Chapter 10: Problem 13
Evaluate \(\left|\begin{array}{lll}1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 9\end{array}\right|\) by expanding it along (a) the second row; (b) the third row; (c) the first column; (d) the third column.
Short Answer
Expert verified
The determinant is 0 for all expansions.
Step by step solution
01
Co-factor Definition
The cofactor of an element in a matrix is calculated by removing the row and column of that element, then taking the determinant of the remaining matrix, and if needed, multiplying by \(-1\) depending on the element's position. For element \((i, j)\), the sign is given by \((-1)^{i+j}\).
02
Second Row Expansion
The second row of the matrix is \([4, 5, 6]\). The determinant can be expanded as:\[|A| = 4 \cdot C_{21} - 5 \cdot C_{22} + 6 \cdot C_{23}\]Where:- \(C_{21}\) is the determinant of \(\begin{vmatrix} 2 & 3 \ 8 & 9 \end{vmatrix} = 2 \cdot 9 - 3 \cdot 8 = 18 - 24 = -6\)- \(C_{22}\) is the determinant of \(\begin{vmatrix} 1 & 3 \ 7 & 9 \end{vmatrix} = 1 \cdot 9 - 3 \cdot 7 = 9 - 21 = -12\)- \(C_{23}\) is the determinant of \(\begin{vmatrix} 1 & 2 \ 7 & 8 \end{vmatrix} = 1 \cdot 8 - 2 \cdot 7 = 8 - 14 = -6\)Thus,\[|A| = 4(-6) - 5(-12) + 6(-6) = -24 + 60 - 36 = 0\]
03
Third Row Expansion
The third row of the matrix is \([7, 8, 9]\). The determinant can be expanded as:\[|A| = 7 \cdot C_{31} - 8 \cdot C_{32} + 9 \cdot C_{33}\]Where:- \(C_{31}\) is the determinant of \(\begin{vmatrix} 2 & 3 \ 5 & 6 \end{vmatrix} = 2 \cdot 6 - 3 \cdot 5 = 12 - 15 = -3\)- \(C_{32}\) is the determinant of \(\begin{vmatrix} 1 & 3 \ 4 & 6 \end{vmatrix} = 1 \cdot 6 - 3 \cdot 4 = 6 - 12 = -6\)- \(C_{33}\) is the determinant of \(\begin{vmatrix} 1 & 2 \ 4 & 5 \end{vmatrix} = 1 \cdot 5 - 2 \cdot 4 = 5 - 8 = -3\)Thus,\[|A| = 7(-3) - 8(-6) + 9(-3) = -21 + 48 - 27 = 0\]
04
First Column Expansion
The first column of the matrix is \([1, 4, 7]\). The determinant can be expanded as:\[|A| = 1 \cdot C_{11} - 4 \cdot C_{21} + 7 \cdot C_{31}\]Where:- \(C_{11}\) is the determinant of \(\begin{vmatrix} 5 & 6 \ 8 & 9 \end{vmatrix} = 5 \cdot 9 - 6 \cdot 8 = 45 - 48 = -3\)- \(C_{21}\) is the determinant of \(\begin{vmatrix} 2 & 3 \ 8 & 9 \end{vmatrix} = 2 \cdot 9 - 3 \cdot 8 = 18 - 24 = -6\)- \(C_{31}\) is the determinant of \(\begin{vmatrix} 2 & 3 \ 5 & 6 \end{vmatrix} = 2 \cdot 6 - 3 \cdot 5 = 12 - 15 = -3\)Thus,\[|A| = 1(-3) - 4(-6) + 7(-3) = -3 + 24 - 21 = 0\]
05
Third Column Expansion
The third column of the matrix is \([3, 6, 9]\). The determinant can be expanded as:\[|A| = 3 \cdot C_{13} - 6 \cdot C_{23} + 9 \cdot C_{33}\]Where:- \(C_{13}\) is the determinant of \(\begin{vmatrix} 4 & 5 \ 7 & 8 \end{vmatrix} = 4 \cdot 8 - 5 \cdot 7 = 32 - 35 = -3\)- \(C_{23}\) is the determinant of \(\begin{vmatrix} 1 & 2 \ 7 & 8 \end{vmatrix} = 1 \cdot 8 - 2 \cdot 7 = 8 - 14 = -6\)- \(C_{33}\) is the determinant of \(\begin{vmatrix} 1 & 2 \ 4 & 5 \end{vmatrix} = 1 \cdot 5 - 2 \cdot 4 = 5 - 8 = -3\)Thus,\[|A| = 3(-3) - 6(-6) + 9(-3) = -9 + 36 - 27 = 0\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cofactor Expansion
Cofactor expansion is a method used to compute the determinant of a matrix, particularly for square matrices. This technique involves choosing a row or a column and expanding the determinant along it.
The main idea is to express the determinant as a sum of products of elements and their respective cofactors. Each cofactor is determined by calculating the determinant of a smaller matrix, the minor, which is formed by excluding the chosen row and column of the specified element. Additionally, each element's cofactor is multiplied by \( -1 \) based on its position \( (i, j) \).
The main idea is to express the determinant as a sum of products of elements and their respective cofactors. Each cofactor is determined by calculating the determinant of a smaller matrix, the minor, which is formed by excluding the chosen row and column of the specified element. Additionally, each element's cofactor is multiplied by \( -1 \) based on its position \( (i, j) \).
- Select a row or column to expand along.
- Loop through each element of the chosen row or column.
- For each element, calculate its cofactor using its minor matrix.
- Combine all these products to get the determinant.
Minor Matrices
Minor matrices play a crucial role in determining the cofactors in cofactor expansion. The minor of an element is the determinant of the matrix formed by deleting the element's row and column.
Imagine a 3x3 matrix; if you need the minor of a specific element, you'll be left with a 2x2 matrix once you remove its row and column. Here's how that works:
Imagine a 3x3 matrix; if you need the minor of a specific element, you'll be left with a 2x2 matrix once you remove its row and column. Here's how that works:
- Identify the element whose minor is needed. Let's say this is element \( a_{ij} \).
- Eliminate the \( i^{th} \) row and the \( j^{th} \) column from the matrix.
- Compute the determinant of the resulting smaller matrix.
3x3 Matrix Determinants
Finding the determinant of a 3x3 matrix is often one of the first introductions to determinants for many students. It's a straightforward but essential step in understanding larger square matrix determinants.
A key method to compute it is the \'cofactor expansion\', typically over a row or a column. For a 3x3 matrix like the one in question, the process goes as follows:
A key method to compute it is the \'cofactor expansion\', typically over a row or a column. For a 3x3 matrix like the one in question, the process goes as follows:
- Choose any row or column to perform the expansion.
- Compute the determinants of the 2x2 minor matrices for each element.
- Multiply each element by its corresponding cofactor and the determinant of its minor matrix (considering the sign \( (-1)^{i+j} \)).
- Sum these products to get the determinant.