Chapter 1: Problem 54
Solve each equation for \(x\) in terms of the other letters. $$\frac{1}{a x}=\frac{1}{b x}-\frac{1}{c}$$
Short Answer
Expert verified
Use the quadratic formula after simplifying: \(x = \frac{-bc \pm \sqrt{b^2c^2 + 4a^2bc}}{2ab}\).
Step by step solution
01
Get a common denominator on the right-hand side
We start by finding a common denominator for the right-hand side of the equation: \( \frac{1}{b x} - \frac{1}{c} \). The common denominator is \(bxc\). This makes the equation: \( \frac{c}{bcx} - \frac{bx}{bcx} \).
02
Combine the fractions on the right-hand side
Combine the fractions on the right-hand side: \(\frac{c}{bcx} - \frac{bx}{bcx} = \frac{c - bx}{bcx} \). Now the equation is \(\frac{1}{a x} = \frac{c - bx}{bcx}\).
03
Cross-multiply to eliminate fractions
Cross-multiply to get rid of the fractions: \(bcx = ax(c - bx)\).
04
Distribute on the right-hand side
Distribute \(ax\) on the right-hand side of the equation: \(bcx = axc - abx^2\).
05
Rearrange the equation
Rearrange the equation so all terms involving \(x\) are on one side: \( abx^2 + bcx - axc = 0 \).
06
Use the quadratic formula
This is a quadratic equation in the form \(Ax^2 + Bx + C = 0\), where \(A = ab\), \(B = bc\), and \(C = -ac\). Use the quadratic formula: \(x = \frac{-B \pm \sqrt{B^2 - 4AC}}{2A}\). Substitute \(A = ab\), \(B = bc\), \(C = -ac\) into the formula.
07
Substitute values into the quadratic formula
Substitute into the quadratic formula: \(x = \frac{-bc \pm \sqrt{(bc)^2 - 4(ab)(-ac)}}{2ab}\). Simplify this expression to get the value of \(x\) in terms of the other letters.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross-Multiplication
Cross-multiplication is a powerful technique often used to solve equations that involve fractions. When you have an equation with two fractions set equal to each other, you can use cross-multiplication to simplify the equation and remove the fractions. This is especially helpful when dealing with algebraic expressions where solving for a variable is necessary.
For instance, if you have an equation in the form \(\frac{a}{b} = \frac{c}{d}\), you can cross-multiply to get \(a \times d = b \times c\).
In the original exercise, after obtaining a single fraction on each side of the equation, we cross-multiplied to eliminate the fractions completely. This step is crucial because it simplifies the equation from a complex fraction form to a more manageable algebraic expression.
For instance, if you have an equation in the form \(\frac{a}{b} = \frac{c}{d}\), you can cross-multiply to get \(a \times d = b \times c\).
In the original exercise, after obtaining a single fraction on each side of the equation, we cross-multiplied to eliminate the fractions completely. This step is crucial because it simplifies the equation from a complex fraction form to a more manageable algebraic expression.
Fractions in Equations
Solving equations with fractions involves understanding how to manipulate and simplify fractions to get a clear solution. Fractions can make equations seem complicated, but with the right approach, they can become much simpler. Let's break down the steps:
- Identify a common denominator: Look for a common denominator to combine fractions on one side of the equation. This helps when dealing with multiple fractions as it simplifies the operation.
- Combine fractions: Use the common denominator to rewrite and combine the fractions into a single fraction. This reduces the complexity of the equation.
- Eliminate the fraction: Often, you can multiply both sides by the denominator to get rid of the fraction, making the equation a ‘normal’ equation.
Quadratic Formula
The quadratic formula is an essential tool for solving quadratic equations. A quadratic equation is typically in the form \(Ax^2 + Bx + C = 0\). Solving such an equation involves finding the value(s) of \(x\) that make the equation true.
The quadratic formula is:
x = \( \frac{-B \pm \sqrt{B^2 - 4AC}}{2A} \)
Here's how to use it:
The quadratic formula is:
x = \( \frac{-B \pm \sqrt{B^2 - 4AC}}{2A} \)
Here's how to use it:
- First, identify coefficients \(A\), \(B\), and \(C\) from the equation. Make sure the equation is in the standard quadratic form.
- Substitute these values into the quadratic formula.
- Solve for \(x\) using calculation for the square root and the division.