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In Exercises 41-45, create a polynomial \(p\) which has the desired characteristics. You may leave the polynomial in factored form. \(\bullet\) The zeros of \(p\) are \(c=\pm 2\) and \(c=\pm 1\) \(\bullet\) The leading term of \(p(x)\) is \(117 x^{4}\).

Short Answer

Expert verified
The polynomial is \(p(x) = 117(x^4 - 5x^2 + 4)\).

Step by step solution

01

Identifying the Roots of the Polynomial

We know that the zeros of the polynomial \(p(x)\) are \(c = \pm 2\) and \(c = \pm 1\). This tells us that the factors of the polynomial can be written as \((x - 2)\), \((x + 2)\), \((x - 1)\), and \((x + 1)\). Hence, the base polynomial is \(p(x) = (x - 2)(x + 2)(x - 1)(x + 1)\), which is equivalent to \((x^2 - 4)(x^2 - 1)\) after applying the difference of squares formula.
02

Expanding to Determine the Polynomial Structure

Next, we expand \((x^2 - 4)(x^2 - 1)\) to find the polynomial's structure: \(p(x) = (x^2 - 4)(x^2 - 1) = x^4 - x^2 - 4x^2 + 4 = x^4 - 5x^2 + 4\). This step confirms that the polynomial is of degree 4. The leading coefficient at this stage is 1.
03

Adjusting the Leading Coefficient

The problem specifies that the leading term of \(p(x)\) should be \(117x^4\). Currently, the leading term is \(x^4\) which means the coefficient is 1. To change it to \(117x^4\), we can multiply the entire polynomial by 117. So, the polynomial becomes \(p(x) = 117(x^4 - 5x^2 + 4)\).
04

Verifying the Polynomial

We must ensure that multiplying the entire expression by 117 maintains the specified conditions. The polynomial \(p(x) = 117(x^4 - 5x^2 + 4)\) has a leading term of \(117x^4\) and includes factors for all specified roots \((x - 2)(x + 2)(x - 1)(x + 1)\). Therefore, it satisfies all given conditions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Zeros of Polynomials
The zeros of a polynomial, sometimes called roots, are the values for which the polynomial equals zero. For instance, if you have a polynomial equation like
  • \( p(x) = (x - 2)(x + 2)(x - 1)(x + 1) \)
it means that setting each factor equal to zero, gives you the zeros of the polynomial. These zeros are
  • \( x = 2 \) and \( x = -2 \)
  • \( x = 1 \) and \( x = -1 \)
These are also called the roots or solutions of the polynomial equation because they are the x-values where the graph intersects the x-axis. Knowing the zeros helps us understand the behavior of the polynomial, especially in relation to its graph and symmetry properties. For example, if these zeros are real and distinct, like in our case, the graph will cross the x-axis at four distinct points.
Leading Coefficient
The leading coefficient in a polynomial is the coefficient of the term with the highest degree. It plays a critical role in determining the end behavior of the polynomial graph. For the polynomial
  • \( p(x) = 117(x^4 - 5x^2 + 4) \)
we see that the term with the highest degree is
  • \( 117x^4 \)
Therefore, the leading coefficient is 117. This leading coefficient tells us how the polynomial stretches or compresses in the vertical direction. For example, a larger leading coefficient indicates that the graph will be steeper as it moves away from the x-axis toward the ends. In our polynomial's case, multiplying by 117 has increased this steepness dramatically. This property affects the width and orientation of the polynomial's graph. Usually, when the leading coefficient is positive, the graph's ends will point upwards.
Factored Form
The factored form of a polynomial is expressed as a product of its factors. It is a helpful way to understand and identify the zeros of the polynomial, especially when they are easily readable from the equation. For example, if we start with
  • \( p(x) = (x - 2)(x + 2)(x - 1)(x + 1) \)
this showcases its factored form directly. This form shows each term being subtracted from x, indicating that these corresponding values are zeros of the polynomial. Using factored form like this is efficient and visually straightforward since it clearly lays out where the polynomial will equal zero—highlighted by those individual factor terms. Furthermore, factored forms allow for easier computations and understanding of multiplication concepts like the distributive property when further operations or simplifications are needed.
Difference of Squares
The difference of squares is a special algebraic identity and a helpful tool in simplifying polynomials or finding factors. It is based on the principle that any two squares subtracted from one another can be expressed as a product:
  • \( a^2 - b^2 = (a - b)(a + b) \)
In our polynomial exercise, we use the difference of squares twice:
  • \( x^2 - 4 = (x - 2)(x + 2) \)
  • \( x^2 - 1 = (x - 1)(x + 1) \)
Recognizing this pattern allows for quicker factorization, turning what initially seems like a complex polynomial into manageable parts. Knowing and applying this identity is a powerful strategy, simplifying the task of reducing expressions and solving polynomial equations. It highlights a symmetry in polynomial expressions, making problems involving squares less intimidating and more algorithmically solvable.

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Most popular questions from this chapter

Find the real zeros of \(f(x)=x^{3}-\frac{1}{12} x^{2}-\frac{7}{72} x+\frac{1}{72}\) by first finding a polynomial \(q(x)\) with integer coefficients such that \(q(x)=N \cdot f(x)\) for some integer \(N\). (Recall that the Rational Zeros Theorem required the polynomial in question to have integer coefficients.) Show that \(f\) and \(q\) have the same real zeros.

For the given polynomial: \- Use Cauchy's Bound to find an interval containing all of the real zeros. \- Use the Rational Zeros Theorem to make a list of possible rational zeros. \- Use Descartes' Rule of Signs to list the possible number of positive and negative real zeros, counting multiplicities. \(f(x)=x^{3}+4 x^{2}-11 x+6\)

For the given polynomial: \- Use Cauchy's Bound to find an interval containing all of the real zeros. \- Use the Rational Zeros Theorem to make a list of possible rational zeros. \- Use Descartes' Rule of Signs to list the possible number of positive and negative real zeros, counting multiplicities. \(f(x)=x^{4}-9 x^{2}-4 x+12\)

In Exercises 31-40, you are given a polynomial and one of its zeros. Use the techniques in this section to find the rest of the real zeros and factor the polynomial. \(x^{3}-6 x^{2}+11 x-6, \quad c=1\)

Create a polynomial \(p\) which has the desired characteristics. You may leave the polynomial in factored form. \(\bullet\) The solutions to \(p(x)=0\) are \(x=\pm 3\) and \(x=6\) \(\bullet\) The leading term of \(p(x)\) is \(7 x^{4}\) \(\bullet\) The point (-3,0) is a local minimum on the graph of \(y=p(x)\).

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