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In Exercises \(1-33,\) solve the equation analytically. $$ 2^{\left(x^{3}-x\right)}=1 $$

Short Answer

Expert verified
The solutions are \(x = 0, 1, -1\).

Step by step solution

01

Understand the Equation

The equation given is \(2^{(x^3-x)} = 1\). In this expression, any number raised to the power of zero is 1, so we can assume that the exponent must equal zero.
02

Set the Exponent to Zero

Since \(2^{(x^3-x)} = 1\), we set the exponent equal to zero: \(x^3 - x = 0\).
03

Factor the Equation

To solve \(x^3 - x = 0\), we can factor out an \(x\) from the terms: \(x(x^2 - 1) = 0\).
04

Further Factorization

Notice that \(x^2 - 1\) is a difference of squares. Thus, \(x^2 - 1 = (x - 1)(x + 1)\). Substitute this back into the factored form: \(x(x - 1)(x + 1) = 0\).
05

Solve for x

Using the zero-product property, set each factor equal to zero: \(x = 0\), \(x - 1 = 0\), and \(x + 1 = 0\). Solving these gives the solutions \(x = 0, 1, -1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring
Factoring is a powerful technique to simplify polynomial equations. When you have an equation like \(x^3 - x = 0\), the goal is to express it as a product of simpler factors. You can often factor out the greatest common factor first. In this case, you can factor out \(x\), leading to \(x(x^2 - 1) = 0\).

But don't stop there! Once you have pulled out a common factor, examine if any remaining polynomials can be factored further. We saw that the expression \(x^2 - 1\) is a special case that can also be factored, which leads us into another factoring technique called the difference of squares. The entire factored equation then becomes \(x(x-1)(x+1) = 0\). This breaks things down into simpler, more solvable parts.
Zero-Product Property
The zero-product property is a fundamental principle used in solving equations that have been factored. This property tells us that if a product of several factors equals zero, at least one of the factors must be zero.

Using the zero-product property on our factored polynomial equation, \(x(x-1)(x+1) = 0\), means setting each factor equal to zero:
  • \(x = 0\)
  • \(x - 1 = 0\) which gives \(x = 1\)
  • \(x + 1 = 0\) which gives \(x = -1\)
Applying this property allows us to find the roots of the equation, providing real solutions: \(x = 0, 1, -1\). It's a straightforward way to solve complex equations after factoring!
Difference of Squares
The difference of squares is a specific factoring technique that helps simplify certain types of quadratic expressions. You use it when you have a term in the form of \(a^2 - b^2\). It can be factored into \((a - b)(a + b)\).

In our exercise, \(x^2 - 1\) is a classic example of a difference of squares since it can be rewritten as \((x)^2 - (1)^2\). By factoring this as \((x - 1)(x + 1)\), we break down a quadratic into two linear factors. This kind of factoring simplifies solving for solutions by reducing higher-degree polynomials into expressions that can be set separately to zero.

Recognizing and applying the difference of squares enhances your ability to solve complex equations more efficiently and is a key tool in algebra.

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Most popular questions from this chapter

For each of the scenarios given in Exercises \(1-6\), \- Find the amount \(A\) in the account as a function of the term of the investment \(t\) in years. \- Determine how much is in the account after 5 years, 10 years, 30 years and 35 years. Round your answers to the nearest cent. \- Determine how long will it take for the initial investment to double. Round your answer to the nearest year. \- Find and interpret the average rate of change of the amount in the account from the end of the fourth year to the end of the fifth year, and from the end of the thirty-fourth year to the end of the thirty-fifth year. Round your answer to two decimal places. $$\$ 5000\( is invested in an account which offers \)2.125 \%$, compounded continuously.

For each of the scenarios given in Exercises \(1-6\), \- Find the amount \(A\) in the account as a function of the term of the investment \(t\) in years. \- Determine how much is in the account after 5 years, 10 years, 30 years and 35 years. Round your answers to the nearest cent. \- Determine how long will it take for the initial investment to double. Round your answer to the nearest year. \- Find and interpret the average rate of change of the amount in the account from the end of the fourth year to the end of the fifth year, and from the end of the thirty-fourth year to the end of the thirty-fifth year. Round your answer to two decimal places. $$\$ 1000$$ is invested in an account which offers \(1.25 \%\), compounded monthly.

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