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Use the property: \(b^{a}=c\) if and only if \(\log _{b}(c)=a\) from Theorem 6.2 to rewrite the given equation in the other form. That is, rewrite the exponential equations as logarithmic equations and rewrite the logarithmic equations as exponential equations. \(2^{3}=8\)

Short Answer

Expert verified
The equation \(2^3 = 8\) is \(\log_2(8) = 3\) in logarithmic form.

Step by step solution

01

Identify the Base, Exponent, and Result

In the given exponential equation, identify the base, which is 2, the exponent, which is 3, and the result, which is 8.
02

Apply the Logarithmic Property

Using the property from Theorem 6.2, convert the exponential equation to a logarithmic form. This property states that if you have an equation in the form of \( b^a = c \), it can be rewritten as \( \log_b(c) = a \). For the equation \( 2^3 = 8 \), rewrite it as \( \log_2(8) = 3 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Equations
Exponential equations are mathematical expressions where a constant base is raised to a variable exponent. The general form is given by \( b^x = y \), where \( b \) is the base, \( x \) is the exponent, and \( y \) is the result. These types of equations are quite common in real-world scenarios such as calculating compound interest or population growth.

To solve an exponential equation, you typically need to rewrite it in a form that allows you to determine the value of the unknown exponent. This frequently involves utilizing logarithms to transform the equation into a more manageable form. The exponential equation \( 2^3 = 8 \) is a simple example where the base is 2, the exponent is 3, and the result is 8. By understanding exponential equations, you can address more complex problems involving variables and constants.
Logarithmic Equations
Logarithmic equations involve finding the exponent to which a base number is raised to produce a given number. The general form of a logarithmic equation is \( \log_b(c) = a \), which asks: "to what power must \( b \) be raised, to give \( c \)?"

Logarithmic equations are closely tied to exponential equations. They are essentially the inverse operation of exponentiation. When dealing with logarithmic equations, it is crucial to understand that they help in solving equations where the unknown is the exponent. For instance, if you have the logarithmic equation \( \log_2(8) = 3 \), it means that 2 raised to the power 3 results in 8. This connection makes logarithmic equations vital in various fields like earthquake measurement (Richter scale) and sound intensity (decibels).

Converting from an exponential form to a logarithmic form, and vice versa, is a powerful technique to solve for variables in both simple and complex mathematical contexts.
Theorem 6.2
Theorem 6.2 provides a pivotal bridge between exponential and logarithmic equations. It asserts that an equation in the form \( b^a = c \) can be equivalently expressed as \( \log_b(c) = a \). This theorem lays the foundation for converting between these two forms.

Utilizing Theorem 6.2 allows you to seamlessly shift between exponential and logarithmic formats, which is particularly useful for solving problems that involve growth and decay. It simplifies the task of isolating variables, especially when exponents are involved, and offers an intuitive method to interpret exponential relationships by viewing them through the lens of logarithms.

In practice, applying Theorem 6.2 efficiently transforms complex exponential relationships into straightforward logarithmic equations. This theorem is fundamental in fields such as finance, physics, and engineering where such transformations are not just useful but essential.

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Most popular questions from this chapter

For each of the scenarios given in Exercises \(1-6\), \- Find the amount \(A\) in the account as a function of the term of the investment \(t\) in years. \- Determine how much is in the account after 5 years, 10 years, 30 years and 35 years. Round your answers to the nearest cent. \- Determine how long will it take for the initial investment to double. Round your answer to the nearest year. \- Find and interpret the average rate of change of the amount in the account from the end of the fourth year to the end of the fifth year, and from the end of the thirty-fourth year to the end of the thirty-fifth year. Round your answer to two decimal places. $$\$ 500$$ is invested in an account which offers \(0.75 \%\), compounded monthly.

Compute the inverse of \(f(x)=\frac{e^{x}-e^{-x}}{2}\). State the domain and range of both \(f\) and \(f^{-1}\).

Solve the equation analytically. $$ \ln \left(x^{2}\right)=(\ln (x))^{2} $$

Use the appropriate change of base formula to approximate the logarithm. $$ \log _{4}\left(\frac{1}{10}\right) $$

We list some radioactive isotopes and their associated half-lives. Assume that each decays according to the formula \(A(t)=A_{0} e^{k t}\) where \(A_{0}\) is the initial amount of the material and \(k\) is the decay constant. For each isotope: \- Find the decay constant \(k\). Round your answer to four decimal places. \- Find a function which gives the amount of isotope \(A\) which remains after time \(t\). (Keep the units of \(A\) and \(t\) the same as the given data.) \- Determine how long it takes for \(90 \%\) of the material to decay. Round your answer to two decimal places. (HINT: If \(90 \%\) of the material decays, how much is left?) Chromium 51, used to track red blood cells, initial amount 75 milligrams, half-life 27.7 days.

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