/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Solve each equation. $$\frac{1... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each equation. $$\frac{1}{x-3}-\frac{2}{x+3}=\frac{1}{x^{2}-9}$$

Short Answer

Expert verified
The solution is \(x = 8\).

Step by step solution

01

Identify the Denominator

The equation involves fractions with denominators of \(x - 3\), \(x + 3\), and \(x^2 - 9\). Notice that \(x^2 - 9\) factors into \((x - 3)(x + 3)\). We'll use this to find a common denominator.
02

Find the Least Common Denominator (LCD)

The least common denominator of the fractions is \((x - 3)(x + 3)\) because \(x^2 - 9 = (x - 3)(x + 3)\). We will rewrite each fraction in the equation to have this common denominator.
03

Rewrite Fractions with the LCD

Rewrite each term of the equation with the common denominator: - Multiply \(\frac{1}{x-3}\) by \(\frac{x+3}{x+3}\), resulting in \(\frac{x+3}{(x-3)(x+3)}\).- Multiply \(\frac{2}{x+3}\) by \(\frac{x-3}{x-3}\), resulting in \(\frac{2(x-3)}{(x-3)(x+3)}\).- The third fraction \(\frac{1}{x^2 - 9}\) already has the common denominator.
04

Combine Fractions

Now that all fractions have the same denominator, combine them:\[\frac{x+3 - 2(x-3)}{(x-3)(x+3)} = \frac{1}{(x-3)(x+3)}\].Simplify the numerator: \[x + 3 - 2x + 6 = -x + 9\], leading to: \[\frac{-x + 9}{(x-3)(x+3)} = \frac{1}{(x-3)(x+3)}\].
05

Solve the Numerator Equation

Set the numerators equal to each other, since the denominators are identical:\(-x + 9 = 1\).Solve for \(x\):Subtract 9 from both sides: \(-x = -8\),Multiply both sides by -1: \(x = 8\).
06

Verify the Solution

Check if \(x = 8\) is a valid solution. Substitute \(x = 8\) into the original denominators:- \(x - 3 = 5\)- \(x + 3 = 11\)- \((x - 3)(x + 3) = 55\)Since none of these are zero, \(x = 8\) is a valid solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Common Denominator
To solve rational equations, finding a common denominator is essential. A common denominator is simply a shared denominator among all the fractions involved in an equation. This allows the fractions to be combined or compared easily. In our example, the denominators are \(x - 3\), \(x + 3\), and \(x^2 - 9\). The expression \(x^2 - 9\) is particularly interesting because it can be factored into \((x - 3)(x + 3)\). Thus, the least common denominator (LCD) for all the terms is \((x - 3)(x + 3)\). By identifying this common denominator, we can adjust each fraction so they can be combined into a single equation for easier solving.
Common denominators are a backbone to solving equations with multiple fractions and are key to simplifying complex rational expressions.
Fraction Operations
Once we identify the common denominator, the next step involves performing fraction operations. This means adjusting each fraction in the equation so they all have the common denominator \((x - 3)(x + 3)\).
To do this, we multiply each fraction by a form of 1 that will give them the needed denominator:
  • For \(\frac{1}{x-3}\), multiply by \(\frac{x+3}{x+3}\), resulting in \(\frac{x+3}{(x-3)(x+3)}\).
  • For \(\frac{2}{x+3}\), multiply by \(\frac{x-3}{x-3}\), resulting in \(\frac{2(x-3)}{(x-3)(x+3)}\).
  • The fraction \(\frac{1}{x^2 - 9}\) is already in terms of our common denominator.
These operations are crucial as they transform distinct fractions into comparable forms and allow us to move toward solving the equation effectively.
Factoring
Factoring is a vital skill in working with rational equations. It involves breaking down an expression into simpler components—or factors—that are multiplied together. In our exercise, recognizing that \(x^2 - 9\) can be factored into \((x - 3)(x + 3)\) was pivotal.
This type of expression is known as a difference of squares, which has a general form of \(a^2 - b^2 = (a - b)(a + b)\).
By factoring, we simplify complex expressions and find common components among terms, which helps in matching denominators. This not only simplifies the process of finding a common denominator but also aids in solving equations by setting the stage for possible cancellation or simplification of terms.
Verification
Verification is the final crucial step in ensuring our solution is correct and valid. After finding a solution for the variable, here \(x = 8\), we substitute it back into the original equation to confirm it satisfies all parts of the equation.
Here's how:
  • Substitute \(x = 8\) into the expressions \(x - 3\), \(x + 3\), and \((x - 3)(x + 3)\) to make sure none equals zero, since a zero denominator is undefined.
  • Check that substituting \(x = 8\) returns equal values on both sides of the equation.
Performing these checks guarantees the solution doesn't produce a mathematical contradiction or invalid scenario. This step is vital in not only ensuring the mathematical correctness but also confirming the solution's practical viability. Verification solidifies that our journey through finding a solution was accurate and meaningful.

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Most popular questions from this chapter

Find an equation for the line that is described. Write the answer in the two forms \(y=m x+b\) and \(A x+B y+C=0\). Is parallel to \(2 x-5 y=10\) and passes through (-1,2)

(a) Use a graphing utility to graph the equation. (b) Use a graphing utility, as in Example \(5,\) to estimate to one decimal place the \(x\) -intercepts. (c) Use algebra to determine the exact values for the \(x\) -intercepts. Then use a calculator to check that the answers are consistent with the estimates obtained in part (b). $$y=2 x^{3}-5 x$$

Use a graphing utility to graph the equations and to approximate the \(x\) -intercepts. In approximating the \(x\) -intercepts, use a "solve" key or a sufficiently magnified view to ensure that the values you give are correct in the first three decimal places. Remark: None of the \(x\) -intercepts for these four equations can be obtained using factoring techniques.) $$y=x^{5}-6 x^{4}+3$$

In each of parts (a) through (d), first solve the equation for \(y\) so that you can enter it in your graphing utility. Then use the graphing utility to graph the equation in an appropriate viewing rectangle. In each case, the graph is a line. Given that the \(x\) - and \(y\) -intercepts are (in every case here) integers, read their values off the screen and write them down for easy reference when you get to part (e). (a) \(\frac{x}{2}+\frac{y}{3}=1\) (c) \(\frac{x}{6}+\frac{y}{5}=1\) (b) \(\frac{x}{-2}+\frac{y}{-3}=1\) (d) \(\frac{x}{-6}+\frac{y}{-5}=1\) (e) On the basis of your results in parts (a) through (d), describe, in general, the graph of the equation \(\frac{x}{a}+\frac{y}{b}=1,\) where \(a\) and \(b\) are nonzero constants.

Find the \(x\) - and \(y\) -intercepts of the line, and find the area and the perimeter of the triangle formed by the line and the axes. (a) \(3 x+5 y=15\) (b) \(3 x-5 y=15\)

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