/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 The set of real numbers satisfyi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The set of real numbers satisfying the given inequality is one or more intervals on the number line. Show the interval(s) on a number line. $$|x-5| \geq 2$$

Short Answer

Expert verified
The solution is the intervals \((-\infty, 3] \cup [7, \infty)\) on the number line.

Step by step solution

01

Understand the Absolute Value Inequality

The given inequality is \(|x-5| \geq 2\). This implies that the distance between \(x\) and 5 on the number line is at least 2. In other words, \(x\) can be either 2 or more units to the right of 5, or 2 or more units to the left of 5.
02

Break Down the Inequality

Rewrite the inequality \(|x-5| \geq 2\) as two separate inequalities.\[x - 5 \geq 2 \quad \text{or} \quad x - 5 \leq -2\]These represent the two cases where the condition holds.
03

Solve the First Inequality

Solve the inequality \(x - 5 \geq 2\). Add 5 to both sides to find:\[x \geq 7\]This means one portion of the solution set is all numbers \(x\) greater than or equal to 7.
04

Solve the Second Inequality

Solve the inequality \(x - 5 \leq -2\). Add 5 to both sides to find:\[x \leq 3\]This indicates the other portion of the solution set is all numbers \(x\) less than or equal to 3.
05

Combine Solutions into Intervals

The two solution sets can be combined into two intervals:\(x \leq 3\) is the interval \((-\infty, 3]\).\(x \geq 7\) is the interval \([7, \infty)\).The complete solution is the union of these two intervals: \((-\infty, 3] \cup [7, \infty)\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Interval Notation
Interval notation is a method used to describe a set of numbers along the number line. It captures the beginning and end of intervals where the inequality holds true. For inequalities, where expressions are either greater than, less than, or between values, interval notation provides a concise way to represent these conditions.

For instance, in the original exercise, we determined that the solution to \(|x-5| \geq 2\) resulted in two separate intervals: one where \((x \leq 3)\) and another where \((x \geq 7)\). In interval notation, these are written as:
  • \((\-\infty, 3]\) — all numbers less than or equal to 3.
  • \([7, \infty)\) — all numbers greater than or equal to 7.
The solution set of the inequality is presented as the union of these intervals, which is \((\-\infty, 3] \cup [7, \infty)\). The union symbol \((\cup)\) signifies all the numbers that belong to either of these intervals. Using interval notation helps organize and simplify expressing solution sets in mathematics.
Solving Inequalities
To solve absolute value inequalities, you first need to understand what the absolute value represents. The absolute value \(|x - a|\) indicates the distance between the number \(x\) and another point \(a\) on the number line. Solving \(|x - 5| \geq 2\) means finding all values of \(x\) where the distance from 5 is at least 2.

Breaking down the inequality involves setting up two conditions because the absolute value function is always non-negative.
  • For \(x - 5 \geq 2\), solve for \(x\) to get \(x \geq 7\). This reveals numbers that are 2 units or more to the right of 5.
  • For \(x - 5 \leq -2\), solve for \(x\) to get \(x \leq 3\). This provides numbers that are 2 units or more to the left of 5.
The solutions to these inequalities give us the intervals that form the complete solution set. By combining them, you obtain the final solution in interval notation. The two resulting inequalities help ensure that \(x\) satisfies the original condition of being outside the range between 3 and 7.
Number Line Representation
A number line is a visual tool used to represent numbers and their relationships. When solving inequalities, drawing a number line can help you see where the solution sets lie and how they relate to each other. For absolute value inequalities like \(|x-5| \geq 2\), the number line becomes an especially valuable resource.

Start by plotting critical numbers from the solved inequalities; in this case, 3 and 7. These numbers indicate where the solution set begins or ends. Then shade the regions that satisfy each inequality:
  • Shade all numbers less than or equal to 3, moving leftwards, indicating the interval \((\-\infty, 3]\).
  • Shade all numbers greater than or equal to 7, moving rightwards, showing the interval \([7, \infty)\).
The number line thus provides a clear representation of how the solution comprises two separate regions, helping you understand the solution's layout intuitively. This visualization assists in verifying the intervals noted down and ensures that you have captured the essence of the inequality appropriately.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Graph the equation \(y=20 / x\) using a standard viewing rectangle. (b) Although both the \(x\) - and the \(y\) -axes are asymptotes for this curve, the graph in part (a) does not show this clearly. Take a second look, using a viewing rectangle that extends from -100 to 100 in both the \(x\) -and the \(y\) -directions. Note that the curve indeed appears indistinguishable from an asymptote when either \(|x|\) or \(|y|\) is sufficiently large.

(a) Sketch the line \(y=\frac{1}{2} x-5\) and the point \(P(1,3) .\) Follow parts (b)-(d) to calculate the perpendicular distance from point \(P(1,3)\) to the line. (b) Find an equation of the line that passes through \(P(1,3)\) and is perpendicular to the line \(y=\frac{1}{2} x-5\) (c) Find the coordinates of the point where these two lines intersect. Hint: From intermediate algebra, to find where two lines \(y=m x+b\) and \(y=M x+B\) intersect, set the expressions \(m x+b\) and \(M x+B\) equal to each other, and solve for \(x\) (d) Use the distance formula to find the perpendicular distance from \(P(1,3)\) to the line \(y=\frac{1}{2} x-5\)

The endpoints of a line segment \(\overline{A B}\) are given. Sketch the reflection of \(\overline{A B}\) about (a) the \(x\) -axis; (b) the \(y\) -axis; and (c) the origin. \(A(-2,-2)\) and \(B(0,0)\)

Determine the center and the radius for the circle. Also, find the \(y\) -coordinates of the points (if any) where the circle intersects the \(y\) -axis. $$4 x^{2}-4 x+4 y^{2}-63=0$$

(a), three points \(A, B,\) and \(C\) are specified. Determine whether \(A, B\), and C are collinear (lie on the same line) by checking to see whether the slope of \(\overline{A B}\) equals the slope of \(\overline{B C}\). $$A(-8,-2) ; B\left(2, \frac{1}{2}\right) ; C(11,-1)$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.