/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 Sketch the graph of \(y=g(x)\) b... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the graph of \(y=g(x)\) by starting with the graph of \(y=f(x)\) and using transformations. Track at least three points of your choice and the horizontal asymptote through the transformations. State the domain and range of \(g\). . \(f(x)=10^{x}, g(x)=10^{\frac{x+1}{2}}-20\)

Short Answer

Expert verified
Domain of \(g(x)\) is all real numbers; range is \((-20, \infty)\).

Step by step solution

01

Identify Starting Function

The starting function is the exponential function \(f(x) = 10^x\). This is a standard exponential curve that passes through the point (0, 1) and has a horizontal asymptote at \(y = 0\). The domain of \(f(x)\) is all real numbers, and the range is \((0, \infty)\).
02

Horizontal Compression and Shift Right

The function \(g(x) = 10^{\frac{x+1}{2}} - 20\) involves the transformation of \(f(x)\). Start with the expression \(10^{\frac{x+1}{2}}\). This represents a horizontal shift and compression. \(x + 1\) indicates a shift 1 unit to the left, and the division by 2 represents a horizontal compression by a factor of 2. Track the point (0,1) to see how it shifts.
03

Vertical Shift Down

Next, observe the transformation \(10^{\frac{x+1}{2}} - 20\). This subtracts 20 from all y-coordinates, effectively shifting the graph vertically downward by 20 units. Track the transformed point from \(Step 2\).
04

Track Specific Points & Asymptote

Track another point, for example, \((1, 10)\) on \(f(x)\), which transforms to \((-1, 10)\) after the shift, and \((-1, -10)\) after the vertical shift. Similarly, track point \((-1, 0.1)\) in \((x+1)/2)\)\to \((-3, 10^{(-.5)})\) and finally \((-3, 10^{(-.5)}-20)\). The horizontal asymptote of \(f(x)\), \(y=0\), transforms into \(y=-20\) after the vertical shift.
05

Determine Domain and Range

The domain of \(g(x)\) remains all real numbers since the starting function \(f(x)\) is defined for all \(x\). The range shifts downward by 20 units, so the range of \(g(x)\) is \((-20, \infty)\), because the exponential part can still take any positive value, reduced by 20.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Function
An exponential function is one of the fundamental types of mathematical functions. In our exercise, the function is given by \[ f(x) = 10^x \] Exponential functions are known for their characteristic curve, which lies above the x-axis and increases rapidly. The graph of \( f(x) = 10^x \) passes through the point \( (0, 1) \), which is a key feature of exponential curves because any number (other than zero) raised to the power of zero is 1.
  • The graph has a horizontal asymptote at \( y = 0 \), which means as x approaches negative infinity, the graph approaches the x-axis but never quite touches it.
  • The domain of the function is all real numbers \( (-\infty, \infty) \).
  • The range of \( f(x) \) is \( (0, \infty) \), meaning that as \( x \) moves from negative to positive values, \( f(x) \) starts from close to zero and grows towards infinity.
Horizontal Compression
A horizontal compression involves adjusting the x-values to squeeze the graph of the function closer together along the horizontal axis. In our transformation, the function \[ g(x) = 10^{\frac{x+1}{2}} \] incorporates a horizontal compression alongside a horizontal shift. The algebraic manipulation of \( \frac{x+1}{2} \) causes these transformations.
  • First, the \( x+1 \) means each point is moved 1 unit to the left.
  • Second, dividing by 2 results in a compression by a factor of 2. This increases the speed with which \( g(x) \) reaches its maximum values compared to \( f(x) \).
Tracking a point like \( (0, 1) \), this transformation shifts it to \( (-1, 10^{(\frac{1}{2})}) = (-1, \sqrt{10}) \). This point reflects the compressed nature of \( g(x) \).
Vertical Shift
Vertical shifts involve moving the graph up or down along the y-axis without altering its shape. For \[ g(x) = 10^{\frac{x+1}{2}} - 20 \] there is a vertical shift downward by 20 units as shown by the \( -20 \) in the equation.
  • This shift moves every point down by 20. Therefore, a point like \( (0, \sqrt{10}) \) moves to \( (0, \sqrt{10} - 20) \).
  • More importantly, the horizontal asymptote of \( y = 0 \) shifts to \( y = -20 \).
A vertical shift does not affect the domain but does change the range significantly. The function now appears lower on the graph but retains its exponential rise.
Domain and Range
The domain and range of a function describe the set of possible input (x-values) and output (y-values) respectively. For our original function \[ f(x) = 10^x \], the domain is all real numbers \( (-\infty, \infty) \), indicating that you can input any real number into the function. The range is \( (0, \infty) \), meaning the outputs are always positive. For the transformed function \[ g(x) = 10^{\frac{x+1}{2}} - 20 \], the domain remains \( (-\infty, \infty) \). This is because transformations like shifts and compressions don't limit or expand the input possibilities. However, the range changes. Since we have a vertical shift downward by 20:
  • The new range of \( g(x) \) is \( (-20, \infty) \).
  • This implies \( g(x) \) can still reach any value above \(-20\), but never reach or drop below \( -20 \).
Understanding the domain and range in these transformations helps ensure we know the limits and extent of the function's behavior.

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