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Solve the inequality. Write your answer using interval notation. . \(x^{2} \leq|4 x-3|\)

Short Answer

Expert verified
\([-2 - \sqrt{7}, -2 + \sqrt{7}] \cup [1, 3]\)

Step by step solution

01

Understand the Problem

The inequality given is \(x^{2} \leq |4x-3|\). This means we need to find the range of values for \(x\) such that the square of \(x\) is less than or equal to the absolute value of \(4x-3\).
02

Express the Absolute Value

The absolute value expression \(|4x-3|\) means \(4x-3\) if \(4x-3 \geq 0\) or \(-(4x-3)\) if \(4x-3 < 0\). We have to consider both cases. This results in two inequalities: \(x^2 \leq 4x - 3\) and \(x^2 \leq -(4x - 3)\).
03

Solve the First Case

For the inequality \(x^2 \leq 4x - 3\), rearrange it to \(x^2 - 4x + 3 \leq 0\). Factor the quadratic expression, resulting in \((x-1)(x-3) \leq 0\). Test the intervals created by the roots \(x=1\) and \(x=3\) to determine where the product is non-positive. The solution is \([1, 3]\).
04

Solve the Second Case

In the second case \(x^2 \leq -(4x - 3)\) becomes \(x^2 + 4x - 3 \leq 0\). Solve this quadratic inequality by factoring or using the quadratic formula. The roots are \(x = -2 \pm \sqrt{7}\). Test the intervals to find where the expression is non-positive, giving \([-2 - \sqrt{7}, -2 + \sqrt{7}]\).
05

Combine the Solutions

Combine the solutions of the two cases for the inequality. The solution is the union of the intervals from both cases. Thus, the solution in interval notation is \([-2 - \sqrt{7}, -2 + \sqrt{7}] \cup [1, 3]\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Inequalities
Quadratic inequalities involve expressions where a quadratic polynomial is less than, less than or equal to, greater than, or greater than or equal to another expression. In the given inequality, \( x^2 \leq |4x - 3| \), the challenge is to interpret and solve the inequality to find the values of \( x \) that satisfy it.
Generally, solving quadratic inequalities involves taking these steps:
  • Move all terms to one side to set the expression to zero.
  • Factor the quadratic polynomial if possible.
  • Find the zeros of the polynomial, which are the solutions when the polynomial equals zero.
  • Use these zeros to determine test intervals on the number line.
  • Check these intervals to find those that satisfy the inequality.
The test intervals created help identify where the quadratic expression changes sign, which is crucial for determining when the inequality holds true. Make sure to include equality if the inequality sign allows for it, which affects how intervals are noted.
Absolute Value
Understanding absolute value is key when dealing with inequalities involving expressions such as \(|4x-3|\). Absolute value refers to the distance a number is from zero on the number line, regardless of direction. For any expression \( |A| \), it can be expressed as:
  • \( A \) if \( A \geq 0 \)
  • \(-A \) if \( A < 0 \)
This leads to two separate inequalities since we consider both the positive and negative scenarios.
For \(|4x-3|\), this implies:
- The case where \( 4x-3 \geq 0 \): leads to the inequality \( x^2 \leq 4x - 3 \).
- The case where \( 4x-3 < 0 \): leads to \( x^2 \leq -(4x - 3) \).
Solving these separately provides the intervals that satisfy each case, which are then considered collectively.
Interval Notation
Interval notation is a way of writing solutions to inequalities in a compact and easy-to-understand form. When used correctly, it shows the range of values that satisfy an inequality. In interval notation:
  • Brackets \([\ ]\) denote that the endpoint is included (equal to).
  • Parentheses \((\ )\) denote that the endpoint is not included.
In our solution, the intervals \([1, 3]\) and \([-2 - \sqrt{7}, -2 + \sqrt{7}]\) mean that all values between 1 and 3, as well as between \(-2 - \sqrt{7}\) and \(-2 + \sqrt{7}\), are included.
These notations help easily express complex solutions without having to use inequalities with specific larger or smaller comparisons.
Solving Inequalities
The process of solving inequalities involves finding the set of values that make an inequality statement true. This can sometimes be complex, especially when quadratic expressions or absolute values are involved.
First, express the inequality in a standard form. For quadratic expressions, factor them or use the quadratic formula to find roots. These roots will help define the intervals on a number line, serving as boundaries for where the inequality might change from true to false or vice versa.
  • Determine the critical points or roots of the expression.
  • Test intervals between these points to see where the inequality holds.
  • Combine findings from various inequality cases (if needed) to find the total solution set.
In the original problem, this involved two separate inequalities formed from the absolute value brackets, each resulting in distinct solution intervals. These intervals were then combined to address where the original inequality is valid overall.

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Most popular questions from this chapter

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