Chapter 8: Problem 3
For each pair of matrices \(A\) and \(B\) find the following, if defined \- \(3 A\) \- \(-B\) \- \(A^{2}\) \- \(A-2 B\) \- \(A B\) \- \(B A\) $$ A=\left[\begin{array}{rr} -1 & 3 \\ 5 & 2 \end{array}\right], B=\left[\begin{array}{rrr} 7 & 0 & 8 \\ -3 & 1 & 4 \end{array}\right] $$
Short Answer
Step by step solution
Calculate 3A
Calculate -B
Attempt to Calculate A²
Calculate A - 2B
Check AB
Check BA
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Matrix Multiplication
For the multiplication to be defined, the number of columns in the first matrix must equal the number of rows in the second matrix. For example, if matrix \(A\) is a \(2 \times 2\) matrix and matrix \(B\) is a \(2 \times 3\) matrix, the product \(AB\) is possible and it results in a \(2 \times 3\) matrix.
Here's how it works step-by-step:
- Take each row from the first matrix.
- Multiply it by each column of the second matrix.
- Add up the results to get each element of the new matrix.
Matrix Subtraction
The operation is quite straightforward—subtract each element of the second matrix from the corresponding element in the first matrix.
- Ensure both matrices have identical dimensions.
- Subtract corresponding elements: if matrix \(A = \begin{bmatrix} a_{1} & a_{2} \ a_{3} & a_{4} \end{bmatrix}\) and matrix \(B = \begin{bmatrix} b_{1} & b_{2} \ b_{3} & b_{4} \end{bmatrix}\), then \(A - B = \begin{bmatrix} a_{1} - b_{1} & a_{2} - b_{2} \ a_{3} - b_{3} & a_{4} - b_{4} \end{bmatrix}\).
Scalar Multiplication
Here's the simple process for scalar multiplication:
- Take the scalar, which is just a number, say \(-1\) or \(3\).
- Multiply this scalar by each element in the matrix. If matrix \(A\) is \(\begin{bmatrix} a & b \ c & d \end{bmatrix}\) and the scalar is 2, then the result is \(\begin{bmatrix} 2a & 2b \ 2c & 2d \end{bmatrix}\).
Matrix Squaring
Here's how to do it:
- Multiply the matrix by itself using the regular matrix multiplication process.
- If matrix \(A\) is \(\begin{bmatrix} -1 & 3 \ 5 & 2 \end{bmatrix}\), then \(A^2 = A \times A\).