/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 Solve each equation for \(x\) in... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each equation for \(x\) in terms of the other letters. $$\frac{1}{x}=a+b$$

Short Answer

Expert verified
\( x = \frac{1}{a + b} \)

Step by step solution

01

Identify the Given Equation

The given equation is \( \frac{1}{x} = a + b \), where we need to solve for \( x \) in terms of \( a \) and \( b \).
02

Clear the Fraction

To eliminate the fraction, multiply both sides of the equation by \( x \). This gives us \( 1 = (a + b)x \).
03

Isolate the Variable x

Divide both sides of the equation by \( a + b \) to solve for \( x \). This results in \( x = \frac{1}{a + b} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Algebra: Understanding the Basics
Algebra is a branch of mathematics dealing with symbols and the rules for manipulating those symbols. It's like a language that helps us represent problems and solve equations systematically.
In algebra, we often use letters such as \( x \), \( a \), and \( b \) to stand for numbers. These letters are called variables. They enable us to create expressions and equations that can describe a wide variety of problems and scenarios.When working with algebraic expressions and equations, the goal is often to isolate one variable, solving it in terms of others. This involves applying different algebraic rules and operations, such as addition, subtraction, multiplication, and division. Remember, keeping each side of an equation balanced is crucial. Every operation you perform on one side must also be performed on the other. This ensures the equation remains true.
Fraction Elimination: Simplifying Equations
A common challenge in algebra is dealing with equations that contain fractions. These can make otherwise simple equations seem complicated. But, with a few techniques, we can eliminate fractions with ease.
To clear a fraction, find the least common denominator or use multiplication. For example, if you have the equation \( \frac{1}{x} = a + b \), multiplying both sides by \( x \) will cancel out the fraction, simplifying the equation to \( 1 = (a + b)x \).
By multiplying both sides by the variable in the denominator (in this case, \( x \)), you effectively "clear" the fraction. This step is often crucial in making the equation easier to solve. Always double-check that the operation is valid and won't lead to division by zero. This can happen if the variable you multiply by turns out to be zero.
Variable Isolation: Solving for the Unknown
Once fractions are cleared from an equation, the next step is to isolate the variable you need to solve for. This process involves rearranging the equation until the variable is alone on one side.
In our equation \( 1 = (a + b)x \), the next step is to get \( x \) by itself. This requires dividing both sides by \( a + b \). This operation reveals our solution: \( x = \frac{1}{a + b} \). The key here is to ensure that you perform arithmetic operations correctly and apply them to both sides of the equation. Variable isolation is often the final step in solving an algebraic equation. Once isolated, you have expressed the unknown variable in terms of other known variables or constants in the problem. This is the point at which the problem is considered solved unless additional steps are specified.

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Most popular questions from this chapter

Rewrite each statement using absolute value notation, as in Example 5. The number \(y\) is less than three units from the origin.

Find an equation for the line that is described, and sketch the graph. Write the final answer in the form \(y=m x+b ;\) (a) Passes through (-3,-1) and has slope 4 (b) Passes through \((5 / 2,0)\) and has slope \(1 / 2\) (c) Has \(x\) -intercept 6 and \(y\) -intercept 5 (d) Has \(x\) -intercept -2 and slope \(3 / 4\) (e) Passes through (1,2) and (2,6)

In each of parts (a) through (d), first solve the equation for \(y\) so that you can enter it in your graphing utility. Then use the graphing utility to graph the equation in an appropriate viewing rectangle. In each case, the graph is a line. Given that the \(x\) - and \(y\) -intercepts are (in every case here) integers, read their values off the screen and write them down for easy reference when you get to part (e). (a) \(\frac{x}{2}+\frac{y}{3}=1\) (c) \(\frac{x}{6}+\frac{y}{5}=1\) (b) \(\frac{x}{-2}+\frac{y}{-3}=1\) (d) \(\frac{x}{-6}+\frac{y}{-5}=1\) (e) On the basis of your results in parts (a) through (d), describe, in general, the graph of the equation \(\frac{x}{a}+\frac{y}{b}=1,\) where \(a\) and \(b\) are nonzero constants.

In parts (a) and (b), sketch the interval or intervals corresponding to the given inequality: (a) \(|x-2|<1\) (b) \(0<|x-2|<1\) (c) In what way do your answers in (a) and (b) differ? (The distinction is important in the study of limits in calculus.)

Use a graphing utility to graph the equations and to approximate the \(x\) -intercepts. In approximating the \(x\) -intercepts, use a "solve" key or a sufficiently magnified view to ensure that the values you give are correct in the first three decimal places. Remark: None of the \(x\) -intercepts for these four equations can be obtained using factoring techniques.) $$y=8 x^{3}-6 x-1$$

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