Chapter 10: Problem 54
In Exercises \(43-58\), solve the equation, giving the exact solutions which lie in \([0,2 \pi)\). $$ \cos (4 x)=\cos (2 x) $$
Short Answer
Expert verified
The solutions are \( x = 0, \frac{\pi}{3}, \frac{2\pi}{3}, \pi, \frac{4\pi}{3}, \frac{5\pi}{3} \).
Step by step solution
01
Set up the equation using the cosine identity
We start by setting \( \cos(4x) = \cos(2x) \). Using the identity that if \( \cos(A) = \cos(B) \), then \( A = 2k\pi \pm B \) for any integer \( k \). Therefore, \( 4x = 2k\pi + 2x \) or \( 4x = 2k\pi - 2x \).
02
Solve the first case
Let's first solve \( 4x = 2k\pi + 2x \):\[4x - 2x = 2k\pi \2x = 2k\pi \x = k\pi \]We need \( x \) to be within \([0, 2\pi)\), so \( k \) can be 0 or 1, leading to the solutions \( x = 0 \) and \( x = \pi \).
03
Solve the second case
Now solve \( 4x = 2k\pi - 2x \): \[4x + 2x = 2k\pi \6x = 2k\pi \x = \frac{k\pi}{3}\]For \( x \) within \([0, 2\pi)\), \( k \) can be 0, 1, 2, 3, 4, 5. This gives us \( x = 0, \frac{\pi}{3}, \frac{2\pi}{3}, \pi, \frac{4\pi}{3}, \text{and} \frac{5\pi}{3} \).
04
Compile all unique solutions within the interval
The unique solutions from solving both cases in the interval \([0, 2\pi)\) are \( x = 0, \frac{\pi}{3}, \frac{2\pi}{3}, \pi, \frac{4\pi}{3}, \text{and} \frac{5\pi}{3} \). Each of these solutions satisfies the original equation \( \cos(4x) = \cos(2x) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cosine Identity
In trigonometry, the cosine identity is a key tool used to solve equations involving cosine functions. In essence, the identity states that if two cosine values are equal, i.e., \( \cos(A) = \cos(B) \), then their corresponding angles are related by:
Applying this principle allows you to systematically find all angles for which \( \cos(4x) = \cos(2x) \). By substituting different integer values for \( k \), you can derive the specific angles or values of \( x \) that satisfy the equation within a specified interval.
- \( A = 2k\pi \pm B \)
Applying this principle allows you to systematically find all angles for which \( \cos(4x) = \cos(2x) \). By substituting different integer values for \( k \), you can derive the specific angles or values of \( x \) that satisfy the equation within a specified interval.
Trigonometric Solutions
Finding solutions to trigonometric equations involves understanding their periodic nature and how they behave within a defined interval. The exercise requires finding all angles \( x \) such that \( \cos(4x) = \cos(2x) \) within the interval \([0, 2\pi)\). To start, you break down the equation using the cosine identity, leading to two potential equations:
- \( 4x = 2k\pi + 2x \)
- \( 4x = 2k\pi - 2x \)
- From \( 4x = 2k\pi + 2x \), we get \( x = k\pi \).
- From \( 4x = 2k\pi - 2x \), we get \( x = \frac{k\pi}{3} \).
Radian Measure
Radian measure is a way of expressing the size of angles based on the radius of a circle. Unlike degrees, radians relate directly to the dimensions of a circle, making them very useful in calculus and trigonometry. A full circle corresponds to \( 2\pi \) radians. Therefore, an angle of \( 2\pi \) radians means completing a full circle.
- \( \pi \) radians is half of a circle, equivalent to 180 degrees.
- A radian itself is the angle created when the arc length is equal to the radius of the circle.