Chapter 11: Problem 19
The matrix \(A(\theta)=\left[\begin{array}{rr}\cos (\theta) & -\sin (\theta) \\\ \sin (\theta) & \cos (\theta)\end{array}\right]\) is called a rotation matrix. We've seen this matrix most recently in the proof of used in the proof of Theorem 11.9 . Using the even / odd identities for cosine and sine, show \(A(\theta)^{-1}=A(-\theta)\). Interpret this geometrically.
Short Answer
Step by step solution
Identify the rotation matrix components using trigonometric identities
Verify matrix multiplication rules
Perform the matrix multiplication
Interpret geometric meaning
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Trigonometric Identities
- Cosine Identity: The function is even, meaning \( \cos(-\theta) = \cos(\theta) \). This tells us the cosine function is symmetric about the y-axis.
- Sine Identity: The function is odd, which means \( \sin(-\theta) = -\sin(\theta) \). The sine function is symmetric around the origin, flipping its sign with negative angles.
Matrix Multiplication
- Multiply the elements of the first row with the columns of the second matrix.
- Do the same for the second row to form a new matrix.
Inverse Matrices
- To find the inverse, we look for a matrix that, when multiplied by the original matrix, results in the identity matrix.
- For rotation matrices, the inverse can be derived using trigonometric identities, making the process straightforward since the determinant is 1.
Geometric Interpretation
- \(A(\theta)\): Rotates a vector clockwise by \(\theta\) radians.
- \(A(-\theta)\): Rotates the vector counter-clockwise by \(\theta\) radians.