$ In each exercise, carry out the indicated matrix operations if they are defined. If an operation is not defined, say so. $$(A+B)+C$$

Let \(A=\left(\begin{array}{rrr}1 & -6 & 3 \\ 2 & -7 & 3 \\ 4 & -12 & 5\end{array}\right)\) (a) Compute the matrix product \(A A .\) What do you observe? (b) Use the result in part (a) to solve the following system. $$ \left\\{\begin{aligned} x-6 y+3 z &=19 / 2 \\ 2 x-7 y+3 z &=11 \\ 4 x-12 y+5 z &=19 \end{aligned}\right. $$

In this exercise, let's agree to write the coordinates \((x, y)\) of a point in the plane as the \(2 \times 1\) matrix \(\left(\begin{array}{l}x \\\ y\end{array}\right) .\) (a) Let \(A=\left(\begin{array}{rr}1 & 0 \\ 0 & -1\end{array}\right)\) and \(Z=\left(\begin{array}{l}x \\ y\end{array}\right) .\) Compute the ma- trix \(A Z .\) After computing \(A Z,\) observe that it represents the point obtained by reflecting \(\left(\begin{array}{l}x \\ y\end{array}\right)\) about the \(x\) -axis. (b) Let \(B=\left(\begin{array}{rr}-1 & 0 \\ 0 & 1\end{array}\right)\) and \(Z=\left(\begin{array}{l}x \\ y\end{array}\right) .\) Compute the ma- trix \(B Z\). After computing \(B Z\), observe that it represents the point obtained by reflecting \(\left(\begin{array}{l}x \\ y\end{array}\right)\) about the \(y\) -axis. (c) Let \(A, B,\) and \(Z\) represent the matrices defined in parts \((a)\) and \((b) .\) Compute the matrix \((A B) Z\) and then interpret it in terms of reflection about the axes.

A parabola \(y=a x^{2}+b x+c\) passes through the three points \((1,-2),(-1,0),\) and (2,3) (a) Write down a system of three linear equations that must be satisfied by \(a, b,\) and \(c\) (b) Solve the system in part (a). (c) With the values for \(a, b,\) and \(c\) that you found in part (b), use a graphing utility to draw the parabola \(y=a x^{2}+b x+c .\) Find a viewing rectangle that seems to confirm that the parabola indeed passes through the three given points. (d) Another way to check your result in part (b): Apply the quadratic regression option on a graphing utility after entering the three given data points \((1,-2),(-1,0),\) and \((2,3) .\) (This is a valid check because, in general, three noncollinear points determine a unique parabola.)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.