/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 Use the properties of logarithms... [FREE SOLUTION] | 91Ó°ÊÓ

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Use the properties of logarithms to write the expression as a single logarithm. $$ \frac{1}{2} \log _{3}(x)-2 \log _{3}(y)-\log _{3}(z) $$

Short Answer

Expert verified
The expression simplifies to \( \log_3\left(\frac{\sqrt{x}}{y^2 z}\right) \).

Step by step solution

01

Apply the Power Rule of Logarithms

The power rule of logarithms states that \( a \log_b(M) = \log_b(M^a) \). We apply this rule to each term. For the first term \( \frac{1}{2} \log_3(x) \), it becomes \( \log_3(x^{1/2}) \). For the second term \(-2 \log_3(y) \), it becomes \( \log_3(y^{-2}) \). The third term \( -\log_3(z) \) is already in a suitable form, equivalent to \( \log_3(z^{-1}) \).
02

Write the Expression as a Single Logarithm

Using the properties of logarithms, specifically the law that states \( \log_b(M) - \log_b(N) = \log_b(\frac{M}{N}) \), we can combine the terms into a single logarithm. Start by combining the terms: \( \log_3(x^{1/2}) + \log_3(y^{-2}) + \log_3(z^{-1}) \). This becomes \( \log_3(x^{1/2} \cdot y^{-2} \cdot z^{-1}) \).
03

Simplify the Expression

This final single logarithm is \( \log_3\left(\frac{\sqrt{x}}{y^2 z}\right) \). We raised each applicable term inside the logarithm accordingly using exponent rules and concluded with the simplification of the product into a single fraction inside the logarithm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule of Logarithms
The power rule of logarithms helps to transform logarithmic equations where coefficients are involved. This rule states that if you have a logarithm written as \( a \log_b(M) \), you can effectively bring the coefficient \( a \) into the argument as an exponent, creating \( \log_b(M^a) \). This is extremely helpful when working to simplify or combine logarithmic expressions.

In our example, the expression \( \frac{1}{2} \log_3(x) \) can be transformed using the power rule. We bring the coefficient \( \frac{1}{2} \) as the exponent of \( x \) inside the logarithm, creating \( \log_3(x^{1/2}) \). Similarly, for \( -2 \log_3(y) \), the coefficient \(-2\) becomes the exponent of \( y \) (i.e., \( y^{-2} \)), resulting in \( \log_3(y^{-2}) \). The third part, \( -\log_3(z) \), translates to \( \log_3(z^{-1}) \) by considering -1 as the exponent.

This transformation is the first step in simplifying expressions because it allows you to handle all logarithmic terms with uniformity, easing further manipulation.
Logarithm Combination
Combining logarithms is based on the use of the properties of logarithms, which allow you to condense expressions. The rule \( \log_b(M) - \log_b(N) = \log_b\left(\frac{M}{N}\right) \) is particularly useful for combining terms.

In the original exercise, after applying the power rule, we have three separate terms: \( \log_3(x^{1/2}) \), \( \log_3(y^{-2}) \), and \( \log_3(z^{-1}) \). We can combine these by using the properties of logarithms. Start with the first two terms, combining them using the property above:

\[ \log_3(x^{1/2}) + \log_3(y^{-2}) = \log_3\left(x^{1/2} \cdot y^{-2}\right) \]

Then include the third term, \( \log_3(z^{-1}) \):

\[ \log_3(x^{1/2} \cdot y^{-2}) + \log_3(z^{-1}) = \log_3\left(x^{1/2} \cdot y^{-2} \cdot z^{-1}\right) \]

Now, all terms are combined into a single logarithm expression, which is more concise and easier to handle.
Single Logarithm Expression
Once logarithms are combined into a single expression, as illustrated in this exercise, it enables you to tidy up and interpret the logarithm more cleanly.

The outcome of combining the terms is \( \log_3(x^{1/2} \cdot y^{-2} \cdot z^{-1}) \). This expression combines all previous individual logarithms into one, achieved by organizing the terms inside the argument into a product. We apply exponent rules here to clarify:

- A root \( x^{1/2} \) can be expressed as \( \sqrt{x} \).
- A negative exponent \( y^{-2} \) translates to \( \frac{1}{y^2} \).
- Likewise, \( z^{-1} \) becomes \( \frac{1}{z} \).

Thus, putting it all together, we organize into a fraction within a single logarithm:

\[ \log_3\left(\frac{\sqrt{x}}{y^2z}\right) \]

This simplification is often the final goal in algebraic expressions involving logarithms, as it optimizes comprehension and further calculations required for solving equations. You can now see the relationships between \( x \), \( y \), and \( z \) more clearly, making this expression more insightful and useful for analysis or decision-making in subsequent steps.

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Most popular questions from this chapter

In Exercises \(1-33,\) solve the equation analytically. $$ 7^{3+7 x}=3^{4-2 x} $$

For each of the scenarios given in Exercises \(1-6\), \- Find the amount \(A\) in the account as a function of the term of the investment \(t\) in years. \- Determine how much is in the account after 5 years, 10 years, 30 years and 35 years. Round your answers to the nearest cent. \- Determine how long will it take for the initial investment to double. Round your answer to the nearest year. \- Find and interpret the average rate of change of the amount in the account from the end of the fourth year to the end of the fifth year, and from the end of the thirty-fourth year to the end of the thirty-fifth year. Round your answer to two decimal places. $$\$ 500$$ is invested in an account which offers \(0.75 \%\), compounded continuously.

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In Exercises \(1-33,\) solve the equation analytically. $$ 7 e^{2 x}=28 e^{-6 x} $$

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